Chapter 3, Problem 3.3P

Interpretation Introduction

(a)

Interpretation:

The mass (kg) of 50 liters of gasoline should be calculated.

Concept introduction:

The density is the ratio of mass and volume given as:

$\rho =\frac{m}{V}$

Here, m is mass and V is volume

The specific gravity of a body with respect to water is calculated by taking ratio of density of that body to the density of water. It is also related to molar mass as follows:

$S=\frac{{\rho }_A}{{\rho }_B}=\frac{M_A}{M_B}$

Interpretation Introduction

(b)

Interpretation:

The volumetric flowrate in liters/s should be calculated.

Concept introduction:

The density is the ratio of mass and volume given as:

$\rho =\frac{m}{V}$

Here, m is mass and V is volume

Interpretation Introduction

(c)

Interpretation:

The average mass flow rate delivered by a gasoline pump should be estimated.

Concept introduction:

The density is the ratio of mass and volume given as:

$\rho =\frac{m}{V}$

Here, m is mass and V is volume

Interpretation Introduction

(d)

Interpretation:

Gasoline and Kerosene are blended to obtain a mixture with a specific gravity of 0.78. The volumetric ratio of the two compounds in the mixture should be estimated.

Concept introduction:

Volumetric ratio of gasoline and kerosene can be calculated as follows:

$\text{Volumetric}\text{ratio}=\frac{V_{\text{gasoline}}}{V_{\text{kerosene}}}$

Volumes can be calculated from densities which are related to each other in terms of specific gravity as follows:

The specific gravity of a body with respect to water is calculated by taking ratio of density of that body to the density of water. It is also related to molar mass as follows:

$S=\frac{{\rho }_A}{{\rho }_B}$