FUND OF ENG THERMODYN(LLF)+WP NEXT GEN
9th Edition
ISBN: 9781119840602
Author: MORAN
Publisher: WILEY
expand_more
expand_more
format_list_bulleted
Concept explainers
Videos
Question
Chapter 3, Problem 3.37CU
To determine
Specify whether the approximation
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solution
Students have asked these similar questions
One mole of a gas is expanded isothermally at 300 Kelvins from 5.00 MegaPascal to 0.10 MegaPascal. If this gas obeys the equation of state given below and from this B is equal to 2.0 x10^4 L/(mol-K^2), answer the question that follow.
Calculate the change in molar Gibbs free energy (in KJ/mole) for this process. Express answer in THREE SIGNIFICANT FIGURES.
Calculate AH, AU, w, and q for the reversible heating of 1 mol of liquid water from 273 K to 373 K at 1 atm.
ΔΗΞ 1806.88
You are correct
AU = -1065.729
You are incorrect
W = -741.151
You are incorrect
q= 1806.88
You are correct
X
cal
cal
X cal
cal
2.00 moles of nitrogen gas at 25.0 °C, confined within a cylinder by a piston maintaining a constant pressure of 1.00 atm, is heated with 3.90 kJ of energy. Assume all the energy is used to do work of expansion of the gas at 1.00 atm. What will be the final temperature (in °C) of the gas? Recall ∆H = ∆E + P∆V and watch your units!
Chapter 3 Solutions
FUND OF ENG THERMODYN(LLF)+WP NEXT GEN
Ch. 3 - Prob. 3.1ECh. 3 - Prob. 3.2ECh. 3 - Prob. 3.3ECh. 3 - Prob. 3.4ECh. 3 - Prob. 3.6ECh. 3 - Prob. 3.7ECh. 3 - Prob. 3.8ECh. 3 - Prob. 3.9ECh. 3 - Prob. 3.10ECh. 3 - Prob. 3.11E
Ch. 3 - Prob. 3.12ECh. 3 - Prob. 3.13ECh. 3 - Prob. 3.1CUCh. 3 - Prob. 3.2CUCh. 3 - Prob. 3.3CUCh. 3 - Prob. 3.4CUCh. 3 - Prob. 3.5CUCh. 3 - Prob. 3.6CUCh. 3 - Prob. 3.7CUCh. 3 - Prob. 3.8CUCh. 3 - Prob. 3.9CUCh. 3 - Prob. 3.10CUCh. 3 - Prob. 3.11CUCh. 3 - Prob. 3.12CUCh. 3 - Prob. 3.13CUCh. 3 - Prob. 3.14CUCh. 3 - Prob. 3.15CUCh. 3 - Prob. 3.16CUCh. 3 - Prob. 3.17CUCh. 3 - Prob. 3.18CUCh. 3 - Prob. 3.19CUCh. 3 - Prob. 3.20CUCh. 3 - Prob. 3.21CUCh. 3 - Prob. 3.22CUCh. 3 - Prob. 3.23CUCh. 3 - Prob. 3.24CUCh. 3 - Prob. 3.25CUCh. 3 - Prob. 3.26CUCh. 3 - Prob. 3.27CUCh. 3 - Prob. 3.28CUCh. 3 - Prob. 3.29CUCh. 3 - Prob. 3.30CUCh. 3 - Prob. 3.31CUCh. 3 - Prob. 3.32CUCh. 3 - Prob. 3.33CUCh. 3 - Prob. 3.34CUCh. 3 - Prob. 3.35CUCh. 3 - Prob. 3.36CUCh. 3 - Prob. 3.37CUCh. 3 - Prob. 3.38CUCh. 3 - Prob. 3.39CUCh. 3 - Prob. 3.40CUCh. 3 - Prob. 3.41CUCh. 3 - Prob. 3.42CUCh. 3 - Prob. 3.43CUCh. 3 - Prob. 3.44CUCh. 3 - Prob. 3.45CUCh. 3 - Prob. 3.46CUCh. 3 - Prob. 3.47CUCh. 3 - Prob. 3.48CUCh. 3 - Prob. 3.49CUCh. 3 - Prob. 3.50CUCh. 3 - Prob. 3.51CUCh. 3 - Prob. 3.52CUCh. 3 - Prob. 3.1PCh. 3 - Prob. 3.2PCh. 3 - Prob. 3.3PCh. 3 - Prob. 3.4PCh. 3 - Prob. 3.5PCh. 3 - Prob. 3.6PCh. 3 - Prob. 3.7PCh. 3 - Prob. 3.8PCh. 3 - Prob. 3.9PCh. 3 - Prob. 3.10PCh. 3 - Prob. 3.11PCh. 3 - Prob. 3.12PCh. 3 - Prob. 3.13PCh. 3 - Prob. 3.14PCh. 3 - Prob. 3.15PCh. 3 - Prob. 3.16PCh. 3 - Prob. 3.17PCh. 3 - Prob. 3.18PCh. 3 - Prob. 3.19PCh. 3 - Prob. 3.20PCh. 3 - Prob. 3.21PCh. 3 - Prob. 3.22PCh. 3 - Prob. 3.23PCh. 3 - Prob. 3.24PCh. 3 - Prob. 3.25PCh. 3 - Prob. 3.26PCh. 3 - Prob. 3.27PCh. 3 - Prob. 3.28PCh. 3 - Prob. 3.29PCh. 3 - Prob. 3.30PCh. 3 - Prob. 3.31PCh. 3 - Prob. 3.32PCh. 3 - Prob. 3.33PCh. 3 - Prob. 3.34PCh. 3 - Prob. 3.35PCh. 3 - Prob. 3.36PCh. 3 - Prob. 3.37PCh. 3 - Prob. 3.38PCh. 3 - Prob. 3.39PCh. 3 - Prob. 3.40PCh. 3 - Prob. 3.41PCh. 3 - Prob. 3.42PCh. 3 - Prob. 3.43PCh. 3 - Prob. 3.44PCh. 3 - Prob. 3.45PCh. 3 - Prob. 3.46PCh. 3 - Prob. 3.47PCh. 3 - Prob. 3.48PCh. 3 - Prob. 3.49PCh. 3 - Prob. 3.50PCh. 3 - Prob. 3.51PCh. 3 - Prob. 3.52PCh. 3 - Prob. 3.53PCh. 3 - Prob. 3.54PCh. 3 - Prob. 3.55PCh. 3 - Prob. 3.56PCh. 3 - Prob. 3.57PCh. 3 - Prob. 3.58PCh. 3 - Prob. 3.59PCh. 3 - Prob. 3.60PCh. 3 - Prob. 3.61PCh. 3 - Prob. 3.62PCh. 3 - Prob. 3.63PCh. 3 - Prob. 3.64PCh. 3 - Prob. 3.65PCh. 3 - Prob. 3.66PCh. 3 - Prob. 3.67PCh. 3 - Prob. 3.68PCh. 3 - Prob. 3.69PCh. 3 - Prob. 3.70PCh. 3 - Prob. 3.71PCh. 3 - Prob. 3.72PCh. 3 - Prob. 3.73PCh. 3 - Prob. 3.74PCh. 3 - Prob. 3.75PCh. 3 - Prob. 3.76PCh. 3 - Prob. 3.77PCh. 3 - Prob. 3.78PCh. 3 - Prob. 3.79PCh. 3 - Prob. 3.80PCh. 3 - Prob. 3.81PCh. 3 - Prob. 3.82PCh. 3 - Prob. 3.83PCh. 3 - Prob. 3.84PCh. 3 - Prob. 3.85PCh. 3 - Prob. 3.86PCh. 3 - Prob. 3.87PCh. 3 - Prob. 3.88PCh. 3 - Prob. 3.89PCh. 3 - Prob. 3.90PCh. 3 - Prob. 3.91PCh. 3 - Prob. 3.92PCh. 3 - Prob. 3.93PCh. 3 - Prob. 3.94PCh. 3 - Prob. 3.95PCh. 3 - Prob. 3.96PCh. 3 - Prob. 3.97PCh. 3 - Prob. 3.98PCh. 3 - Prob. 3.99P
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, mechanical-engineering and related others by exploring similar questions and additional content below.Similar questions
- 1. The equation of state of the actual gas is as follows. v (P+ 10 /v^ 2 )= RT, provided that the units of v and P are m^ 3 /kmol and kPa. 300K, 0.3 kmol of gas in the cylinder expanded from 2m^3 to 5m^3 in an isothermal process. Answer the following questions. (1) What is the unit of the number 10 in the above equation? (2) Find the work done during this process. (3) If the equation for the internal energy of this gas is the same as the internal energy of the ideal gas, find the amount of heat transfer during this process.arrow_forwardA certain ideal gas has the following properties: Molecular Mass, M = 24.943416 kg/kmole and Cvo = 1.000 kJ/ºK/kg. Determine Cpo in kJ / °K / kg.arrow_forwardQuestion 1: Derive the thermodynamic equation of state (dH/dP)_T = V-T(dV/dT)_P Derive an expression for (dH/dP)_T for an ideal gas and for a van der Waals gas. For the van der waals gas, estimate its value for 1.0 mol of Ar(g) at 298K and 10 atm. Question 2: Show that the slope of compressibility factor Z as a function of pressure as P ---> 0; at isothermal conditions is related to the van der waals parameters by: Limit (P-->0) dz/dP = (b-a/RT)/RTarrow_forward
- Solve the following problems SYSTEMATICALLY. Show your complete solution and enclose your final answers in a box. At 250°C, a mixture of steam and liquid water exists in equilibrium. If the specific volume of the mixture is 0.05159 m/kg, calculate the following: (a) percent moisture, (b) enthalpy and (c) entropy.arrow_forwardA round bottom flask containing 1.75 moles of ideal gas molecules, for which C_(V,m) = 3/2 R is heated reversibly from [T_1 = 263 K, p_1 = 97 kPa] to [T_2 = 363 K, p_2 = ?] at constant volume. Calculate p2, ΔU, q, and w.arrow_forwardA 6-kg block of copper at 300 °C is submerged in 0.08 m3 of water at 0 °C contained in an insulated tank. Estimate the final equilibrium temperature. Conservation of energy requires that the energy lost by the copper block is gained by the water. Units are in Celsius.arrow_forward
- A rigid vessel as shown in figure below contain three different gases separated by diaphragms. If diaphragms are removed and gases allowed to be mixed together adiabatically, find the final temperature and pressure of the mixture. CO2 m = 24 kg T = 77 °C P = 1.5 bar N2 m = 6 kg T = 52 °C P = 0.5 bar O2 m = 12 kg T = 27 °C P = 2.0 bararrow_forwardA cylinder contains oxygen at a pressure of 2.00 atm. The volume is 4.00 L, and the temperature is 300 K. Assume that the oxygen may be treated as an ideal gas. The oxygen is carried through the following processes: (i) Heated at constant pressure from the initial state (state 1) to state 