The number of moles of KNO 3 which produces 56.5 kg of oxygen is to be determined. Concept introduction: In a balanced chemical equation, the total mass of reactants and products are equal in a balanced chemical equation, thus, it obeyed the law of conservation of mass. Also, the amounts of substances in a balanced chemical reaction are stoichiometrically equivalent to each other. Stoichiometry gives the quantitative relationship between the reactants and products of the chemical reaction. It helps in the calculation of the percentage yield of the product of any chemical reaction. Following are the steps to calculate the moles of a chemical substance when the mass of other substance present in the chemical reaction is given. Step 1: Convert the mass form kilogram to the gram. Divide the given mass of the substance by its molar mass to calculate the moles of that compound. The expression to calculate the amount of a chemical substance in moles is as follows: Amount ( mol ) = Mass ( g ) Molar mass ( g/mol ) (1) Step 2: Determine the molar ratio between the substance whose mass is given and the substance whose amount is to be calculated from the balanced chemical equation. Multiply the calculated moles in step 1 by the molar ratio to obtain the amount of the substance.

Question

Want to see the full answer?

Answer 1

Question

Chapter 3, Problem 3.71P

(a)

Interpretation Introduction

Interpretation:

The number of moles of KNO3 which produces 56.5 kg of oxygen is to be determined.

Concept introduction:

In a balanced chemical equation, the total mass of reactants and products are equal in a balanced chemical equation, thus, it obeyed the law of conservation of mass. Also, the amounts of substances in a balanced chemical reaction are stoichiometrically equivalent to each other.

Stoichiometry gives the quantitative relationship between the reactants and products of the chemical reaction. It helps in the calculation of the percentage yield of the product of any chemical reaction.

Following are the steps to calculate the moles of a chemical substance when the mass of other substance present in the chemical reaction is given.

Step 1: Convert the mass form kilogram to the gram. Divide the given mass of the substance by its molar mass to calculate the moles of that compound. The expression to calculate the amount of a chemical substance in moles is as follows:

Amount(mol)=Mass (g)Molar mass(g/mol) (1)

Step 2: Determine the molar ratio between the substance whose mass is given and the substance whose amount is to be calculated from the balanced chemical equation. Multiply the calculated moles in step 1 by the molar ratio to obtain the amount of the substance.

(b)

Interpretation Introduction

Interpretation:

The mass of KNO3 which produces 56.5 kg of oxygen is to be determined.

Concept introduction:

In a balanced chemical equation, the total mass of reactants and products are equal in a balanced chemical equation, thus, it obeyed the law of conservation of mass. Also, the amounts of substances in a balanced chemical reaction are stoichiometrically equivalent to each other.

Stoichiometry gives the quantitative relationship between the reactants and products of the chemical reaction. It helps in the calculation of the percentage yield of the product of any chemical reaction.

The expression to calculate the mass from the moles of a substance is as follows:

Mass(g)=(Amount(mol))(Molar mass(g/mol)) (2)

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Students have asked these similar questions

Write the equilibrium constant expression for the following reaction: HNO2(aq) + H2O(l) ⇌ H3O+(aq) + NO2-(aq)

Write the reaction quotient for: Pb2+(aq) + 2 Cl- (aq) ⇌ PbCl2(s)

Write the equilibrium constant expression for the following system at equilibrium: I2 (g) ⇌ 2 I (g)

Answer 2

Question

Chapter 3, Problem 3.71P

(a)

Interpretation Introduction

Interpretation:

The number of moles of KNO3 which produces 56.5 kg of oxygen is to be determined.

Concept introduction:

In a balanced chemical equation, the total mass of reactants and products are equal in a balanced chemical equation, thus, it obeyed the law of conservation of mass. Also, the amounts of substances in a balanced chemical reaction are stoichiometrically equivalent to each other.

Stoichiometry gives the quantitative relationship between the reactants and products of the chemical reaction. It helps in the calculation of the percentage yield of the product of any chemical reaction.

Following are the steps to calculate the moles of a chemical substance when the mass of other substance present in the chemical reaction is given.

Step 1: Convert the mass form kilogram to the gram. Divide the given mass of the substance by its molar mass to calculate the moles of that compound. The expression to calculate the amount of a chemical substance in moles is as follows:

Amount(mol)=Mass (g)Molar mass(g/mol) (1)

Step 2: Determine the molar ratio between the substance whose mass is given and the substance whose amount is to be calculated from the balanced chemical equation. Multiply the calculated moles in step 1 by the molar ratio to obtain the amount of the substance.

(b)

Interpretation Introduction

Interpretation:

The mass of KNO3 which produces 56.5 kg of oxygen is to be determined.

Concept introduction:

In a balanced chemical equation, the total mass of reactants and products are equal in a balanced chemical equation, thus, it obeyed the law of conservation of mass. Also, the amounts of substances in a balanced chemical reaction are stoichiometrically equivalent to each other.

Stoichiometry gives the quantitative relationship between the reactants and products of the chemical reaction. It helps in the calculation of the percentage yield of the product of any chemical reaction.

