Create the ERD. (Hint: Look at the table contents. You will discover that an AIRCRAFT can fly many CHARTER trips but that each CHARTER trip is flown by one AIRCRAFT, that a MODEL references many AIRCRAFT but that each AIRCRAFT references a single MODEL, and so on.)

Primary Key:
A Primary Key in a database table is a field in the table that uniquely identifies every row or record present in the database table.
Example:
Students in Universities are assigned a unique registration number.
Therefore, in a STUDENT database table, the attribute “reg_no” acts as primary key.
Foreign Key:
Foreign Key is a column in a relational database table which provides a relation between two tables. It provides a cross reference between tables by pointing to primary key of another table.
Example:
In STUDENT database table, the attribute “reg_no” acts as primary key and in COURSE database table in which the student selects his or her course, the same “reg_no” acts as foreign key for the STUDENT table.
Many to One Relationship:
When more than one record in a database table is associated with only one record in another table, the relationship between the two tables is referred as many to one relationship. It is also represented as M: 1 relationship.
One to Many Relationship:
When one record in a database table is associated with more than one record in another table, the relationship between the two tables is referred as one to many relationship. It is also represented as1: M relationship. This is the opposite of many to one relationship.
One to One Relationship:
When one record in a database table is associated with one record in another table, the relationship between the two tables is referred as one to one relationship. It is also represented as1: 1relationship.
CROW FOOT ERD:
The Crow Foot ERD is an Entity Relationship Diagram which is used to represent the cardinalities present in the basic ER diagram. It is used to represent the relationships present between two tuples or tables present in the database.
Explanation of Solution
Given database tables:
Table Name: CHARTER
CHAR_TRIP | CHAR_DATE | CHAR_PILOT | CHAR_COPILOT | AC_NUMBER | CHAR_DESTINATION | CHAR_DISTANCE | CHAR_HOURS_FLOWN | CHA_HOURS_WAIT | CHAR_FUEL_GALLONS | CHAR_OIL_QTS | CUS_CODE |
10001 | 05-Feb-18 | 104 | 2289L | ATL | 936.0 | 5.1 | 2.2 | 354.1 | 1 | 10011 | |
10002 | 05-Feb-18 | 101 | 2778V | BNA | 320.0 | 1.6 | 0.0 | 72.6 | 0 | 10016 | |
10003 | 05-Feb-18 | 105 | 109 | 4278Y | GNV | 1574.0 | 7.8 | 0.0 | 339.8 | 2 | 10014 |
10004 | 06-Feb-18 | 106 | 1484P | STL | 472.0 | 2.9 | 4.9 | 97.2 | 1 | 10019 | |
10005 | 06-Feb-18 | 101 | 2289L | ATL | 1023.0 | 5.7 | 3.5 | 397.7 | 2 | 10011 | |
10006 | 06-Feb-18 | 109 | 4278Y | STL | 472.0 | 2.6 | 5.2 | 117.1 | 0 | 10017 | |
10007 | 06-Feb-18 | 104 | 105 | 2778V | GNV | 1574.0 | 7.9 | 0.0 | 348.4 | 2 | 10012 |
10008 | 07-Feb-18 | 106 | 1484P | TYS | 644.0 | 4.1 | 0.0 | 140.6 | 1 | 10014 | |
10009 | 07-Feb-18 | 105 | 2289L | GNV | 1574.0 | 6.6 | 23.4 | 459.9 | 0 | 10017 | |
10010 | 07-Feb-18 | 109 | 4278Y | ATL | 998.0 | 6.2 | 3.2 | 279.7 | 0 | 10016 | |
10011 | 07-Feb-18 | 101 | 104 | 1484P | BNA | 352.0 | 1.9 | 5.3 | 66.4 | 1 | 10012 |
