Chapter 3, Problem 3.81QP

Interpretation Introduction

Interpretation: The comparison between percent C by mass in methane ( ${\text{CH}}_{\text{4}}$) and tetrafluoromethane ( ${\text{CF}}_{\text{4}}$) is to be done.

Concept introduction: The molar mass of a compound is equal to the sum of molar masses of the elements in the compound.

To determine: The comparison between percent C by mass in methane ( ${\text{CH}}_{\text{4}}$) and tetrafluoromethane ( ${\text{CF}}_{\text{4}}$).