2, which has T = 450 K. (ii) Cooled at constant volume to 250 K (state 3). (iii) Compressed at constant temperature to a volume of 4.00 L (state 4). (iv) Heated at constant volume to 300 K, which takes the system back to state 1. (a) Show these four processes in a pV-diagram, giving the numerical values of p and V in each of the four states. (b) Calculate Q and W for each of the four processes. (c) Calculate the net work done by the oxygen in the complete cycle. (d) What is the efficiency of this device as a heat engine? How does this compare to the efficiency of a Carnot-cycle engine operating between the same minimum and maximum temperatures of 250 K and 450 K?arrow_forwardAn ideal gas contained in a piston-and-cylinder device undergoes a thermodynamic cycle made up of three quasi-equilibrium processes. Step 1-2: Adiabatic compression from 330 K and 9.35 atm to 12.58 atm Step 2-3: Isobaric cooling Step 3-1: Isothermal expansion c.) Calculate Q, W, ΔU and ΔH, in J/mole, for each step in the process and for the entire cycle. Assume that CP = (5/2) R. d.) Is this cycle a power cycle or a refrigeration cycle? Explain. Calculate the thermal efficiency or COP of the cycle, whichever is appropriate.arrow_forward
- Complete the following table for Refrigerant-134a. Use the data from the steam tables exactly as listed.arrow_forwardNiloarrow_forwardAt low pressures, the compressibility factor of a van der Waals gas is given by the equation: Z = PV/RT = 1+(b- a/RT) P/RT Calculate the fugacity of nitrogen gas at 3000 K and 0.05 bar. The van der Waals constants of nitrogen gas are a = 1.408 L^2-bar-mol^2 and b = 0.03913 L-mol^-1. By investigating the fugacity coefficient, what can be said about nitrogen at this temperature and pressure? *final answer in 4 decimalsarrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
Elements Of ElectromagneticsMechanical EngineeringISBN:9780190698614Author:Sadiku, Matthew N. O.Publisher:Oxford University Press
Mechanics of Materials (10th Edition)Mechanical EngineeringISBN:9780134319650Author:Russell C. HibbelerPublisher:PEARSON
Thermodynamics: An Engineering ApproachMechanical EngineeringISBN:9781259822674Author:Yunus A. Cengel Dr., Michael A. BolesPublisher:McGraw-Hill Education
Control Systems EngineeringMechanical EngineeringISBN:9781118170519Author:Norman S. NisePublisher:WILEY
Mechanics of Materials (MindTap Course List)Mechanical EngineeringISBN:9781337093347Author:Barry J. Goodno, James M. GerePublisher:Cengage Learning
Engineering Mechanics: StaticsMechanical EngineeringISBN:9781118807330Author:James L. Meriam, L. G. Kraige, J. N. BoltonPublisher:WILEY
Elements Of Electromagnetics
Mechanical Engineering
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Oxford University Press
Mechanics of Materials (10th Edition)
Mechanical Engineering
ISBN:9780134319650
Author:Russell C. Hibbeler
Publisher:PEARSON
Thermodynamics: An Engineering Approach
Mechanical Engineering
ISBN:9781259822674
Author:Yunus A. Cengel Dr., Michael A. Boles
Publisher:McGraw-Hill Education
Control Systems Engineering
Mechanical Engineering
ISBN:9781118170519
Author:Norman S. Nise
Publisher:WILEY
Mechanics of Materials (MindTap Course List)
Mechanical Engineering
ISBN:9781337093347
Author:Barry J. Goodno, James M. Gere
Publisher:Cengage Learning
Engineering Mechanics: Statics
Mechanical Engineering
ISBN:9781118807330
Author:James L. Meriam, L. G. Kraige, J. N. Bolton
Publisher:WILEY
First Law of Thermodynamics, Basic Introduction - Internal Energy, Heat and Work - Chemistry; Author: The Organic Chemistry Tutor;https://www.youtube.com/watch?v=NyOYW07-L5g;License: Standard youtube license