10012 | 08-Feb-18 | 101 | 2289L | MOB | 884.0 | 4.8 | 4.2 | 215.1 | 0 | 10010 | |
10013 | 08-Feb-18 | 105 | 4278Y | TYS | 644.0 | 3.9 | 4.5 | 174.3 | 1 | 10011 | |
10014 | 09-Feb-18 | 106 | 4278V | ATL | 936.0 | 6.1 | 2.1 | 302.6 | 0 | 10017 | |
10015 | 09-Feb-18 | 104 | 101 | 2289L | GNV | 1645.0 | 6.7 | 0.0 | 459.5 | 2 | 10016 |
10016 | 09-Feb-18 | 109 | 105 | 2778V | MQY | 312.0 | 1.5 | 0.0 | 67.2 | 0 | 10011 |
10017 | 10-Feb-18 | 101 | 1484P | STL | 508.0 | 3.1 | 0.0 | 105.5 | 0 | 10014 | |
10018 | 10-Feb-18 | 105 | 104 | 4278Y | TYS | 644.0 | 3.8 | 4.5 | 167.4 | 0 | 10017 |
Table Name: AIRCRAFT
AC_NUMBER | MODE-CODE | AC_TTAF | AC_TTEL | AC_TTER |
1484P | PA23-250 | 1833.1 | 1833.1 | 101.8 |
2289L | C-90A | 4243.8 | 768.9 | 1123.4 |
2778V | PA31-350 | 7992.9 | 1513.1 | 789.5 |
4278Y | PA31-350 | 2147.3 | 622.1 | 243.2 |
Table Name: MODEL
MOD_CODE | MOD_MANUFACTER | MOD_NAME | MOD_SEATS | MOD_CHG_MILE |
B200 | Beechcraft | Super KingAir | 10 | 1.93 |
C-90A | Beechcraft | KingAir | 8 | 2.67 |
PA23-250 | Piper | Aztec | 6 | 1.93 |
PA31-350 | Piper | Navajao Chiettan | 10 | 2.35 |
Table Name: PILOT
EMP_NUM | PIL_LICENSE | PIL_RATINGS | PIL_MED_TYPE | PIL_MED_DATE | PIL_PTI35_DATE |
101 | ATP | ATP/SEL/MEL/Instr/CFII | 1 | 20-Jan-18 | 11-Jan-18 |
104 | ATP | ATP/SEL/MEL/Instr | 1 | 18-Dec-17 | 17-Jan-18 |
105 | COM | COMM/SEL/MEL/Instr/CFI | 2 | 05-Jan-18 | 02-Jan-18 |
106 | COM | COMM/SEL/MEL/Instr | 2 | 10-Dec-17 | 02-Feb-18 |
109 | COM | ATP/SEL/MEL/SES/Instr/CFII | 1 | 22-Jan-18 | 15-Jan-18 |
Table Name: EMPLOYEE
EMP_NUM | EMP_TITLE | EMP-LNAME | EMP_FNAME | EMP_INITIAL | EMP_CODE | EMP_HIRE_DATE |
100 | Mr. | Kolrnycz | George | D | 15-Jun-62 | 15-Mar-08 |
101 | Ms. | Lewis | Rhonda | G | 19-Mar-85 | 25-Apr-06 |
102 | Mr. | Vandam | Rhett | 14-Nov-78 | 18-May-13 | |
103 | Ms. | Jones | Anne | M | 11-May-94 | 26-Jul-17 |
104 | Mr. | Lange | John | P | 12-Jul-91 | 20-Aug-10 |
105 | Mr. | Williams | Robert | D | 14-Mar-95 | 19-Jun-17 |
106 | Mrs. | Duzak | Jeanine | K | 12-Feb-88 | 13-Mar-18 |
107 | Mr. | Deante | George | D | 01-May-95 | 02-Jul-16 |
108 | Mr. | Wiesanbach | Paul | R | 14-Feb-86 | 03-Jun-13 |
109 | Ms. | Travis | Elizabeth | K | 18-Jun-81 | 14-Feb-16 |
110 | Mrs. | Genkazi | Lieghla | W | 19-May-90 | 29-Jun-10 |
Table Name: EMPLOYEE
CUS_CODE | CUS_LNAME | CUS_FNAME | CUS_INITIAL | CUS_AREACODE | CUS_PHONE | CUS_BALANCE |
10010 | Ramas | Alfred | A | 615 | 844-2573 | 0.00 |
10011 | Dunne | Leona | K | 713 | 894-1293 | 0.00 |
10012 | Smith | Kathy | W | 615 | 894-2285 | 896.54 |
10013 | Owolski | Paul | F | 615 | 894-2180 | 1285.19 |
10014 | Orlando | Myron | 615 | 222-1672 | 673.21 | |
10015 | OBrian | Amy | B | 713 | 442-3381 | 1014.86 |
10016 | Brown | James | G | 615 | 297-1228 | 0.00 |
10017 | Williams | George | 615 | 290-2556 | 0.00 | |
10018 | Fariss | Anne | G | 713 | 382-7185 | 0.00 |
10019 | Smith | Olette | K | 615 | 297-3809 | 453.98 |
PRIMARY KEY in the above tables:
For Table Name: CHARTER:
Primary Key: CHAR_TRIP
“CHAR_TRIP” acts as primary key of the table because the attribute “CHAR_TRIP” is a unique ID that is assigned to every individual trip by the charter plane. It also uniquely identifies every other row present in the database table.