The expression to calculate the mass from the moles of a substance is as follows:

Mass(g)=(Amount(mol))(Molar mass(g/mol)) (2)

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 3

Question

Chapter 3, Problem 3.71P

(a)

Interpretation Introduction

Interpretation:

The number of moles of KNO3 which produces 56.5 kg of oxygen is to be determined.

Concept introduction:

In a balanced chemical equation, the total mass of reactants and products are equal in a balanced chemical equation, thus, it obeyed the law of conservation of mass. Also, the amounts of substances in a balanced chemical reaction are stoichiometrically equivalent to each other.

Stoichiometry gives the quantitative relationship between the reactants and products of the chemical reaction. It helps in the calculation of the percentage yield of the product of any chemical reaction.

Following are the steps to calculate the moles of a chemical substance when the mass of other substance present in the chemical reaction is given.

Step 1: Convert the mass form kilogram to the gram. Divide the given mass of the substance by its molar mass to calculate the moles of that compound. The expression to calculate the amount of a chemical substance in moles is as follows:

Amount(mol)=Mass (g)Molar mass(g/mol) (1)

Step 2: Determine the molar ratio between the substance whose mass is given and the substance whose amount is to be calculated from the balanced chemical equation. Multiply the calculated moles in step 1 by the molar ratio to obtain the amount of the substance.

(b)

Interpretation Introduction

Interpretation:

The mass of KNO3 which produces 56.5 kg of oxygen is to be determined.

Concept introduction:

In a balanced chemical equation, the total mass of reactants and products are equal in a balanced chemical equation, thus, it obeyed the law of conservation of mass. Also, the amounts of substances in a balanced chemical reaction are stoichiometrically equivalent to each other.

Stoichiometry gives the quantitative relationship between the reactants and products of the chemical reaction. It helps in the calculation of the percentage yield of the product of any chemical reaction.

The expression to calculate the mass from the moles of a substance is as follows:

Mass(g)=(Amount(mol))(Molar mass(g/mol)) (2)

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 4

Question

Chapter 3, Problem 3.71P

(a)

Interpretation Introduction

Interpretation:

The number of moles of KNO3 which produces 56.5 kg of oxygen is to be determined.

Concept introduction:

In a balanced chemical equation, the total mass of reactants and products are equal in a balanced chemical equation, thus, it obeyed the law of conservation of mass. Also, the amounts of substances in a balanced chemical reaction are stoichiometrically equivalent to each other.

Stoichiometry gives the quantitative relationship between the reactants and products of the chemical reaction. It helps in the calculation of the percentage yield of the product of any chemical reaction.

Following are the steps to calculate the moles of a chemical substance when the mass of other substance present in the chemical reaction is given.

Step 1: Convert the mass form kilogram to the gram. Divide the given mass of the substance by its molar mass to calculate the moles of that compound. The expression to calculate the amount of a chemical substance in moles is as follows:

Amount(mol)=Mass (g)Molar mass(g/mol) (1)

Step 2: Determine the molar ratio between the substance whose mass is given and the substance whose amount is to be calculated from the balanced chemical equation. Multiply the calculated moles in step 1 by the molar ratio to obtain the amount of the substance.

(b)

Interpretation Introduction

Interpretation:

The mass of KNO3 which produces 56.5 kg of oxygen is to be determined.

Concept introduction:

In a balanced chemical equation, the total mass of reactants and products are equal in a balanced chemical equation, thus, it obeyed the law of conservation of mass. Also, the amounts of substances in a balanced chemical reaction are stoichiometrically equivalent to each other.

Stoichiometry gives the quantitative relationship between the reactants and products of the chemical reaction. It helps in the calculation of the percentage yield of the product of any chemical reaction.

The expression to calculate the mass from the moles of a substance is as follows:

Mass(g)=(Amount(mol))(Molar mass(g/mol)) (2)

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 5

Chapter 3, Problem 3.71P

(a)

Interpretation Introduction

Interpretation:

The number of moles of KNO3 which produces 56.5 kg of oxygen is to be determined.

Concept introduction:

In a balanced chemical equation, the total mass of reactants and products are equal in a balanced chemical equation, thus, it obeyed the law of conservation of mass. Also, the amounts of substances in a balanced chemical reaction are stoichiometrically equivalent to each other.

Stoichiometry gives the quantitative relationship between the reactants and products of the chemical reaction. It helps in the calculation of the percentage yield of the product of any chemical reaction.

Following are the steps to calculate the moles of a chemical substance when the mass of other substance present in the chemical reaction is given.

Step 1: Convert the mass form kilogram to the gram. Divide the given mass of the substance by its molar mass to calculate the moles of that compound. The expression to calculate the amount of a chemical substance in moles is as follows:

Amount(mol)=Mass (g)Molar mass(g/mol) (1)

Step 2: Determine the molar ratio between the substance whose mass is given and the substance whose amount is to be calculated from the balanced chemical equation. Multiply the calculated moles in step 1 by the molar ratio to obtain the amount of the substance.

(b)

Interpretation Introduction

Interpretation:

The mass of KNO3 which produces 56.5 kg of oxygen is to be determined.

