The Ballot Problem. In an election, candidate A receives n votes and candidate B receives m votes, where n > m . Assuming that all of the ( n + m ) ! n ! m ! orderings of the votes are equally likely, let P n , m denote the probability that A is always ahead in the counting of the votes. a. Compute P 2 , 1 , P 3 , 1 , P 3 , 1 , P 3 , 2 , P 4 , 1 , P 4 , 2 , P 4 , 3 . b. Find P n , 1 , P m , 2 . c. On the basis of your results in parts (a) and (b), conjecture the value of P n , m . d. Derive a recursion for P n , m in terms of P n − 1 , m and P n , m − 1 by conditioning on who receives the last vote. e. Use part (d) to verify your conjecture in part (c) by an induction proof on n + m .
The Ballot Problem. In an election, candidate A receives n votes and candidate B receives m votes, where n > m . Assuming that all of the ( n + m ) ! n ! m ! orderings of the votes are equally likely, let P n , m denote the probability that A is always ahead in the counting of the votes. a. Compute P 2 , 1 , P 3 , 1 , P 3 , 1 , P 3 , 2 , P 4 , 1 , P 4 , 2 , P 4 , 3 . b. Find P n , 1 , P m , 2 . c. On the basis of your results in parts (a) and (b), conjecture the value of P n , m . d. Derive a recursion for P n , m in terms of P n − 1 , m and P n , m − 1 by conditioning on who receives the last vote. e. Use part (d) to verify your conjecture in part (c) by an induction proof on n + m .
Solution Summary: The author explains how the probabilities are calculated for n+m people voting for A or B, with votes being read in random order.
The Ballot Problem. In an election, candidate A receives n votes and candidate B receives m votes, where
n
>
m
. Assuming that all of the
(
n
+
m
)
!
n
!
m
!
orderings of the votes are equally likely, let
P
n
,
m
denote the probability that A is always ahead in the counting of the votes.
a. Compute
P
2
,
1
,
P
3
,
1
,
P
3
,
1
,
P
3
,
2
,
P
4
,
1
,
P
4
,
2
,
P
4
,
3
.
b. Find
P
n
,
1
,
P
m
,
2
.
c. On the basis of your results in parts (a) and (b), conjecture the value of
P
n
,
m
.
d. Derive a recursion for
P
n
,
m
in terms of
P
n
−
1
,
m
and
P
n
,
m
−
1
by conditioning on who receives the last vote.
e. Use part (d) to verify your conjecture in part (c) by an induction proof on
n
+
m
.
التمرين الأول: 08) نقاط)
نرمي رباعي وجوه مرقم من ا إلى 4 بحيث إحتمال وجوهه يحقق العلاقة التالية: - 24 = (3)P(1) = ) = 4P
-1 أحسب احتمال كل وجه.
-2
(١ أحسب احتمال الحادثة : الحصول على عدد زوجي).
ب استنتج احتمال الحادثة ة.
-3 أحسب احتمال الحادثة B الحصول على عدد د أكبر أو يساوي (2)
Please solve the following Probability problem. Show all work and solve all parts that are asked:
HW 1.y.(Yutnori)
Yutnori is played by 2 (groups of) players on a gameboard with pieces thatmove around. Each player takes turns throwing yut sticks - each stick hastwo sides, round and flat, which makes the stick roll. Five combinationsare possible with yut sticks: do, gae, geol, yut and mo. A player achievinga yut or mo is allowed to roll again. Combinations and the number ofmoves they allow on the gameboard are presented in Figure 3 (flat sideup is blank and round side up is filled with x-es).
Assuming each of the 4 Yut sticks falls on both of its sides with equalprobability, what is the probability that:a) you roll a yut?b) you roll a geol ?c) you get a second roll?d) you move 6 spaces in your first turn?In reality, a typical Yut stick is designed so that the probability of flat sidefacing up is around 60%. Try to think of what the previous probabilitieswould be in this case.
Please solve the following Probability Problem, please show all work and solve what is asked:
HW 1.w. (Special game)The atmosphere has heated up and a fight erupted! There are n + 1players and somebody threw the first punch. Once a person is punched,they punch another person in the group at random. What are the oddsthat after m iterations:a) Nobody punches the person who started it?b) Nobody gets punched twice?Now take it up a notch: imagine the first person punched N other peopleat random, and once someone gets punched, they punch another N peoplein the group at random, and so on. Again, what are the odds that afterm iterations:a) Nobody punches the person who started it?b) Nobody gets punched twice?
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