ELEM.PRIN.OF CHEMICAL PROC.-W/ACCESS
ELEM.PRIN.OF CHEMICAL PROC.-W/ACCESS
4th Edition
ISBN: 9781119330745
Author: FELDER
Publisher: WILEY
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Chapter 3, Problem 3.20P
Interpretation Introduction

(a)

Interpretation:

How many of kg of C8 H10 in 15 kmol of C8 H10.

Concept introduction:

The mole is defined as the amount of substance containing the same number of chemical units. This can be written as,

Mole = Mass of the substance / Molecular weight of the substance

Interpretation Introduction

(b)

Interpretation:

How many of mol of C8 H10 in 15 kmol of C8 H10.

Concept introduction:

The mole is defined as the amount of substance containing the same number of chemical units. This can be written as,

Mole = Mass of the substance / Molecular weight of the substance

Units can be converted as,

1 kmol = 1000 mol

Interpretation Introduction

(c)

Interpretation:

How many of lb-mol of C8 H10 in 15 kmol of C8 H10.

Concept introduction:

The mole is defined as the amount of substance containing the same number of chemical units. This can be written as,

Mole = Mass of the substance / Molecular weight of the substance

Units can be converted as,

1 lb-mol = 453.6 mol

Interpretation Introduction

(d)

Interpretation:

How many of mol (g-atom) of C in 15 kmol of C8 H10.

Concept introduction:

The mole is defined as the amount of substance containing the same number of chemical units. This can be written as,

Mole = Mass of the substance / Molecular weight of the substance

Interpretation Introduction

(e)

Interpretation:

How many of mol (g-atom) of H in 15 kmol of C8 H10.

Concept introduction:

The mole is defined as the amount of substance containing the same number of chemical units. This can be written as,

Mole = Mass of the substance / Molecular weight of the substance

Interpretation Introduction

(f)

Interpretation:

How many of g of C in 15 kmol of C8 H10.

Concept introduction:

The mole is defined as the amount of substance containing the same number of chemical units. This can be written as,

Mole = Mass of the substance / Molecular weight of the substance

Interpretation Introduction

(g)

Interpretation:

How many of g of H in 15 kmol of C8 H10.

Concept introduction:

The mole is defined as the amount of substance containing the same number of chemical units. This can be written as,

Mole = Mass of the substance / Molecular weight of the substance

Interpretation Introduction

(h)

Interpretation:

How many of molecules in 15 kmol of C8 H10.

Concept introduction:

The mole is defined as the amount of substance containing the same number of chemical units. This can be written as,

Mole = Mass of the substance / Molecular weight of the substance

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Chapter 3 Solutions

ELEM.PRIN.OF CHEMICAL PROC.-W/ACCESS

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