Number of moles present in 1 .33×10 26 molecules of Br 2 has to be stated.

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Answer 1

Question

Chapter 3, Problem 3.56QE

(a)

Interpretation Introduction

Interpretation:

Number of moles present in $1.33×1026 molecules of Br2$ has to be stated.

(a)

Expert Solution

Explanation of Solution

$1mol=6.022×1023molecules$ .

$6.022×1023molecules$ is known as Avogadro’s number.

From Avogadro’s number, it is clear that $1mol Br2= 6.022×1023molecules Br2$ .

Therefore, number of moles of $Br2$ is:

$Amount Br2= 1.33×1026 molecules of Br2×(1mol Br26.022×1023molecules Br2) = 2.20×102 mol Br2$

(b)

Interpretation Introduction

Interpretation:

Number of moles present in $7.71×1026 molecules of C5H12$ has to be stated.

(b)

Expert Solution

Explanation of Solution

$1mol=6.022×1023atoms$ .

$6.022×1023molecules$ is known as Avogadro’s number.

From Avogadro’s number, it is clear that $1mol C5H12= 6.022×1023molecules C5H12$ .

Therefore, number of moles of $C5H12$ is:

$Amount C5H12 = 7.71×1026 molecules of C5H12 ×(1mol C5H126.022×1023atoms of C5H12) = 1.3×102 mol C5H12$

(c)

Interpretation Introduction

Interpretation:

Number of moles present in $2.34×1023 molecules of B2H6$ has to be stated.

(c)

Expert Solution

Explanation of Solution

$1mol=6.022×1023molecules$ .

$6.022×1023molecules$ is known as Avogadro’s number.

From Avogadro’s number, it is clear that $1mol B2H6= 6.022×1023molecules B2H6$ .

Therefore, number of moles of $B2H6$ is:

$Amount B2H6= 2.34×1023 molecules of B2H6×(1mol B2H66.022×1023molecules B2H6) = 0.388 mol B2H6$

(d)

Interpretation Introduction

Interpretation:

Number of moles present in $7.76 ×1023 molecules of Ne$ has to be stated.

(d)

Expert Solution

Explanation of Solution

$1mol=6.022×1023molecules$ .

$6.022×1023molecules$ is known as Avogadro’s number.

From Avogadro’s number, it is clear that $1mol Ne = 6.022×1023molecules Ne$ .

Therefore, number of moles of $Ne$ is:

$Amount Ne= 7.76×1023 molecules of Ne×(1mol Ne6.022×1023molecules Ne) = 1.28 mol Ne$

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Answer 2

Question

Chapter 3, Problem 3.56QE

(a)

Interpretation Introduction

Interpretation:

Number of moles present in $1.33×1026 molecules of Br2$ has to be stated.

(a)

Expert Solution

Explanation of Solution

$1mol=6.022×1023molecules$ .

$6.022×1023molecules$ is known as Avogadro’s number.

From Avogadro’s number, it is clear that $1mol Br2= 6.022×1023molecules Br2$ .

Therefore, number of moles of $Br2$ is:

$Amount Br2= 1.33×1026 molecules of Br2×(1mol Br26.022×1023molecules Br2) = 2.20×102 mol Br2$

(b)

Interpretation Introduction

Interpretation:

Number of moles present in $7.71×1026 molecules of C5H12$ has to be stated.

(b)

Expert Solution

Explanation of Solution

$1mol=6.022×1023atoms$ .

$6.022×1023molecules$ is known as Avogadro’s number.

From Avogadro’s number, it is clear that $1mol C5H12= 6.022×1023molecules C5H12$ .

Therefore, number of moles of $C5H12$ is:

$Amount C5H12 = 7.71×1026 molecules of C5H12 ×(1mol C5H126.022×1023atoms of C5H12) = 1.3×102 mol C5H12$

(c)

Interpretation Introduction

Interpretation:

Number of moles present in $2.34×1023 molecules of B2H6$ has to be stated.

(c)

Expert Solution

Explanation of Solution

$1mol=6.022×1023molecules$ .

$6.022×1023molecules$ is known as Avogadro’s number.

From Avogadro’s number, it is clear that $1mol B2H6= 6.022×1023molecules B2H6$ .

Therefore, number of moles of $B2H6$ is:

$Amount B2H6= 2.34×1023 molecules of B2H6×(1mol B2H66.022×1023molecules B2H6) = 0.388 mol B2H6$

(d)

Interpretation Introduction

Interpretation:

Number of moles present in $7.76 ×1023 molecules of Ne$ has to be stated.

(d)

Expert Solution

Explanation of Solution

$1mol=6.022×1023molecules$ .

$6.022×1023molecules$ is known as Avogadro’s number.

From Avogadro’s number, it is clear that $1mol Ne = 6.022×1023molecules Ne$ .

