Concept explainers
Does the following sequence produce a division by zero?
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C Programming Language
- #include int k=0; int f(int t) { k += t; heturn k; } void main() { int i, result=1; for(i = 1;i <= 3;i++) result = f(i); printf("%d\n", result); } A 3 B C) 1 D 123arrow_forwardI need help with this problem. Please help me, because I do not understand. if 14 > 7: print("Greater than 14") x = 2 print(x * 7) else: print("Less than") print(7)arrow_forward#include <stdio.h>int main(){int i, j, k=0;for (i=1; i<3; i++){for (j=1; j<3; j++){k = i+j;printf("Value of k is %d\n" ,k);}}printf("Value of k is %d\n",2*k);return 0;} how do you modify this code so k only prints even numbersarrow_forward
- What is the final value of x when the following code is run? int x;for(x =1; x<20; x+=2) {}arrow_forwardQuestion #4: Re-write the program of Question #3 using data files. The input data numbers.txt contains (positive) integer numbers. Each time the program reads a number, check whether it is a prime and stores the result in the output file Results.txt. 373 373 is Prime!! 11 11 is Prime!! 2552 is NOT prime!! 5 is Prime!! 3561 is NOT prime!! 2552 3561 numbers.txt Results.txtarrow_forwardWhat the output forthe code fragments? int i = 7; do{ i = i/2; System.out.println(i); } while (i >0);arrow_forward
- 8. Given this code: //This a code to determine the root of a function //The function is (cosx+2)/3 #include #include float root(float); int main() { float a[100],b[100],c=100.0; int i=1,j=0; b[0]=(cos(0)-3*0+1); printf("\nEnter a beginning guess:\n"); scanf ("%f",&a[0]); while(c>0.00001) { a[j+1]=root(a[j]); c=a[j+1]-a[j]; c=fabs(c); //fabs = Absolute Value of Floating-Point Number j++; } printf("\n The root of the given function is %f",a[j]); } float root(float x) {arrow_forwardCode in python: A certain company has encoded the accounts of its customers and requires that you provide an algorithm that, given an account code, informs if it is valid according to the following description: The account codes are made up of 4 digits counted from right to left, plus the verification digit. The verifying digit is obtained by adding the digits of the account number of the even positions and multiplying the digits of the odd positions, from the new result the residue of the division is extracted for 10, which represents the verifying digit. Develop the code in python as a check digit class that returns 1 if it is correct or 0 if not Heading: Extract digits, verifier calculation, Account verification, Integral algorithmarrow_forwardd) What will be the value of func(2,5,4). int func(int x, int y, int z){ return pow(x,y)/z; }arrow_forward
- #include <stdio.h> int main(){ int arr[10]; int i; for (i=0; i<10; i++){ arr[i] = i; } for (i=0; i<10; i++){ printf("arr[%d] = %d\n", i, arr[i]); } return 0;} Copy the code and modify it as follows: Add another separate array of 10 integers. The following code parts are to be added (in the same order as specified) after the printing of the values of the first array:(1) Copy the content of the first array to the second array. Add 10 to each of the values of the second array. Make use of a single loop to achieve this part.(2) Print each element of the second array. Make use of another loop for this partarrow_forward#include double f(double x) { return 4 * exp(-x); } double trapezoidalRule(double a, double b, int N) { double h = (b - a) / N; double sum = 0.5 * (f(a) + f(b)); for (int i = 1; i < N; i++) { sum += f(a + i * h); } return h * sum; } int main() { double a = 0.0; // lower limit double b = 1.0; // upper limit int N = 5; // number of trapezoids double integral = trapezoidalRule(a, b, N); std::cout << "The estimate of the integral of f(x) = 4e^-x between " << a << " and " << b << " using " << N << " trapezoids is: " << integral << std::endl; return 0; } Please write down the explanation, step by step for this trapezoidal rule program, Emphasize on this part:for (int i = 1; i < N; i++) { sum += f(a + i * h); }arrow_forwardQ1:Find the output of the following code:arrow_forward
- C++ for Engineers and ScientistsComputer ScienceISBN:9781133187844Author:Bronson, Gary J.Publisher:Course Technology Ptr