For Table Name: AIRCRAFT:
Primary Key: AC_NUMBER
“AC_NUMBER” acts as primary key of the table because the attribute “AC_NUMBER” is a unique number that is assigned to every individual charter plane and is used to distinguish among them. It also uniquely identifies every other row present in the database table.
For Table Name: MODEL:
Primary Key: MOD_CODE
“MOD_CODE” acts as primary key of the table because the attribute “MOC_CODE” is a unique number that is assigned to every individual model of the charter plane and is used to distinguish models among them. It also uniquely identifies every other row present in the database table.
For Table Name: PILOT:
Primary Key: EMP_NUM
“EMP_NUM” acts as primary key of the table because the attribute “EMP_NUM” is a unique number that is assigned to every pilot that flies an aircraft. It also uniquely identifies every other row present in the database table.
For Table Name: EMPLOYEE:
Primary Key: EMP_NUM
“EMP_NUM” acts as primary key of the table because the attribute “EMP_NUM” is a unique number or ID that is assigned to every employee that works in the airline. It also uniquely identifies every other row present in the database table.
For Table Name: CUSTOMER:
Primary Key: CUS_CODE
“CUS_CODE” acts as primary key of the table because the attribute “CUS_CODE” is a unique code that is assigned to every customer that books a flight with the airline. It also uniquely identifies every other row present in the database table.
FOREIGN KEY in the above tables:
For Table Name: CHARTER:
Primary Key: CHAR_PILOT,CHAR_COPILOT,AC_NUMBER,CUS_CODE
“CHAR_PILOT” acts as foreign key of the table because the attribute “CHAR_PILOT” is also present in the table PILOT and it references PILOT and hence it forms a link between the two tables.
“CHAR_COPILOT” acts as foreign key of the table because the attribute “CHAR_COPILOT” is also present in the table PILOT and it references PILOT and hence it forms a link between the two tables.
“AC_NUMBER” acts as foreign key of the table because the attribute “AC_NUMBER” is also present in the table AIRCRAFT and it references AIRCRAFT and hence it forms a link between the two tables.
“CUS_CODE” acts as foreign key of the table because the attribute “CUS_CODE” is also present in the table CUSTOMER and it references CUSTOMER and hence it forms a link between the two tables.
For Table Name: AIRCRAFT:
Foreign Key: MOD_CODE
“MOD_CODE” acts as foreign key of the table because the attribute “MOD_CODE” is also present in the table MODEL and it references MODEL and hence it forms a link between the two tables.
“For Table Name: MODEL:
Foreign Key: None
There is no Foreign Key attribute present in the table because there is no attribute in the table except the primary key which is present in any other database table.
For Table Name: PILOT:
Primary Key: EMP_NUM
“EMP_NUM” acts as foreign key of the table because the attribute “EMP_NUM” is also present in the table EMPLOYEE and it references EMPLOYEE and hence it forms a link between the two tables.
For Table Name: EMPLOYEE:
Foreign Key: None
There is no Foreign Key attribute present in the table because there is no attribute in the table except the primary key which is present in any other database table.
For Table Name: CUSTOMER:
Foreign Key: None
There is no Foreign Key attribute present in the table because there is no attribute in the table except the primary key which is present in any other database table.
Relationship among the tables:
A CUSTOMER requests many CHARTER trips and more than one CHARTER trip can be requested by a single customer. Hence, the relationship between CUSTOMER and CHARTER is one to many or 1: M.