Concept introduction:

In a balanced chemical equation, the total mass of reactants and products are equal in a balanced chemical equation, thus, it obeyed the law of conservation of mass. Also, the amounts of substances in a balanced chemical reaction are stoichiometrically equivalent to each other.

Stoichiometry gives the quantitative relationship between the reactants and products of the chemical reaction. It helps in the calculation of the percentage yield of the product of any chemical reaction.

The expression to calculate the mass from the moles of a substance is as follows:

Mass(g)=(Amount(mol))(Molar mass(g/mol)) (2)

Answer 6

Chapter 3, Problem 3.71P

(a)

Interpretation Introduction

Interpretation:

The number of moles of KNO3 which produces 56.5 kg of oxygen is to be determined.

Concept introduction:

In a balanced chemical equation, the total mass of reactants and products are equal in a balanced chemical equation, thus, it obeyed the law of conservation of mass. Also, the amounts of substances in a balanced chemical reaction are stoichiometrically equivalent to each other.

Stoichiometry gives the quantitative relationship between the reactants and products of the chemical reaction. It helps in the calculation of the percentage yield of the product of any chemical reaction.

Following are the steps to calculate the moles of a chemical substance when the mass of other substance present in the chemical reaction is given.

Step 1: Convert the mass form kilogram to the gram. Divide the given mass of the substance by its molar mass to calculate the moles of that compound. The expression to calculate the amount of a chemical substance in moles is as follows:

Amount(mol)=Mass (g)Molar mass(g/mol) (1)

Step 2: Determine the molar ratio between the substance whose mass is given and the substance whose amount is to be calculated from the balanced chemical equation. Multiply the calculated moles in step 1 by the molar ratio to obtain the amount of the substance.

Answer 7

Chapter 3, Problem 3.71P

(a)

Interpretation Introduction

Interpretation:

The number of moles of KNO3 which produces 56.5 kg of oxygen is to be determined.

Concept introduction:

In a balanced chemical equation, the total mass of reactants and products are equal in a balanced chemical equation, thus, it obeyed the law of conservation of mass. Also, the amounts of substances in a balanced chemical reaction are stoichiometrically equivalent to each other.

Stoichiometry gives the quantitative relationship between the reactants and products of the chemical reaction. It helps in the calculation of the percentage yield of the product of any chemical reaction.

Following are the steps to calculate the moles of a chemical substance when the mass of other substance present in the chemical reaction is given.

Step 1: Convert the mass form kilogram to the gram. Divide the given mass of the substance by its molar mass to calculate the moles of that compound. The expression to calculate the amount of a chemical substance in moles is as follows:

Amount(mol)=Mass (g)Molar mass(g/mol) (1)

Step 2: Determine the molar ratio between the substance whose mass is given and the substance whose amount is to be calculated from the balanced chemical equation. Multiply the calculated moles in step 1 by the molar ratio to obtain the amount of the substance.

Answer 8

(b)

Interpretation Introduction

Interpretation:

The mass of KNO3 which produces 56.5 kg of oxygen is to be determined.

Concept introduction:

In a balanced chemical equation, the total mass of reactants and products are equal in a balanced chemical equation, thus, it obeyed the law of conservation of mass. Also, the amounts of substances in a balanced chemical reaction are stoichiometrically equivalent to each other.

Stoichiometry gives the quantitative relationship between the reactants and products of the chemical reaction. It helps in the calculation of the percentage yield of the product of any chemical reaction.

The expression to calculate the mass from the moles of a substance is as follows:

Mass(g)=(Amount(mol))(Molar mass(g/mol)) (2)

Answer 9

(b)

Interpretation Introduction

Interpretation:

The mass of KNO3 which produces 56.5 kg of oxygen is to be determined.

Concept introduction:

In a balanced chemical equation, the total mass of reactants and products are equal in a balanced chemical equation, thus, it obeyed the law of conservation of mass. Also, the amounts of substances in a balanced chemical reaction are stoichiometrically equivalent to each other.

Stoichiometry gives the quantitative relationship between the reactants and products of the chemical reaction. It helps in the calculation of the percentage yield of the product of any chemical reaction.

The expression to calculate the mass from the moles of a substance is as follows:

Mass(g)=(Amount(mol))(Molar mass(g/mol)) (2)

Answer 10

Expert Solution & Answer

Answer 11

Expert Solution & Answer

Answer 12

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 13

Ch. 3.1 - Graphite is the crystalline form of carbon used in...Ch. 3.1 - Prob. 3.1BFP Ch. 3.1 - At rest, a person inhales 9.72×1021 nitrogen...Ch. 3.1 - Prob. 3.2BFP Ch. 3.1 - Prob. 3.3AFP Ch. 3.1 - Prob. 3.3BFP Ch. 3.1 - Fluoride ion is added to drinking water to prevent...Ch. 3.1 - Calcium chloride is applied to highways in winter...Ch. 3.1 - Tetraphosphorus decoxide reacts with water to form...Ch. 3.1 - Prob. 3.5BFP

Concept explainers

Videos

Want to see the full answer?

Chapter 3 Solutions