Chapter 3, Problem 3.34PAE

3.32 Balance the following equations and then write the net

ionic equation.

(a)(NH₄)₂CO₃ (aq)+ Cu(NO₃)₂ (aq)( CuCO₃ (s)+ NH₄NO₃(aq)

(b) Pb(OH)₂(s)+ HCl(aq) ( PbCl₂(s) + H₂O (l)

(c) BaCO₃(s) + HCl(aq)( BaCl₂(aq) + H₂O (l) + CO₂(g)

(d) CH₃CO₂H (aq)+ Ni(OH)₂(s)( Ni(CH₃CO₂)₂(aq) + H₂O(l)

Interpretation Introduction

To Determine:

To determine the balanced chemical equation and net ionic equation.

Explanation of Solution

Given Information:

The unbalanced chemical equation is ${{\text{(NH}}_{\text{4}}\text{)}}_{\text{2}}{\text{CO}}_{\text{3}}{\text{ + Cu(NO}}_{\text{3}}{\text{)}}_{\text{2}}\to {\text{CuCO}}_{\text{3}}{\text{ + NH}}_{\text{4}}{\text{NO}}_{\text{3}}$

The Balanced chemical equation is-

${{\text{(NH}}_{\text{4}}\text{)}}_{\text{2}}{\text{CO}}_{\text{3}}{\text{ + Cu(NO}}_{\text{3}}{\text{)}}_{\text{2}}{\text{ = CuCO}}_{\text{3}}{\text{ + 2NH}}_{\text{4}}{\text{NO}}_{\text{3}}$

In the Balanced chemical equation N, H, C, O, & Cu atoms are same on both the side. Copper ion is the spectator ions here so the net ionic equation will be as follows −

$2N{H}_4{}^{+}+2N{O}_3{}^{**\#x2212;}\to {\text{2NH}}_{\text{4}}{\text{NO}}_{\text{3}}$

Interpretation Introduction

To Determine:

To determine the balanced chemical equation and net ionic equation.

Explanation of Solution

Given Information:

The unbalanced chemical equation is ${\text{Pb(OH)}}_{\text{2}}\text{ + HCl }\to {\text{ PbCl}}_{\text{2}}{\text{ +H}}_{\text{2}}\text{O}$

The Balanced chemical equation is-

${\text{Pb(OH)}}_{\text{2}}{\text{ + 2HCl = PbCl}}_{\text{2}}{\text{ +2H}}_{\text{2}}\text{O}$

In the Balanced chemical equation Pb, H, Cl, & O atoms are same on both the side. There is no spectator ions here so the net ionic equation will be as follows −

${\text{2OH}}^{\text{-}}+2H^{+}+P{b}^{2+}+2C{l}^{**\#x2212;}\to PbC{l}_2+2H_{2}O$

Interpretation Introduction

To Determine:

To determine the balanced chemical equation and net ionic equation.

Explanation of Solution

Given Information:

The unbalanced chemical equation is ${\text{BaCO}}_{\text{3}}\text{+ HCl}\to {\text{ BaCl}}_{\text{2}}{\text{ + H}}_{\text{2}}{\text{O + CO}}_{\text{2}}$

The Balanced chemical equation is-

${\text{BaCO}}_{\text{3}}{\text{+ 2HCl= BaCl}}_{\text{2}}{\text{ + H}}_{\text{2}}{\text{O + CO}}_{\text{2}}$

In the Balanced chemical equation Ba, H, C, O, & Cl atoms are same on both the side. There are no spectator ions here so the net ionic equation will be as follows −

$B{a}^{2+}+C{O}_3{}^{2**\#x2212;}+2H^{+}+2C{l}^{-}\to BaC{l}_2+H_{2}O+C{O}_2$

Interpretation Introduction

To Determine:

To determine the balanced chemical equation and net ionic equation.

Explanation of Solution

Given Information:

The unbalanced chemical equation is ${\text{CH}}_{\text{3}}{\text{CO}}_{\text{2}}{\text{H+ Ni(OH)}}_{\text{2}}\to {\text{Ni(CH}}_{\text{3}}{\text{CO}}_{\text{2}}{\text{)}}_{\text{2}}{\text{+ H}}_{\text{2}}\text{O}$

The Balanced chemical equation is-

${\text{2CH}}_{\text{3}}{\text{CO}}_{\text{2}}{\text{H+ Ni(OH)}}_{\text{2}}{\text{=Ni(CH}}_{\text{3}}{\text{CO}}_{\text{2}}{\text{)}}_{\text{2}}{\text{+ 2H}}_{\text{2}}\text{O}$

In the Balanced chemical equation H, C, O, & Ni atoms remain the same on both sides. Copper ion is the spectator ion here so the net ionic equation will be as follows −

${\text{2CH}}_{\text{3}}{\text{COO}}^{**\#x2212;}+2H^{+}+N{i}^{2+}+2O{H}^{-}\to {\text{Ni(CH}}_{\text{3}}{\text{CO}}_{\text{2}}{\text{)}}_{\text{2}}{\text{+ 2H}}_{\text{2}}\text{O}$

Conclusion

The balanced chemical equations are as follows-

${{\text{(NH}}_{\text{4}}\text{)}}_{\text{2}}{\text{CO}}_{\text{3}}{\text{ + Cu(NO}}_{\text{3}}{\text{)}}_{\text{2}}{\text{ = CuCO}}_{\text{3}}{\text{ + 2NH}}_{\text{4}}{\text{NO}}_{\text{3}}$

Net ionic equation $2N{H}_4{}^{+}+2N{O}_3{}^{-}\to {\text{2NH}}_{\text{4}}{\text{NO}}_{\text{3}}$

${\text{Pb(OH)}}_{\text{2}}{\text{ + 2HCl = PbCl}}_{\text{2}}{\text{ +2H}}_{\text{2}}\text{O}$

Net Ionic equation ${\text{2OH}}^{\text{-}}+2H^{+}+P{b}^{2+}+2C{l}^{-}\to PbC{l}_2+2H_{2}O$

${\text{BaCO}}_{\text{3}}{\text{+ 2HCl= BaCl}}_{\text{2}}{\text{ + H}}_{\text{2}}{\text{O + CO}}_{\text{2}}$

Net Ionic equation $B{a}^{2+}+C{O}_3{}^{2-}+2H^{+}+2C{l}^{-}\to BaC{l}_2+H_{2}O+C{O}_2$

${\text{2CH}}_{\text{3}}{\text{CO}}_{\text{2}}{\text{H+ Ni(OH)}}_{\text{2}}{\text{=Ni(CH}}_{\text{3}}{\text{CO}}_{\text{2}}{\text{)}}_{\text{2}}{\text{+ 2H}}_{\text{2}}\text{O}$

Net Ionic equation ${\text{2CH}}_{\text{3}}{\text{COO}}^{-}+2H^{+}+N{i}^{2+}+2O{H}^{-}\to {\text{Ni(CH}}_{\text{3}}{\text{CO}}_{\text{2}}{\text{)}}_{\text{2}}{\text{+ 2H}}_{\text{2}}\text{O}$