Chapter 3, Problem 3.35PAE

3.33 Balance the following equations, and then write the net

ionic equation.

(a) Zn(s) + HC1(aq) ( H₂(g) + ZnCl₂(aq)

(b) Mg(OH)₂ (s)+ HCl (aq) ( MgCl2(aq) + H₂O (l)

(c) HNO₃(aq) + CaCO₃(s) ( Ca(NO₃)₂(aq) + H₂0(l) + CO₂(g)

(d) (NH₄)₂S (aq)+ FeCl₃(aq)( NH₄Cl (aq)+Fe₂S₃(s)

Interpretation Introduction

To Determine:

To determine the balanced chemical equation and net ionic equation.

Explanation of Solution

Given Information:

The unbalanced chemical equation is $\text{Zn(s) + HCl(aq) }\to {\text{ H}}_2{\text{(g) + ZnCl}}_{\text{2}}\text{(aq)}$

The Balanced chemical equation is-

${\text{Zn(s) + 2 HCl(aq) = H}}_2{\text{(g) + ZnCl}}_{\text{2}}\text{(aq)}$

In the Balanced chemical equation Zn, H, & Cl atoms remain unchanged on both the sides. Copper ion is the spectator ion here so the net ionic equation will be as follows −

${\text{Zn(s)**\#x00A0;+ 2 H}}^{\text{+}}{\text{(aq) = H}}_{\text{2}}{\text{(g) + Zn}}^{\text{2+}}\text{(aq)}$

Interpretation Introduction

To Determine:

To determine the balanced chemical equation and net ionic equation.

Explanation of Solution

Given Information:

The unbalanced chemical equation is ${\text{Mg(OH)}}_{\text{2}}\text{(s) + HCl(aq) }\to {\text{ MgCl}}_{\text{2}}{\text{(aq) + 2 H}}_{\text{2}}\text{O}$

The Balanced chemical equation is-

${\text{Mg(OH)}}_{\text{2}}{\text{(s) + 2 HCl(aq) = MgCl}}_{\text{2}}{\text{(aq) + 2 H}}_{\text{2}}\text{O}$

In the Balanced chemical equation Mg, H, O, & Cl atoms remain unchanged on both the sides. There are no spectator ions here so the net ionic equation will be as follows −

${\text{Mg(OH)}}_{\text{2}}{\text{(s)**\#x00A0;+ 2 H}}^{+}{\text{(aq) = Mg}}^{2+}{\text{(aq) + 2 H}}_{\text{2}}\text{O}$

Interpretation Introduction

To Determine:

To determine the balanced chemical equation and net ionic equation.

Explanation of Solution

Given Information:

The unbalanced chemical equation is - ${\text{HNO}}_{\text{3}}{\text{(aq) + CaCO}}_{\text{3}}\text{(s) }\to {\text{ Ca(NO}}_{\text{3}}{\text{)}}_{\text{2}}{\text{(aq) + H}}_{\text{2}}{\text{O + CO}}_{\text{2}}\text{(g)}$

The Balanced chemical equation is-

${\text{2 HNO}}_{\text{3}}{\text{(aq) + CaCO}}_{\text{3}}{\text{(s) = Ca(NO}}_{\text{3}}{\text{)}}_{\text{2}}{\text{(aq) + H}}_{\text{2}}{\text{O + CO}}_{\text{2}}\text{(g)}$

In the Balanced chemical equation Ca, H, C, O, & N atoms remain unchanged on both the sides. There are no spectator ions here so the net ionic equation will be as follows −

${\text{2**\#x00A0;H+(aq) + CaCO}}_{\text{3}}{\text{(s) = Ca}}^{2+}{\text{(aq) + H}}_{\text{2}}{\text{O + CO}}_{\text{2}}\text{(g)}$

Interpretation Introduction

To Determine:

To determine the balanced chemical equation and net ionic equation.

Explanation of Solution

Given Information:

The unbalanced chemical equation is ${{\text{(NH}}_{\text{4}}\text{)}}_{\text{2}}{\text{S(aq) + FeCl}}_{\text{3}}\text{(aq) }\to {\text{ NH}}_{\text{4}}{\text{Cl(aq) + Fe}}_{\text{2}}{\text{S}}_{\text{3}}\text{(s)}$

The Balanced chemical equation is-

${\text{3 (NH}}_{\text{4}}{\text{)}}_{\text{2}}{\text{S(aq) + 2 FeCl}}_{\text{3}}{\text{(aq) = 6 NH}}_{\text{4}}{\text{Cl(aq) + Fe}}_{\text{2}}{\text{S}}_{\text{3}}\text{(s)}$

In the Balanced chemical equation N, H, S, Cl & Fe remain unchanged on both the sides. Copper ion is the spectator ions here so the net ionic equation will be as follows −

${\text{3**\#x00A0;S}}^{2-}(aq)+2F{e}^{3+}(aq)=F{e}_2{S}_3(s)$

Conclusion

${\text{Zn(s) + 2 HCl(aq) = H}}_2{\text{(g) + ZnCl}}_{\text{2}}\text{(aq)}$

Net ionic equation ${\text{Zn(s) + 2 H}}^{\text{+}}{\text{(aq) = H}}_{\text{2}}{\text{(g) + Zn}}^{\text{2+}}\text{(aq)}$

${\text{Mg(OH)}}_{\text{2}}{\text{(s) + 2 HCl(aq) = MgCl}}_{\text{2}}{\text{(aq) + 2 H}}_{\text{2}}\text{O}$

Net Ionic equation ${\text{Mg(OH)}}_{\text{2}}{\text{(s) + 2 H}}^{+}{\text{(aq) = Mg}}^{2+}{\text{(aq) + 2 H}}_{\text{2}}\text{O}$

${\text{2 HNO}}_{\text{3}}{\text{(aq) + CaCO}}_{\text{3}}{\text{(s) = Ca(NO}}_{\text{3}}{\text{)}}_{\text{2}}{\text{(aq) + H}}_{\text{2}}{\text{O + CO}}_{\text{2}}\text{(g)}$

Net Ionic equation ${\text{2 H+(aq) + CaCO}}_{\text{3}}{\text{(s) = Ca}}^{2+}{\text{(aq) + H}}_{\text{2}}{\text{O + CO}}_{\text{2}}\text{(g)}$

${\text{3 (NH}}_{\text{4}}{\text{)}}_{\text{2}}{\text{S(aq) + 2 FeCl}}_{\text{3}}{\text{(aq) = 6 NH}}_{\text{4}}{\text{Cl(aq) + Fe}}_{\text{2}}{\text{S}}_{\text{3}}\text{(s)}$

Net Ionic equation ${\text{3 S}}^{2-}(aq)+2F{e}^{3+}(aq)=F{e}_2{S}_3(s)$