Therefore, number of moles of $Ne$ is:

$Amount Ne= 7.76×1023 molecules of Ne×(1mol Ne6.022×1023molecules Ne) = 1.28 mol Ne$

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Answer 3

Question

Chapter 3, Problem 3.56QE

(a)

Interpretation Introduction

Interpretation:

Number of moles present in $1.33×1026 molecules of Br2$ has to be stated.

(a)

Expert Solution

Explanation of Solution

$1mol=6.022×1023molecules$ .

$6.022×1023molecules$ is known as Avogadro’s number.

From Avogadro’s number, it is clear that $1mol Br2= 6.022×1023molecules Br2$ .

Therefore, number of moles of $Br2$ is:

$Amount Br2= 1.33×1026 molecules of Br2×(1mol Br26.022×1023molecules Br2) = 2.20×102 mol Br2$

(b)

Interpretation Introduction

Interpretation:

Number of moles present in $7.71×1026 molecules of C5H12$ has to be stated.

(b)

Expert Solution

Explanation of Solution

$1mol=6.022×1023atoms$ .

$6.022×1023molecules$ is known as Avogadro’s number.

From Avogadro’s number, it is clear that $1mol C5H12= 6.022×1023molecules C5H12$ .

Therefore, number of moles of $C5H12$ is:

$Amount C5H12 = 7.71×1026 molecules of C5H12 ×(1mol C5H126.022×1023atoms of C5H12) = 1.3×102 mol C5H12$

(c)

Interpretation Introduction

Interpretation:

Number of moles present in $2.34×1023 molecules of B2H6$ has to be stated.

(c)

Expert Solution

Explanation of Solution

$1mol=6.022×1023molecules$ .

$6.022×1023molecules$ is known as Avogadro’s number.

From Avogadro’s number, it is clear that $1mol B2H6= 6.022×1023molecules B2H6$ .

Therefore, number of moles of $B2H6$ is:

$Amount B2H6= 2.34×1023 molecules of B2H6×(1mol B2H66.022×1023molecules B2H6) = 0.388 mol B2H6$

(d)

Interpretation Introduction

Interpretation:

Number of moles present in $7.76 ×1023 molecules of Ne$ has to be stated.

(d)

Expert Solution

Explanation of Solution

$1mol=6.022×1023molecules$ .

$6.022×1023molecules$ is known as Avogadro’s number.

From Avogadro’s number, it is clear that $1mol Ne = 6.022×1023molecules Ne$ .

Therefore, number of moles of $Ne$ is:

$Amount Ne= 7.76×1023 molecules of Ne×(1mol Ne6.022×1023molecules Ne) = 1.28 mol Ne$

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Answer 4

Question

Chapter 3, Problem 3.56QE

(a)

Interpretation Introduction

Interpretation:

Number of moles present in $1.33×1026 molecules of Br2$ has to be stated.

(a)

Expert Solution

Explanation of Solution

$1mol=6.022×1023molecules$ .

$6.022×1023molecules$ is known as Avogadro’s number.

From Avogadro’s number, it is clear that $1mol Br2= 6.022×1023molecules Br2$ .

Therefore, number of moles of $Br2$ is:

$Amount Br2= 1.33×1026 molecules of Br2×(1mol Br26.022×1023molecules Br2) = 2.20×102 mol Br2$

(b)

Interpretation Introduction

Interpretation:

Number of moles present in $7.71×1026 molecules of C5H12$ has to be stated.

(b)

Expert Solution

Explanation of Solution

$1mol=6.022×1023atoms$ .

$6.022×1023molecules$ is known as Avogadro’s number.

From Avogadro’s number, it is clear that $1mol C5H12= 6.022×1023molecules C5H12$ .

Therefore, number of moles of $C5H12$ is:

$Amount C5H12 = 7.71×1026 molecules of C5H12 ×(1mol C5H126.022×1023atoms of C5H12) = 1.3×102 mol C5H12$

(c)

Interpretation Introduction

Interpretation:

Number of moles present in $2.34×1023 molecules of B2H6$ has to be stated.

(c)

Expert Solution

Explanation of Solution

$1mol=6.022×1023molecules$ .

$6.022×1023molecules$ is known as Avogadro’s number.

From Avogadro’s number, it is clear that $1mol B2H6= 6.022×1023molecules B2H6$ .

Therefore, number of moles of $B2H6$ is:

$Amount B2H6= 2.34×1023 molecules of B2H6×(1mol B2H66.022×1023molecules B2H6) = 0.388 mol B2H6$

(d)

Interpretation Introduction

Interpretation:

Number of moles present in $7.76 ×1023 molecules of Ne$ has to be stated.

(d)

Expert Solution

Explanation of Solution

$1mol=6.022×1023molecules$ .

$6.022×1023molecules$ is known as Avogadro’s number.

