Potassium superoxide, KO 2 , is employed in a self-contained breathing apparatus used by emergency personnel as a source of oxygen. The reaction is 4 KO 2 ( s ) + 2 H 2 O ( l ) → 4 KOH ( s ) + 3 O 2 ( g ) If a self-contained breathing apparatus is charged with 750 g KO 2 and then is used to produce 188 g of oxygen, was all of the KO 2 consumed in this reaction? If the KO 2 wasn’t all consumed, how much is left over and what mass of additional O 2 could be produced?
Potassium superoxide, KO 2 , is employed in a self-contained breathing apparatus used by emergency personnel as a source of oxygen. The reaction is 4 KO 2 ( s ) + 2 H 2 O ( l ) → 4 KOH ( s ) + 3 O 2 ( g ) If a self-contained breathing apparatus is charged with 750 g KO 2 and then is used to produce 188 g of oxygen, was all of the KO 2 consumed in this reaction? If the KO 2 wasn’t all consumed, how much is left over and what mass of additional O 2 could be produced?
Solution Summary: The author calculates the amount of KO_Text2 left over and the mass of additional Oxygen.
Potassium superoxide, KO2, is employed in a self-contained breathing apparatus used by emergency personnel as a source of oxygen. The reaction is
4
KO
2
(
s
)
+
2
H
2
O
(
l
)
→
4
KOH
(
s
)
+
3
O
2
(
g
)
If a self-contained breathing apparatus is charged with 750 g KO2 and then is used to produce 188 g of oxygen, was all of the KO2 consumed in this reaction? If the KO2 wasn’t all consumed, how much is left over and what mass of additional O2 could be produced?
5. A solution of sucrose is fermented in a vessel until the evolution of CO2 ceases. Then, the
product solution is analyzed and found to contain, 45% ethanol; 5% acetic acid; and 15%
glycerin by weight.
If the original charge is 500 kg, evaluate;
e. The ratio of sucrose to water in the original charge (wt/wt).
f. Moles of CO2 evolved.
g. Maximum possible amount of ethanol that could be formed.
h. Conversion efficiency.
i. Per cent excess of excess reactant.
Reactions:
Inversion reaction: C12H22O11 + H2O →2C6H12O6
Fermentation reaction: C6H12O6 →→2C2H5OH + 2CO2
Formation of acetic acid and glycerin: C6H12O6 + C2H5OH + H₂O→ CH3COOH + 2C3H8O3
Show work. don't give Ai generated solution. How many carbons and hydrogens are in the structure?
13. (11pts total) Consider the arrows pointing at three different carbon-carbon bonds in the
molecule depicted below.
Bond B
2°C. +2°C. cleavage
Bond A
•CH3 + 26.← Cleavage
2°C. +
Bond C
+3°C•
CH3 2C
Cleavage
E
2°C. 26.
weakest bond
Intact molecule
Strongest 3°C 20.
Gund
Largest
argest
a. (2pts) Which bond between A-C is weakest? Which is strongest? Place answers in
appropriate boxes.
C
Weakest
bond
A
Produces
Most
Bond
Strongest
Bond
Strongest Gund
produces least stable
radicals
Weakest
Stable radical
b. (4pts) Consider the relative stability of all cleavage products that form when bonds A,
B, AND C are homolytically cleaved/broken. Hint: cleavage products of bonds A, B,
and C are all carbon radicals.
i. Which ONE cleavage product is the most stable? A condensed or bond line
representation is fine.
13°C. formed in
bound C
cleavage
ii. Which ONE cleavage product is the least stable? A condensed or bond line
representation is fine.
• CH3
methyl radical
Formed in Gund A Cleavage
c.…
Chapter 3 Solutions
OWLv2 with Student Solutions Manual eBook for Ebbing/Gammon's General Chemistry, 11th Edition, [Instant Access], 4 terms (24 months)
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