An AIRCRAFT can fly many CHARTER trips but that each CHARTER trip is flown by one AIRCRAFT. Hence, the relationship between AIRCRAFT and CHARTER is one to many or 1: M.
Each AIRCRAFT references a single MODEL but a MODEL references many AIRCRAFT. Hence, the relationship between AIRCRAFT and MODEL is many to one or M: 1.
Many CHARTER trips are flown by a single PILOT and with a single COPILOT but a PILOT can fly only one charter trip at a time. Hence, the relationship between CHARTER and PILOT is many to one or M: 1.
All PILOTS are EMPLOYEES, but not all EMPLOYEES are PILOTS – some are mechanics, accountants, and so on.
There is an optional (default) 1:1 relationship between EMPLOYEE and PILOT. It can be represented that EMPLOYEE is the “parent” of PILOT.
CROW FOOT diagram to represent relationship between CHARTER, MODEL, AIRCRAFT, PILOT, EMPLOYEE and CUSTOMER:
The CROW FOOT diagram to represent relationship between CHARTER, MODEL, AIRCRAFT, PILOT, EMPLOYEE and CUSTOMER is shown below:
The above diagram represents the one to many relationship between CUSTOMER and CHARTER, one to many relationship between AIRCRAFT and CHARTER, many to one relationship between AIRCRAFT and MODEL, many to one relation between CHARTER and PILOT and an optional one to one relationship between PILOT and EMPLOYEE.
Want to see more full solutions like this?
Chapter 3 Solutions
Bundle: Database Systems Design, Implementation, & Management, Loose-leaf Version, 13th + MindTapV2.0, 1 term Printed Access Card
- My daughter is a Girl Scout and it is time for our cookie sales. There are 15 neighbors nearby and she plans to visit every neighbor this evening. There is a 40% likelihood that someone will be home. If someone is home, there is an 85% likelihood that person will make a purchase. If a purchase is made, the revenue generated from the sale follows the Normal distribution with mean $18 and standard deviation $5. Using @RISK, simulate our door-to-door sales using at least 1000 iterations and report the expected revenue, the maximum revenue, and the average number of purchasers. What is the probability that the revenue will be greater than $120?arrow_forwardQ4 For the network of Fig. 1.41: a- Determine re b- Find Aymid =VolVi =Vo/Vi c- Calculate Zi. d- Find Ay smid e-Determine fL, JLC, and fLE f-Determine the low cutoff frequency. g- Sketch the asymptotes of the Bode plot defined by the cutoff frequencies of part (e). h-Sketch the low-frequency response for the amplifier using the results of part (f). Ans: 28.48 2, -72.91, 2.455 KS2, -54.68, 103.4 Hz. 38.05 Hz. 235.79 Hz. 235.79 Hz. 14V 15.6ΚΩ 68kQ 0.47µF Vo 0.82 ΚΩ V₁ B-120 3.3kQ 0.47µF 10kQ 1.2k0 =20µF Z₁ Fig. 1.41 Circuit forarrow_forwarda. [10 pts] Write a Boolean equation in sum-of-products canonical form for the truth table shown below: A B C Y 0 0 0 1 0 0 1 0 0 1 0 0 0 1 1 0 1 0 0 1 1 0 1 0 1 1 1 1 0 1 1 0 a. [10 pts] Minimize the Boolean equation you obtained in (a). b. [10 pts] Implement, using Logisim, the simplified logic circuit. Include an image of the circuit in your report.arrow_forward
- Using XML, design a simple user interface for a fictional app. Your UI should include at least three different UI components (e.g., TextView, Button, EditText). Explain the purpose of each component in your design-you need to add screenshots of your work with your name as part of the code to appear on the interface-. Screenshot is needed.arrow_forwardQ4) A thin ring of radius 5 cm is placed on plane z = 1 cm so that its center is at (0,0,1 cm). If the ring carries 50 mA along a^, find H at (0,0,a).arrow_forward4. [15 pts] A logic function F of four variables a; b; c; d is described by the following K-map. Derive the fully minimized SOP logic expression form of F. cd ab 00 01 11 10 00 0 0 0 1 01 1 0 0 1 11 1 0 1 1 10 0 0 1 1arrow_forward
