Chapter 3, Problem 3.112P

(a)

Interpretation Introduction

Interpretation:

The mass of oxygen gas required for the complete combustion of toluene is to be calculated.

Concept introduction:

No. of moles is calculated by the formula:

  $\text{Number of moles}=\frac{\text{given mass of sample}\left(\text{g}\right)}{\text{molecular mass (g/mol)}}$        (1)

The formula to calculate the mass is,

  $\text{Mass of a given sample}\left(\text{g}\right)=\left(\text{molecular mass}\left(\text{g/mol}\right)\right)\left(\text{number of moles}\right)$

(b)

Interpretation Introduction

Interpretation:

The total moles of gaseous products formed are to be calculated.

Concept introduction:

No. of moles is calculated by the formula:

  $\text{Number of moles}=\frac{\text{given mass of sample}\left(\text{g}\right)}{\text{molecular mass (g/mol)}}$        (1)

The formula to calculate the mass is,

  $\text{Mass of a given sample}\left(\text{g}\right)=\left(\text{molecular mass}\left(\text{g/mol}\right)\right)\left(\text{number of moles}\right)$

(c)

Interpretation Introduction

Interpretation:

The number of molecules of water vapor formed upon complete combustion of toluene is to be determined.

Concept introduction:

No. of moles is calculated by the formula:

  $\text{Number of moles}=\frac{\text{given mass of sample}\left(\text{g}\right)}{\text{molecular mass (g/mol)}}$        (1)

The formula to calculate the mass is,

  $\text{Mass of a given sample}\left(\text{g}\right)=\left(\text{molecular mass}\left(\text{g/mol}\right)\right)\left(\text{number of moles}\right)$