Chapter 3, Problem 3.62AP

After a ball rolls off the edge of a horizontal table at time t = 0, its velocity as a function of time is given by

$\stackrel{\to }{v}=1.2\hat{i}-9.8t\hat{j}$

where  $\stackrel{\to }{\text{v}}$ is in meters per second and t is in seconds. The balls displacement away from the edge of the table, during the time interval of 0.380 s for which the ball is in flight, is given by

$\Delta \stackrel{\to }{r}={\displaystyle {\int }_0^{{0.380}_3}\stackrel{\to }{\text{v}}}dt$

To perform the integral, you can use the calculus theorem

${\displaystyle \int [A+Bf(x)]dx={\displaystyle \int A}dx+B{\displaystyle \int f\left(x\right)}dx}$

You can think of the units and unit vectors as constants, represented by A and B. Perform the integration to calculate the displacement of the ball from the edge of the table at 0.380 s.