Chapter 3, Problem 3.110QE

Interpretation Introduction

Interpretation:

The empirical formula of the compound has to be determined for a compound that contains only carbon, hydrogen, oxygen and nitrogen.  The combustion of a $\text{2}\text{.18g}$ of the compound in excess ${\text{O}}_{\text{2}}$ yields $\text{3}\text{.94g}$${\text{CO}}_{\text{2}}$ and $\text{1}\text{.89g}$${\text{H}}_{\text{2}}\text{O}$, a separate experiment shows that a $\text{1}\text{.23g}$ of the same compound contain $\text{0}\text{.235g}$$\text{N}$.