Concept explainers
(a)
Interpretation:
The reaction between solid tetraphosphorus trisulfide and oxygen gas to form solid tetraphosphorus decoxide and sulfur dioxide gas is to be shown in terms of molecules.
Concept introduction:
In a balanced chemical equation, the total mass of reactants and products are equal in a balanced chemical equation, thus, it obeyed the law of conservation of mass. Also, the amounts of substances in a balanced
The coefficients in the balanced equation tell about the number of molecules or moles of each reactant and product involved in the reaction.
(b)
Interpretation:
The reaction between solid tetraphosphorus trisulfide and oxygen gas to form solid tetraphosphorus decoxide and sulfur dioxide gas is to be shown in terms of moles.
Concept introduction:
In a balanced chemical equation, the total mass of reactants and products are equal in a balanced chemical equation, thus, it obeyed the law of conservation of mass. Also, the amounts of substances in a balanced chemical reaction are stoichiometrically equivalent to each other.
The coefficients in the balanced equation tell about the number of molecules or moles of each reactant and product involved in the reaction.
(c)
Interpretation:
The reaction between solid tetraphosphorus trisulfide and oxygen gas to form solid tetraphosphorus decoxide and sulfur dioxide gas is to be shown in terms of grams.
Concept introduction:
In a balanced chemical equation, the total mass of reactants and products are equal in a balanced chemical equation, thus, it obeyed the law of conservation of mass. Also, the amounts of substances in a balanced chemical reaction are stoichiometrically equivalent to each other.
The coefficients in the balanced equation tell about the number of molecules or moles of each reactant and product involved in the reaction.
The formula to calculate the mass is as follows:
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Chapter 3 Solutions
MCGRAW: CHEMISTRY THE MOLECULAR NATURE
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- 4. Assign the following molecules to proper point groups: Pyridine N 1,3,5-triazine N Narrow_forward7. a) Under normal conditions (room temperature & atmospheric pressure) potassium assumes bcc lattice. Atomic radius for 12-coordinate K atom is listed as 235 pm. What is the radius of potassium atom under normal conditions? (3 points) b) Titanium metal crystallyzes in hcp lattice. Under proper conditions nitrogen can be absorbed into the lattice of titanium resulting in an alloy of stoichiometry TiNo.2. Is this compound likely to be a substitutional or an interstitial alloy? (Radius of Ti (12-coordinate) is 147 pm; radius of N atom is 75 pm. (3 points)arrow_forwardcan someone answer the questions and draw out the complete mechanismarrow_forward
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