FUND OF ENG THERMODYN-WILEYPLUS NEXT GEN
9th Edition
ISBN: 9781119840589
Author: MORAN
Publisher: WILEY
expand_more
expand_more
format_list_bulleted
Concept explainers
Videos
Question
Chapter 3, Problem 3.24CU
To determine
Corresponding states principle
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solution
Students have asked these similar questions
3.23
3.24
d
3.25. Gas at constant T and P is contained in a supply line connected through a valve to
closed tank containing the same gas at a lower pressure. The valve is opened to allow
flow of gas into the tank, and then is shut again.
(a) Develop a general equation relating n1 and n2, the moles (or mass) of gas in the
tank at the beginning and end of the process, to the properties U1 and U2, the
internal energy of the gas in the tank at the beginning and end of the process, and
H', the enthalpy of the gas in the supply line, and to Q, the heat transferred to the
material in the tank during the process.
(b) Reduce the general equation to its simplest form for the special case of an ideal
gas with constant heat capacities.
(c) Further reduce the equation of (b) for the case of n1 = 0.
(d) Further reduce the equation of (c) for the case in which, in addition, Q = 0.
(e) Treating nitrogen as an ideal gas for which Cp
equation to the case in which a steady supply of nitrogen at 25°C and…
2. For a certain gas, R = 0.377KJ/kg.K and k = 1.384. (a)What are the values of c, and a, ?
(b) What mass of this gas would occupy a volume of 0.552 m at 517.11 kPa and 36.7
deg. Celsius? (c) If 31.65 kJ is transferred to this gas at constant volume, what are the
resulting temperature and pressure? Use 2kgm
2.35 Consider the five processes a-b, b-c, c-d, d-a, and
a-c as sketched on the P-v coordinates. Show the
same processes on P-T and T-v coordinates
assuming ideal-gas behavior.
a
9.
P2
C
di
T1
V
Chapter 3 Solutions
FUND OF ENG THERMODYN-WILEYPLUS NEXT GEN
Ch. 3 - Prob. 3.1ECh. 3 - Prob. 3.2ECh. 3 - Prob. 3.3ECh. 3 - Prob. 3.4ECh. 3 - Prob. 3.6ECh. 3 - Prob. 3.7ECh. 3 - Prob. 3.8ECh. 3 - Prob. 3.9ECh. 3 - Prob. 3.10ECh. 3 - Prob. 3.11E
Ch. 3 - Prob. 3.12ECh. 3 - Prob. 3.13ECh. 3 - Prob. 3.1CUCh. 3 - Prob. 3.2CUCh. 3 - Prob. 3.3CUCh. 3 - Prob. 3.4CUCh. 3 - Prob. 3.5CUCh. 3 - Prob. 3.6CUCh. 3 - Prob. 3.7CUCh. 3 - Prob. 3.8CUCh. 3 - Prob. 3.9CUCh. 3 - Prob. 3.10CUCh. 3 - Prob. 3.11CUCh. 3 - Prob. 3.12CUCh. 3 - Prob. 3.13CUCh. 3 - Prob. 3.14CUCh. 3 - Prob. 3.15CUCh. 3 - Prob. 3.16CUCh. 3 - Prob. 3.17CUCh. 3 - Prob. 3.18CUCh. 3 - Prob. 3.19CUCh. 3 - Prob. 3.20CUCh. 3 - Prob. 3.21CUCh. 3 - Prob. 3.22CUCh. 3 - Prob. 3.23CUCh. 3 - Prob. 3.24CUCh. 3 - Prob. 3.25CUCh. 3 - Prob. 3.26CUCh. 3 - Prob. 3.27CUCh. 3 - Prob. 3.28CUCh. 3 - Prob. 3.29CUCh. 3 - Prob. 3.30CUCh. 3 - Prob. 3.31CUCh. 3 - Prob. 3.32CUCh. 3 - Prob. 3.33CUCh. 3 - Prob. 3.34CUCh. 3 - Prob. 3.35CUCh. 3 - Prob. 3.36CUCh. 3 - Prob. 3.37CUCh. 3 - Prob. 3.38CUCh. 3 - Prob. 3.39CUCh. 3 - Prob. 3.40CUCh. 3 - Prob. 3.41CUCh. 3 - Prob. 3.42CUCh. 3 - Prob. 3.43CUCh. 3 - Prob. 3.44CUCh. 3 - Prob. 3.45CUCh. 3 - Prob. 3.46CUCh. 3 - Prob. 3.47CUCh. 3 - Prob. 3.48CUCh. 3 - Prob. 3.49CUCh. 3 - Prob. 3.50CUCh. 3 - Prob. 3.51CUCh. 3 - Prob. 3.52CUCh. 3 - Prob. 3.1PCh. 3 - Prob. 3.2PCh. 3 - Prob. 3.3PCh. 3 - Prob. 3.4PCh. 3 - Prob. 3.5PCh. 3 - Prob. 3.6PCh. 3 - Prob. 3.7PCh. 3 - Prob. 3.8PCh. 3 - Prob. 3.9PCh. 3 - Prob. 3.10PCh. 3 - Prob. 3.11PCh. 3 - Prob. 3.12PCh. 3 - Prob. 3.13PCh. 3 - Prob. 3.14PCh. 3 - Prob. 3.15PCh. 3 - Prob. 3.16PCh. 3 - Prob. 3.17PCh. 3 - Prob. 3.18PCh. 3 - Prob. 3.19PCh. 3 - Prob. 3.20PCh. 3 - Prob. 3.21PCh. 3 - Prob. 3.22PCh. 3 - Prob. 3.23PCh. 3 - Prob. 3.24PCh. 3 - Prob. 3.25PCh. 3 - Prob. 3.26PCh. 3 - Prob. 3.27PCh. 3 - Prob. 3.28PCh. 3 - Prob. 3.29PCh. 3 - Prob. 3.30PCh. 3 - Prob. 3.31PCh. 3 - Prob. 3.32PCh. 3 - Prob. 3.33PCh. 3 - Prob. 3.34PCh. 3 - Prob. 