Three displacement vectors of a croquet ball are shown in Figure P3.22, where | A → | = 20.0 units, | B → | = 40.0 units, and | C → | = 30.0 units. Find (a) the resultant in unit-vector notation and (b) the magnitude and direction of the resultant displacement. Figure P3.22
Three displacement vectors of a croquet ball are shown in Figure P3.22, where | A → | = 20.0 units, | B → | = 40.0 units, and | C → | = 30.0 units. Find (a) the resultant in unit-vector notation and (b) the magnitude and direction of the resultant displacement. Figure P3.22
Solution Summary: The resultant vector in unit vector notation is 49.5stackreli+27.07
Three displacement vectors of a croquet ball are shown in Figure P3.22, where
|
A
→
|
=
20.0
units,
|
B
→
|
=
40.0
units, and
|
C
→
|
=
30.0
units. Find (a) the resultant in unit-vector notation and (b) the magnitude and direction of the resultant displacement.
Use the component method to add the vectors A
and B shown in Figure P3.9. Both vectors have mag-
nitudes of 3.00 m and vector A makes an angle of
0 = 30.0° with the x axis. Express the resultant Á + B in
unit-vector notation.
Three displacement vectors of a croquet ball are shown in the figure, where |A| = 12.0 units, |B| = 35.0 units, and |C| = 20.0 units.
A
45.0°
45.0°
c
(a) Find the resultant in unit-vector notation.
R = 67
X units
magnitude
x
(b) Find the magnitude and direction of the resultant displacement.
42.06
X
Your response is within 10% of the correct value. This may be due to roundoff error, or you could have a mistake in your calculation. Carry out all intermediate results to at least four-digit
accuracy to minimize roundoff error. unit(s)
225
° counterclockwise from the +x axis
direction
2.1. Consider the displacement vector Ā=(3î +3j)m, B= (i – 4ĵ)m, and č=(-2î +5j)m. Use the
component method to determine:
a) The magnitude and direction of vector D = Ã+B+C.
b) The magnitude and direction of vector E = -Ã-B+C
1
Chapter 3 Solutions
Physics For Scientists And Engineers With Modern Physics, 9th Edition, The Ohio State University
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.