Process Dynamics and Control, 4e
4th Edition
ISBN: 9781119285915
Author: Seborg
Publisher: WILEY
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Textbook Question
Chapter 3, Problem 3.17E
UseLaplace transforms to find the solution to the following set of equations
for
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6. In a process design, the following process streams must be cooled or heated:
Stream
No
mCp
Temperature In Temperature Out
°C
°C
kW/°C
1
5
350
270
2
9
270
120
3
3
100
320
4
5
120
288
Use the MUMNE algorithm for heat exchanger networks with a minimum approach
temperature of 20°C.
(5)
a. Determine the temperature interval diagram.
(3)
(2)
(10)
(10)
b. Determine the cascade diagram, the pinch temperatures, and the minimum hot and
cold utilities.
c. Determine the minimum number of heat exchangers above and below the pinch.
d. Determine a valid heat exchange network above the pinch.
e. Determine a valid heat exchange network below the pinch.
Use this equation to solve it.
Q1: Consider the following transfer function
G(s)
5e-s
15s +1
1. What is the study state gain
2. What is the time constant
3. What is the value of the output at the end if the input is a unit step
4. What is the output value if the input is an impulse function with amplitude equals
to 3, at t=7
5. When the output will be 3.5 if the input is a unit step
Chapter 3 Solutions
Process Dynamics and Control, 4e
Ch. 3 - Find the Laplace transforms of the following...Ch. 3 - Prob. 3.2ECh. 3 - Prob. 3.3ECh. 3 - Prob. 3.4ECh. 3 - Prob. 3.5ECh. 3 - Using PFE where required, find X(t) for a....Ch. 3 - Expand each of the following s-domain functions...Ch. 3 - For the integro-differential equation,...Ch. 3 - Prob. 3.9ECh. 3 - Which solutions of the following equations will...
Ch. 3 - Prob. 3.11ECh. 3 - Find the complete time-domain solutions for the...Ch. 3 - Prob. 3.13ECh. 3 - Prob. 3.14ECh. 3 - Prob. 3.15ECh. 3 - Prob. 3.16ECh. 3 - UseLaplace transforms to find the solution to the...Ch. 3 - Prob. 3.18ECh. 3 - Prob. 3.19ECh. 3 - Prob. 3.20ECh. 3 - Prob. 3.21ECh. 3 - Solve this ODE using a Symbolic software program:...
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- Example(3): It is desired to design a double effect evaporator for concentrating a certain caustic soda solution from 12.5wt% to 40wt%. The feed at 50°C enters the first evaporator at a rate of 2500kg/h. Steam at atmospheric pressure is being used for the said purpose. The second effect is operated under 600mmHg vacuum. If the overall heat transfer coefficients of the two stages are 1952 and 1220kcal/ m2.h.°C. respectively, determine the heat transfer area of each effect. The BPR will be considered and present for the both effect 5:49arrow_forwardالعنوان ose only Q Example (7): Determine the heating surface area 개 required for the production of 2.5kg/s of 50wt% NaOH solution from 15 wt% NaOH feed solution which entering at 100 oC to a single effect evaporator. The steam is available as saturated at 451.5K and the boiling point rise (boiling point evaluation) of 50wt% solution is 35K. the overall heat transfer coefficient is 2000 w/m²K. The pressure in the vapor space of the evaporator at atmospheric pressure. The solution has a specific heat of 4.18kJ/ kg.K. The enthalpy of vaporization under these condition is 2257kJ/kg Example (6): 5:48 An evaporator is concentrating F kg/h at 311K of a 20wt% solution of NaOH to 50wt %. The saturated steam used for heating is at 399.3K. The pressure in the vapor space of the evaporator is 13.3 KPa abs. The 5:48 1 J ۲/۱ ostrarrow_forwardExample 8: 900 Kg dry solid per hour is dried in a counter current continues dryer from 0.4 to 0.04 Kg H20/Kg wet solid moisture content. The wet solid enters the dryer at 25 °C and leaves at 55 °C. Fresh air at 25 °C and 0.01Kg vapor/Kg dry air is mixed with a part of the moist air leaving the dryer and heated to a temperature of 130 °C in a finned air heater and enters the dryer with 0.025 Kg/Kg alry air. Air leaving the dryer at 85 °C and have a humidity 0.055 Kg vaper/Kg dry air. At equilibrium the wet solid weight is 908 Kg solid per hour. *=0.0088 Calculate:- Heat loss from the dryer and the rate of fresh air. Take the specific heat of the solid and moisture are 980 and 4.18J/Kg.K respectively, A. =2500 KJ/Kg. Humid heat at 0.01 Kg vap/Kg dry=1.0238 KJ/Kg. "C. Humid heat at 0.055 Kg/Kg 1.1084 KJ/Kg. "C 5:42 Oarrow_forward
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