3.35PCh. 3 - Prob. 3.36PCh. 3 - Prob. 3.37PCh. 3 - Prob. 3.38PCh. 3 - Prob. 3.39PCh. 3 - Prob. 3.40PCh. 3 - Prob. 3.41PCh. 3 - Prob. 3.42PCh. 3 - Prob. 3.43PCh. 3 - Prob. 3.44PCh. 3 - Prob. 3.45PCh. 3 - Prob. 3.46PCh. 3 - Prob. 3.47PCh. 3 - Prob. 3.48PCh. 3 - Prob. 3.49PCh. 3 - Prob. 3.50PCh. 3 - Prob. 3.51PCh. 3 - Prob. 3.52PCh. 3 - Prob. 3.53PCh. 3 - Prob. 3.54PCh. 3 - Prob. 3.55PCh. 3 - Prob. 3.56PCh. 3 - Prob. 3.57PCh. 3 - Prob. 3.58PCh. 3 - Prob. 3.59PCh. 3 - Prob. 3.60PCh. 3 - Prob. 3.61PCh. 3 - Prob. 3.62PCh. 3 - Prob. 3.63PCh. 3 - Prob. 3.64PCh. 3 - Prob. 3.65PCh. 3 - Prob. 3.66PCh. 3 - Prob. 3.67PCh. 3 - Prob. 3.68PCh. 3 - Prob. 3.69PCh. 3 - Prob. 3.70PCh. 3 - Prob. 3.71PCh. 3 - Prob. 3.72PCh. 3 - Prob. 3.73PCh. 3 - Prob. 3.74PCh. 3 - Prob. 3.75PCh. 3 - Prob. 3.76PCh. 3 - Prob. 3.77PCh. 3 - Prob. 3.78PCh. 3 - Prob. 3.79PCh. 3 - Prob. 3.80PCh. 3 - Prob. 3.81PCh. 3 - Prob. 3.82PCh. 3 - Prob. 3.83PCh. 3 - Prob. 3.84PCh. 3 - Prob. 3.85PCh. 3 - Prob. 3.86PCh. 3 - Prob. 3.87PCh. 3 - Prob. 3.88PCh. 3 - Prob. 3.89PCh. 3 - Prob. 3.90PCh. 3 - Prob. 3.91PCh. 3 - Prob. 3.92PCh. 3 - Prob. 3.93PCh. 3 - Prob. 3.94PCh. 3 - Prob. 3.95PCh. 3 - Prob. 3.96PCh. 3 - Prob. 3.97PCh. 3 - Prob. 3.98PCh. 3 - Prob. 3.99P
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, mechanical-engineering and related others by exploring similar questions and additional content below.Similar questions
- WA 4. a Th To Room temperature T = 293 K %3D V The gas volume changes from Vp to Va at constant temperature T. The cartoon on the right shows a piston of gas undergoing this compression while submerged in a container of room temperature water, which acts as a reservoir. The initial state of this process is a piston containing 2 moles of a monatomic gas at T, = 293 K (room temperature water) and volume V = 1.0 m. The gas is compressed until V, = 0.2 m. During the compression, the heat bath of room temperature water maintains the temperature of the gas at T = 293 K. Calculate the change in internal energy of the gas in joules during this process. Do not include units in your answer. Be careful to use the standard sign conventions for heat and work. Write your numerical answer in normal form as described above in the instructions to this worksheet. Click Save and Submit to save and submit. Click Save All Answers to save all answers. 28 F aarrow_forwardOn a T-V diagram sketch the constant specific volume through the reference state (state 0) T = 250C, v = 1.1989 m^3/kg from T1 = 350C to T2 = 120C. Sketch the constant pressure curves through the states so that they extend form the compressed liquid region to the superheated region. Places states on diagram along with their temperatures, pressures, and specific volumes on the diagram axes. The fluid is water.arrow_forwardA PV diagram below, Figure 1, shows two possible states of a system containing three moles of a monatomic ideal gas. (P,= P2 = 450 Pa, V, = 2m', V,= 8m²) c. Draw the process which depicts an isothermal expansion from state 1 to the volume V, followed by an isochoric increase in temperature to state 2 and label this process (B). d. Find the change in internal energy of the gas for the two-step process (B) Figure 1 (N/m²) 500 ! 400+ 300+ 200+ 100 - + + + + 4 6. 8 10 V (m³) 2 Copyright © 2005 Pearson Prentice Hall, Inc.arrow_forward
- Define the van der Waals Equation of State.arrow_forwardThe van der Wails equation of state is p ± (v-b = RT, where p is pressure, v is specific volume, T is temperature and R is characteristic gas constant The SI unit of a isarrow_forwardThoses two answers are not correct can you help me with others which is the correct onearrow_forward
