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(a)
Interpretation:
Unit cell volume should be calculated
Concept Introduction:
The atomic symbol of bismuth is Bi and has the atomic number of 83. The indium metal is a post transition pentavalent one and the earth has natural bismuth metal. The bismuth oxides and sulfide forms essential ores that are of commercial use. The pnictogens of the metal along with its chemical properties resembles homologs light arsenic and antimony.
(b)
Interpretation:
Atom numbers per unit cell should be calculated.
Concept Introduction:
The atomic symbol of bismuth is Bi and has the atomic number of 83. The indium metal is a post transition pentavalent one and the earth has natural bismuth metal. The bismuth oxides and sulfide forms essential ores that are of commercial use. The pnictogens of the metal along with its chemical properties resembles homologs light arsenic and antimony.
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Chapter 3 Solutions
Essentials Of Materials Science And Engineering, Si Edition
- Fig 2 (II) [60 Points] Using centered finite difference approximation as done in class, solve the equation: 020 020 + მx2 მy2 +0.0150+Q=0 subject to the boundary conditions shown in the stencils below. Do this for two values of Q: (a) Q = 0.3, and (b) Q = 10.5x² + 1.26 * 1.5 x 0.002 0.008. For Case (a) (that is, Q = 0.3) use Fig 3. For Case (b), use both Fig. 3 and Fig 4. For all the three cases, show a table as well as the contour plots of versus (x, y), and the (x, y) heat flux values at all the nodes on the boundaries x = 1 and y = 1. Discuss your results. Use MATLAB and hand in the MATLAB codes. (Note that the domain is (x, y)e[0,1] x [0,1].) 0=0 0=0 4 8 12 16 10 Ꮎ0 15 25 9 14 19 24 3 11 15 0=0 8-0 0=0 3 8 13 18 23 2 6 сл 5 0=0 10 14 6 12 17 22 1 6 11 16 21 13 e=0 Fig 3 Fig 4 Textbook: Numerical Methods for Engineers, Steven C. Chapra and Raymond P. Canale, McGraw-Hill, Eighth Edition (2021).arrow_forwardA structure is an intersecting hip roof with the main hip roof outside dimensions being 73 ft long and the width being 30 ft wide. The intersection portion extends 20 ft beyond the 30-ft side, and the intersecting portion is 20 ft wide. The overhang is 2 ft 6 in. and the slope is 5:12. The rafters are 16 in. on center. Based on the information provided, what is the total length of the common rafters in linear feet?arrow_forwardHow many board feet is 200 lnft of 2 in. × 6 in wood studs.arrow_forward
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- 2. A support hook was formed from a rectangular bar. Find the stresses at the inner and outer surfaces at sections just above and just below O-B. -210 mm 120 mm 160 mm 400 N B thickness 8 mm = Figure 2 - Problem 2arrow_forwardExample: Determine the minimum slope in the upper reach of a chute section of 30 m width. The range of discharge is 150 to 2000 m³/sec. n = 0.015.arrow_forwardIn the past, encryption and decryption were mostly done by substitution and permutation of letters in a text message. study those classic cryptographic schemes Then, develop an automatic cipher using Javascript The cipher should be able to perform the following tasks: generate keys encrypt a given plaintext message with a key selected from the list of keys generated decrypt a given ciphertext message with a known cipher keyarrow_forward
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