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In later years, motors improved and could be run directly from a 60 Hz power supply. As a result, 25 Hz power systems shrank and disappeared. However, there were many perfectly good working 25 Hz motors in factories around the country that owners were not ready to discard. To keep them running, some users created their own 25 Hz power in the plant using motor-generator sets. A motor-generator set consists of two machines connected on a common shaft, one acting as a motor and the other acting as a generator. If the two machines have different numbers of poles but exactly the same shaft speed, then the electrical frequency of the two machines will be different due to Equation (3-34). What combination of poles on the two machines could convert 60 Hz power to 25 Hz power?
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Chapter 3 Solutions
Electric machinery fundamentals
- use this code on the bottom to answer the question in the photo clc; clearvars; % Read the file [y, Fs] = audioread('106miles.wav'); N = length(y); Nfft = 2^nextpow2(N); dt = 1/Fs; t = (0:dt:(N-1)*dt)'; % Ensure t is a column vector y = y - mean(y); % Remove DC component (if not already zero-mean) % Carrier signal (25 kHz) fc = 25000; % Carrier frequency in Hz carrier = cos(2 * pi * fc * t); % DSB-SC Modulation modulated_signal = y .* carrier; % Plot Time Domain Signal figure; subplot(2,1,1); plot(t, y); title('Original Signal (Time Domain)'); xlabel('Time (s)'); ylabel('Amplitude'); subplot(2,1,2); plot(t, modulated_signal); title('DSB-SC Modulated Signal (Time Domain)'); xlabel('Time (s)'); ylabel('Amplitude'); % Frequency Domain (FFT) Y = fft(y, Nfft) / Nfft; Modulated_Y = fft(modulated_signal, Nfft) / Nfft; f = Fs * (0:(Nfft/2)) / Nfft; % Frequency vector % Plot Frequency Domain Signal figure; subplot(2,1,1); plot(f, abs(Y(1:Nfft/2+1))); title('Original Signal…arrow_forward5-9 A 230 V shunt motor has a nominal arma- ture current of 60 A. If the armature resist- ance is 0.152, calculate the following: a. The counter-emf [V] b. The power supplied to the armature [W] c. The mechanical power developed by the motor, [kW] and [hp] 5-10 a. In Problem 5-9 calculate the initial start- ing current if the motor is directly con- nected across the 230 V line. b. Calculate the value of the starting resistor needed to limit the initial current to 115 A.arrow_forwardhow to solve this?arrow_forward
- For the circuit in Fig. P8.52, choose the load impedance ZLso that the power dissipated in it is a maximum. How much powerwill that be?arrow_forwardhow to solve the attached question? please explain or give reference where required in the solution.arrow_forwardHANDWRITTEN SOLUTION REQUIRED NOT USING CHATGPTarrow_forward
- Please only do part E and F. Please show your work and be as detailed as possible. Please explain the relationship between K the gain and stability of the system. Also, show how to plot the poles and why they are on either the real or imaginary axis. What is it about the example that indicated that? thank youarrow_forwardPlease draw the block diagram for this problem and explain how. thank youarrow_forwardPlease show your work and be as detailed as possible. I would like to really understand the connection between the type of loop, the dampness, and the gain, K. Thank youarrow_forward
- In the zone refining of silicon, an RF-heater is used to remove trace amounts of impuritiesfrom the silicon. If the silicon has the impurity of 10^14 Co (k = 8*10^-6) what is the purityof the crystal after one pass of the zone refiner? After two passes? Plot concentration as afunction of crystal length from 0 to 8ft (total length of the crystal). The width of the moltenzone is 5”.arrow_forwardNot use ai pleasearrow_forwardSolve on paper not using AI or chatgptarrow_forward
- Electricity for Refrigeration, Heating, and Air C...Mechanical EngineeringISBN:9781337399128Author:Russell E. SmithPublisher:Cengage LearningDelmar's Standard Textbook Of ElectricityElectrical EngineeringISBN:9781337900348Author:Stephen L. HermanPublisher:Cengage Learning
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