- V. W. Th To %3D Room temperature T = 293 K V V. Vp The gas volume changes from Vp to Va at constant temperature T. The cartoon on the right shows a piston of gas undergoing this compression while submerged in a container of room temperature water, which acts as a reservoir. The initial state of this process is a piston containing 2 moles of a monatomic gas at Tc = 293 K (room temperature water) and volume V = a 1.0 m. The gas is compressed until V, = 0.2 m. During the compression, the heat bath of room temperature water maintains the temperature of the gas at T 293 K. Calculate the work done in joules by the gas during this process. Do not include units in your answer. Be careful to use the standard sign convention for work done by the gas. Write your numerical answer in normal form as described above in the instructions to this worksheet.arrow_forward(e) Any change that a system undergoes from one equilibrium state to another is called a process. What is a process during which the specific volume remains constant?arrow_forwardp62,#13 with illustration and explanationarrow_forward
- 2. Consider a metal rod with the equation of state L- Lo = Lo +a(T YA %3D Here Lo, Y, A, To, and a are constants,T is the temperature, L is the length, and F is the tension. Work is given by dW a) Using the first law and the expression for dU in terms of it partial derivatives with respect to T and L, show that for this system -FdL. (). -). G). (4). - se, b) By differentiating the first of these equations with respect to L and the second with respect to T show that ), -r(器). =F-T ƏT c) Using the above result and the equation of state, find an expression for (0/aL). Then, assuming that C. the heat capacity at constant length is a Constant. find an expression for the internal energy, U, as a function of T and L.arrow_forwardcan water ever acts counter to entropy to perhaps stop a reaction from moving forward?arrow_forwardc. What is the internal energy, u, in kJ/kg of refrigerant R22 at temperature T=-10°C. and specific volume v=0.055 m³/kg? Draw a p-v and T-o diagram and locate the state. What is the phase of the state?arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
Elements Of ElectromagneticsMechanical EngineeringISBN:9780190698614Author:Sadiku, Matthew N. O.Publisher:Oxford University Press
Mechanics of Materials (10th Edition)Mechanical EngineeringISBN:9780134319650Author:Russell C. HibbelerPublisher:PEARSON
Thermodynamics: An Engineering ApproachMechanical EngineeringISBN:9781259822674Author:Yunus A. Cengel Dr., Michael A. BolesPublisher:McGraw-Hill Education
Control Systems EngineeringMechanical EngineeringISBN:9781118170519Author:Norman S. NisePublisher:WILEY
Mechanics of Materials (MindTap Course List)Mechanical EngineeringISBN:9781337093347Author:Barry J. Goodno, James M. GerePublisher:Cengage Learning
Engineering Mechanics: StaticsMechanical EngineeringISBN:9781118807330Author:James L. Meriam, L. G. Kraige, J. N. BoltonPublisher:WILEY
Elements Of Electromagnetics
Mechanical Engineering
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Oxford University Press
Mechanics of Materials (10th Edition)
Mechanical Engineering
ISBN:9780134319650
Author:Russell C. Hibbeler
Publisher:PEARSON
Thermodynamics: An Engineering Approach
Mechanical Engineering
ISBN:9781259822674
Author:Yunus A. Cengel Dr., Michael A. Boles
Publisher:McGraw-Hill Education
Control Systems Engineering
Mechanical Engineering
ISBN:9781118170519
Author:Norman S. Nise
Publisher:WILEY
Mechanics of Materials (MindTap Course List)
Mechanical Engineering
ISBN:9781337093347
Author:Barry J. Goodno, James M. Gere
Publisher:Cengage Learning
Engineering Mechanics: Statics
Mechanical Engineering
ISBN:9781118807330
Author:James L. Meriam, L. G. Kraige, J. N. Bolton
Publisher:WILEY
First Law of Thermodynamics, Basic Introduction - Internal Energy, Heat and Work - Chemistry; Author: The Organic Chemistry Tutor;https://www.youtube.com/watch?v=NyOYW07-L5g;License: Standard youtube license