From Avogadro’s number, it is clear that $1mol Ne = 6.022×1023molecules Ne$ .

Therefore, number of moles of $Ne$ is:

$Amount Ne= 7.76×1023 molecules of Ne×(1mol Ne6.022×1023molecules Ne) = 1.28 mol Ne$

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Answer 5

Chapter 3, Problem 3.56QE

(a)

Interpretation Introduction

Interpretation:

Number of moles present in $1.33×1026 molecules of Br2$ has to be stated.

(a)

Expert Solution

Explanation of Solution

$1mol=6.022×1023molecules$ .

$6.022×1023molecules$ is known as Avogadro’s number.

From Avogadro’s number, it is clear that $1mol Br2= 6.022×1023molecules Br2$ .

Therefore, number of moles of $Br2$ is:

$Amount Br2= 1.33×1026 molecules of Br2×(1mol Br26.022×1023molecules Br2) = 2.20×102 mol Br2$

(b)

Interpretation Introduction

Interpretation:

Number of moles present in $7.71×1026 molecules of C5H12$ has to be stated.

(b)

Expert Solution

Explanation of Solution

$1mol=6.022×1023atoms$ .

$6.022×1023molecules$ is known as Avogadro’s number.

From Avogadro’s number, it is clear that $1mol C5H12= 6.022×1023molecules C5H12$ .

Therefore, number of moles of $C5H12$ is:

$Amount C5H12 = 7.71×1026 molecules of C5H12 ×(1mol C5H126.022×1023atoms of C5H12) = 1.3×102 mol C5H12$

(c)

Interpretation Introduction

Interpretation:

Number of moles present in $2.34×1023 molecules of B2H6$ has to be stated.

(c)

Expert Solution

Explanation of Solution

$1mol=6.022×1023molecules$ .

$6.022×1023molecules$ is known as Avogadro’s number.

From Avogadro’s number, it is clear that $1mol B2H6= 6.022×1023molecules B2H6$ .

Therefore, number of moles of $B2H6$ is:

$Amount B2H6= 2.34×1023 molecules of B2H6×(1mol B2H66.022×1023molecules B2H6) = 0.388 mol B2H6$

(d)

Interpretation Introduction

Interpretation:

Number of moles present in $7.76 ×1023 molecules of Ne$ has to be stated.

(d)

Expert Solution

Explanation of Solution

$1mol=6.022×1023molecules$ .

$6.022×1023molecules$ is known as Avogadro’s number.

From Avogadro’s number, it is clear that $1mol Ne = 6.022×1023molecules Ne$ .

Therefore, number of moles of $Ne$ is:

$Amount Ne= 7.76×1023 molecules of Ne×(1mol Ne6.022×1023molecules Ne) = 1.28 mol Ne$

Answer 6

Chapter 3, Problem 3.56QE

(a)

Interpretation Introduction

Interpretation:

Number of moles present in $1.33×1026 molecules of Br2$ has to be stated.

(a)

Expert Solution

Explanation of Solution

$1mol=6.022×1023molecules$ .

$6.022×1023molecules$ is known as Avogadro’s number.

From Avogadro’s number, it is clear that $1mol Br2= 6.022×1023molecules Br2$ .

Therefore, number of moles of $Br2$ is:

$Amount Br2= 1.33×1026 molecules of Br2×(1mol Br26.022×1023molecules Br2) = 2.20×102 mol Br2$

Answer 7

Chapter 3, Problem 3.56QE

(a)

Interpretation Introduction

Interpretation:

Number of moles present in $1.33×1026 molecules of Br2$ has to be stated.

Answer 8

(a)

Expert Solution

Explanation of Solution

$1mol=6.022×1023molecules$ .

$6.022×1023molecules$ is known as Avogadro’s number.

From Avogadro’s number, it is clear that $1mol Br2= 6.022×1023molecules Br2$ .

Therefore, number of moles of $Br2$ is:

$Amount Br2= 1.33×1026 molecules of Br2×(1mol Br26.022×1023molecules Br2) = 2.20×102 mol Br2$

Answer 9

(a)

Expert Solution

Answer 10

(a)

Expert Solution

Answer 11

Expert Solution

Answer 12

(b)

Interpretation Introduction

Interpretation:

Number of moles present in $7.71×1026 molecules of C5H12$ has to be stated.

(b)

Expert Solution

Explanation of Solution

$1mol=6.022×1023atoms$ .

$6.022×1023molecules$ is known as Avogadro’s number.

From Avogadro’s number, it is clear that $1mol C5H12= 6.022×1023molecules C5H12$ .

Therefore, number of moles of $C5H12$ is:

$Amount C5H12 = 7.71×1026 molecules of C5H12 ×(1mol C5H126.022×1023atoms of C5H12) = 1.3×102 mol C5H12$

Answer 13

(b)

Interpretation Introduction

Interpretation:

Number of moles present in $7.71×1026 molecules of C5H12$ has to be stated.