- 2. [20 pts] Student A B will enjoy his picnic on sunny days that have no ants. He will also enjoy his picnic any day he sees a hummingbird, as well as on days where there are ants and ladybugs. a. Write a Boolean equation for his enjoyment (E) in terms of sun (S), ants (A), hummingbirds (H), and ladybugs (L). b. Implement in Logisim, the logic circuit of E function. Use the Circuit Analysis tool in Logisim to view the expression, include an image of the expression generated by Logisimarrow_forwardHow would I go about creating this computer database in MariaDB with sql? Create a database name "dbXXXXXX" Select the database using the "use [database name]" command. Now you are in the database. Based on the above schema from Enrolment System database, create all the tables with the last 6 digits of "123456", then the table name for table Lecturer should be "123456_Lecturer". Refer to basic SQL lecture note to create table that has primary keys and Foreign Keys. Provide the datatype of each attributes. Add a column called "Department" with datatype "VARCHAR(12)" to the table "Lecturer". Shows the metadata of the updated "Lecturer" table. (Use Describe command) Drop the "Department" column from the table "Lecturer", and show the metadata of the updated "Lecturer" table. Insert three (3) data to each of the table in the tables created. Note: If you have foreign key issues, please disable foreign key constraints before inserting the data, see below SET FOREIGN_KEY_CHECKS=0;…arrow_forwardCSE330 Discrete Mathematics 1. In the classes, we discussed three forms of floating number representations as given below, (1) Standard/General Form, (2) Normalized Form, (3) Denormalized Form. 3. Consider the real number x = (3.395) 10 (a) (b) Convert the decimal number x into binary format up to 7 binary places (7 binary digits after decimal) Convert the calculated value into denormalized form and calculate fl(x) for m=4 Don't use any Al tool show answer in pen a nd paper then take pi ctures and sendarrow_forward
- Simplify the following expressions by means of a four-variable K-Map. AD+BD+ BC + ABDarrow_forwardCSE330 Discrete Mathematics 1. In the classes, we discussed three forms of floating number representations as given below, (1) Standard/General Form, (2) Normalized Form, (3) Denormalized Form. 2. Let ẞ 2, m = 6, emin = -3 and emax = 3. Answer the following questions: Compute the minimum of |x| for General and Normalized form (a) Compute the Machine Epsilon value for the General and Denormalized form. If we change the value of emax to 6 then how will it affect the value of maximum scale invariant error for the case of Normalized form? Explain your answer. show answer in pen a Don't use any Al tool nd paper then take pi ctures and sendarrow_forwardCSE330: Discrete Mathematics 1. In the classes, we discussed three forms of floating number representations as given below, (1) Standard/General Form, (2) Normalized Form, (3) Denormalized Form. Now, let's take, ẞ = 2, m = 3, emin = -2 and emax = 3. Based on these, answer the following: (a) (b) (c) (d) What are the maximum/largest numbers that can be stored in the system by these three forms defined above? (express your answer in decimal values) What are the non-negative minimum/smallest numbers that can be stored in the system by the denormalized form? (express your answer in decimal values) How many numbers (both non-negative and negative) can be represented in the above mentioned system using the general form? Explain your answer. Find all the decimal numbers for e = 3 and e = 2 in denormalized form, plot them on a real line and prove that all the numbers are not equally spaced. Write the equally spaced sets for the number line you drew. show your answer in Don't use any Al tool pen…arrow_forward
- COMPREHENSIVE MICROSOFT OFFICE 365 EXCEComputer ScienceISBN:9780357392676Author:FREUND, StevenPublisher:CENGAGE LNp Ms Office 365/Excel 2016 I NtermedComputer ScienceISBN:9781337508841Author:CareyPublisher:Cengage
- A Guide to SQLComputer ScienceISBN:9781111527273Author:Philip J. PrattPublisher:Course Technology PtrProgramming with Microsoft Visual Basic 2017Computer ScienceISBN:9781337102124Author:Diane ZakPublisher:Cengage LearningNew Perspectives on HTML5, CSS3, and JavaScriptComputer ScienceISBN:9781305503922Author:Patrick M. CareyPublisher:Cengage Learning


