EBK USING MIS
10th Edition
ISBN: 8220103633642
Author: KROENKE
Publisher: YUZU
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Chapter 3, Problem 3.13MML
a)
Explanation of Solution
Analyzing five competitive force would help Samantha in her business:
Porter’s five competitive force will help Samantha to financially stand at her owned business.
- Most of the customer tries to bargain some services to reduce the rate of the services and deliverability of the best quality.
- She provide both the services, trimming a tree and removing a tree. So customer expectations for both the services will differ.
- They expect a good quality of work in order for the customers to appreciate the service provided by Samantha...
b)
Explanation of Solution
Analyzing Samantha’s competitive strategy:
“No”, Samantha does not follow any competitive strategy. She operates his business on the survival mode...
c)
Explanation of Solution
View of competitive strategy towards sales and marketing efforts:
Samantha should keep in mind that she is not doing the process of tree and landscape trimming, rather she is performing the service business...
d)
Explanation of Solution
Kind of
- Samantha has to be responsible to the customer calls. For that she need to establish a tracking system which calls in timely way...
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D. S. Malik, Data Structures Using C++, 2nd Edition, 2010
Methods (Ch6) - Review
1. (The MyRoot method) Below is a manual implementation of the Math.sqrt() method in Java.
There are two methods, method #1 which calculates the square root for positive integers, and
method #2, which calculates the square root of positive doubles (also works for integers).
public class SquareRoot {
public static void main(String[] args) {
}
// implement a loop of your choice here
// Method that calculates the square root of integer variables
public static double myRoot(int number) {
double root;
root=number/2;
double root old;
do {
root old root;
root (root_old+number/root_old)/2;
} while (Math.abs(root_old-root)>1.8E-6);
return root;
}
// Method that calculates the square root of double variables
public static double myRoot(double number) {
double root;
root number/2;
double root_old;
do {
root old root;
root (root_old+number/root_old)/2;
while (Math.abs (root_old-root)>1.0E-6);
return root;
}
}
Program-it-Yourself: In the main method, create a program that…
I would like to know the main features about the following 3 key concepts:1. Backup Domain Controller (BDC)2. Access Control List (ACL)3. Dynamic Memory
Chapter 3 Solutions
EBK USING MIS
Ch. 3.3 - Prob. 1EGDQCh. 3.3 - Prob. 2EGDQCh. 3.3 - Prob. 3EGDQCh. 3.3 - Prob. 4EGDQCh. 3.7 - Prob. 1TARQCh. 3.7 - Prob. 2TARQCh. 3.7 - Prob. 3TARQCh. 3.7 - Prob. 4TARQCh. 3.8 - Prob. 1SGDQCh. 3.8 - Prob. 2SGDQ
Ch. 3.8 - Prob. 3SGDQCh. 3.8 - Prob. 4SGDQCh. 3.8 - Prob. 3.1ARQCh. 3.8 - Prob. 3.2ARQCh. 3.8 - Prob. 3.3ARQCh. 3.8 - Prob. 3.4ARQCh. 3.8 - Prob. 3.5ARQCh. 3.8 - Prob. 3.6ARQCh. 3.8 - Prob. 3.7ARQCh. 3.8 - Prob. 3.8ARQCh. 3 - Prob. 3.1UYKCh. 3 - Prob. 3.2UYKCh. 3 - Prob. 3.3UYKCh. 3 - Prob. 3.1CE3Ch. 3 - Prob. 3.4CS3Ch. 3 - Prob. 3.5CS3Ch. 3 - Prob. 3.6CS3Ch. 3 - Prob. 3.7CS3Ch. 3 - Prob. 3.8CS3Ch. 3 - Prob. 3.9CS3Ch. 3 - Prob. 3.10CS3Ch. 3 - Prob. 3.11CS3Ch. 3 - Prob. 3.12CS3Ch. 3 - Prob. 3.13MMLCh. 3 - Prob. 3.14MMLCh. 3 - Prob. 3.15MML
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