Answer 14

(b)

Expert Solution

Explanation of Solution

$1mol=6.022×1023atoms$ .

$6.022×1023molecules$ is known as Avogadro’s number.

From Avogadro’s number, it is clear that $1mol C5H12= 6.022×1023molecules C5H12$ .

Therefore, number of moles of $C5H12$ is:

$Amount C5H12 = 7.71×1026 molecules of C5H12 ×(1mol C5H126.022×1023atoms of C5H12) = 1.3×102 mol C5H12$

Answer 15

(b)

Expert Solution

Answer 16

(b)

Expert Solution

Answer 17

Expert Solution

Answer 18

(c)

Interpretation Introduction

Interpretation:

Number of moles present in $2.34×1023 molecules of B2H6$ has to be stated.

(c)

Expert Solution

Explanation of Solution

$1mol=6.022×1023molecules$ .

$6.022×1023molecules$ is known as Avogadro’s number.

From Avogadro’s number, it is clear that $1mol B2H6= 6.022×1023molecules B2H6$ .

Therefore, number of moles of $B2H6$ is:

$Amount B2H6= 2.34×1023 molecules of B2H6×(1mol B2H66.022×1023molecules B2H6) = 0.388 mol B2H6$

Answer 19

(c)

Interpretation Introduction

Interpretation:

Number of moles present in $2.34×1023 molecules of B2H6$ has to be stated.

Answer 20

(c)

Expert Solution

Explanation of Solution

$1mol=6.022×1023molecules$ .

$6.022×1023molecules$ is known as Avogadro’s number.

From Avogadro’s number, it is clear that $1mol B2H6= 6.022×1023molecules B2H6$ .

Therefore, number of moles of $B2H6$ is:

$Amount B2H6= 2.34×1023 molecules of B2H6×(1mol B2H66.022×1023molecules B2H6) = 0.388 mol B2H6$

Answer 21

(c)

Expert Solution

Answer 22

(c)

Expert Solution

Answer 23

Expert Solution

Answer 24

(d)

Interpretation Introduction

Interpretation:

Number of moles present in $7.76 ×1023 molecules of Ne$ has to be stated.

(d)

Expert Solution

Explanation of Solution

$1mol=6.022×1023molecules$ .

$6.022×1023molecules$ is known as Avogadro’s number.

From Avogadro’s number, it is clear that $1mol Ne = 6.022×1023molecules Ne$ .

Therefore, number of moles of $Ne$ is:

$Amount Ne= 7.76×1023 molecules of Ne×(1mol Ne6.022×1023molecules Ne) = 1.28 mol Ne$

Answer 25

(d)

Interpretation Introduction

Interpretation:

Number of moles present in $7.76 ×1023 molecules of Ne$ has to be stated.

Answer 26

(d)

Expert Solution

Explanation of Solution

$1mol=6.022×1023molecules$ .

$6.022×1023molecules$ is known as Avogadro’s number.

From Avogadro’s number, it is clear that $1mol Ne = 6.022×1023molecules Ne$ .

Therefore, number of moles of $Ne$ is:

$Amount Ne= 7.76×1023 molecules of Ne×(1mol Ne6.022×1023molecules Ne) = 1.28 mol Ne$

Answer 27

(d)

Expert Solution

Answer 28

(d)

Expert Solution

Answer 29

Expert Solution

Answer 30

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Number of moles present in 1 .33×10 26 molecules of Br 2 has to be stated.

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Interpretation:

Number of moles present in $1.33×1026 molecules of Br2$ has to be stated.

Explanation of Solution

Interpretation:

Number of moles present in $7.71×1026 molecules of C5H12$ has to be stated.

Explanation of Solution

Interpretation:

Number of moles present in $2.34×1023 molecules of B2H6$ has to be stated.

Explanation of Solution

Interpretation:

Number of moles present in $7.76 ×1023 molecules of Ne$ has to be stated.

Explanation of Solution

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Chapter 3 Solutions

Number of moles present in 1 .33×10 26 molecules of Br 2 has to be stated.

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Videos

Explanation of Solution

Explanation of Solution

Explanation of Solution

Interpretation: Number of moles present in 7.76 ×1023 molecules of Ne<m:math><m:mrow><m:mtext>7</m:mtext><m:msup><m:mrow><m:mtext>.76 ×10</m:mtext></m:mrow><m:mrow><m:mtext>23</m:mtext></m:mrow></m:msup><m:mtext> molecules of Ne</m:mtext></m:mrow></m:math> has to be stated.

Explanation of Solution

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Chapter 3 Solutions

Interpretation:

Number of moles present in $7.76 ×1023 molecules of Ne$ has to be stated.