Refer the university schema from the textbook for the following subparts.

Question

Want to see more full solutions like this?

Answer 1

Question

Chapter 3, Problem 1PE

a.

Program Plan Intro

Refer the university schema from the textbook for the following subparts.

a.

Expert Solution

Explanation of Solution

Query:

Select title from where dept_name= ‘Comp.Sci’ and credits=3

Explanation:

In the above query, “Select”, “from”, and “where” are the keywords in Structured Query Language (SQL).
This query selects the title of courses where department matches with “Comp.Sci” department and credits is equal to “3”.

b.

Explanation of Solution

Query:

Select distinct student.ID from (student join takes using (ID)) join (instructor join teaches using(ID)) using(course_id,sec_id,semester,year) where instructor.name= ‘Einstein’

Explanation:

In the above query, “Select”, “distinct”, “from”, “join”, “using” and “where” are the keywords in Structured Query Language (SQL).

In this query, the join operation is performed between student and instructor table using the ID’s.

Then it retrieves the fields such as course id, section id, semester and year of the student. In that fields, select the distinct student ID taught by the instructor name “Einstein”.

c.

Explanation of Solution

Query:

Select max(salary) from instructor

Explanation:

In the above query, “Select”, “from”, and “max” are the keywords in Structured Query Language (SQL).

This query selects the maximum salary of the instructor from instructor table.

d.

Explanation of Solution

Query:

Select ID,name from instructor where salary=(select max(salary) from instructor)

Explanation:

In the above query, “Select”, “from”, and “where” are the keywords in Structured Query Language (SQL).

This query selects the ID and name from the instructor table where salary is equal to maximum salary from the instructor table.

e.

Explanation of Solution

Query:

Select course_id,sec_id,count(ID) from section natural join takes where semester= ‘Fall’ and year=2017 group by course_id, sec_id

Explanation:

In the above query, “Select”, “from”, “natural join”, “group by” and “where” are the keywords in Structured Query Language (SQL).

This query selects the course id, section id and count of enrollment of each section where semester is “Fall” season and year is “2017”.

f.

Explanation of Solution

Query:

Select max(enrollment) from (select count(ID) as enrollment from section natural join takes where semester= ‘Fall’ and year=2017 group by course_id, sec_id)

Explanation:

In the above query, “Select”, “from”, “natural join”, “group by” and “where” are the keywords in Structured Query Language (SQL).

This query selects the number of IDs from enrolment sections where semester is “Fall” season and year is “2017”.

After selecting number of IDs, select the maximum enrollment from all section.

g.

Explanation of Solution

Query:

With sec_enrollment as (select course_id,sec_id,count(ID) from section natural join takes where semester= ‘Fall’ and year=2017 group by course_id, sec_id)

Select course_id,sec_id from sec_enrollment where enrollment=(select max(enrollment) from sec_enrollment)

Explanation:

In the above query, “Select”, “from”, “natural join”, “group by” and “where” are the keywords in Structured Query Language (SQL).

This first inner query selects the number of IDs from enrolment sections where semester is “Fall” season and year is “2017”.

After selecting number of IDs, select the maximum enrollment from all section.

It is stored in temporary view as “sec_enrollment”.

Next the second inner query selects the maximum enrollment from “sec_enrollment” which displays the section id, course id from the table.

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Students have asked these similar questions

When the given integer variable numberOfPackages is: greater than 12, output "Needs more than one box". between 5 inclusive and 12 inclusive, output "Large box". between 0 exclusive and 4 inclusive, output "Small box". less than or equal to 0, output "Invalid input". End with a newline.

summarize in a short paragraph how to Advance Incident Response and Automation in ML home based security systems

1.[30 pts] Computers generate color pictures on a video screen or liquid crystal display by mixing three different colors of light: red, green, and blue. Imagine a simple scheme, with three different lights, each of which can be turned on or off, projecting onto a glass screen: We can create eight different colors based on the absence (0) or presence (1) of light sources R,G and B: R G B Color 0 0 0 Black 0 0 1 Blue 0 1 0 Green 0 1 1 Cyan 1 0 0 Red 1 0 1 Magenta 1 1 1 0 Yellow 1 White 1 Each of these colors can be represented as a bit vector of length 3, and we can apply Boolean operations to them. a. The complement of a color is formed by turning off the lights that are on and turning on the lights that are off. What would be the complement of each of the eight colors listed above? b. Describe the effect of applying Boolean operations on the following colors: Λ 1. Red(100) ^ Magenta(101)= Blue(001) 2. Bue(001) | Green(010)= 3. Yellow(100) & Cyan(011)= 2.[30 pts] Perform the following…

Answer 2

Question

Chapter 3, Problem 1PE

a.

Program Plan Intro

Refer the university schema from the textbook for the following subparts.

a.

Expert Solution

Explanation of Solution

Query:

Select title from where dept_name= ‘Comp.Sci’ and credits=3

Explanation:

In the above query, “Select”, “from”, and “where” are the keywords in Structured Query Language (SQL).
This query selects the title of courses where department matches with “Comp.Sci” department and credits is equal to “3”.

b.

Explanation of Solution

Query:

Select distinct student.ID from (student join takes using (ID)) join (instructor join teaches using(ID)) using(course_id,sec_id,semester,year) where instructor.name= ‘Einstein’

Explanation:

In the above query, “Select”, “distinct”, “from”, “join”, “using” and “where” are the keywords in Structured Query Language (SQL).

In this query, the join operation is performed between student and instructor table using the ID’s.

Then it retrieves the fields such as course id, section id, semester and year of the student. In that fields, select the distinct student ID taught by the instructor name “Einstein”.

c.

Explanation of Solution

Query:

Select max(salary) from instructor

Explanation:

In the above query, “Select”, “from”, and “max” are the keywords in Structured Query Language (SQL).

This query selects the maximum salary of the instructor from instructor table.

d.

Explanation of Solution

Query:

Select ID,name from instructor where salary=(select max(salary) from instructor)

Explanation:

In the above query, “Select”, “from”, and “where” are the keywords in Structured Query Language (SQL).

This query selects the ID and name from the instructor table where salary is equal to maximum salary from the instructor table.

e.

Explanation of Solution

Query:

Select course_id,sec_id,count(ID) from section natural join takes where semester= ‘Fall’ and year=2017 group by course_id, sec_id

Explanation:

In the above query, “Select”, “from”, “natural join”, “group by” and “where” are the keywords in Structured Query Language (SQL).

This query selects the course id, section id and count of enrollment of each section where semester is “Fall” season and year is “2017”.

f.

Explanation of Solution

Query:

Select max(enrollment) from (select count(ID) as enrollment from section natural join takes where semester= ‘Fall’ and year=2017 group by course_id, sec_id)

Explanation:

In the above query, “Select”, “from”, “natural join”, “group by” and “where” are the keywords in Structured Query Language (SQL).

This query selects the number of IDs from enrolment sections where semester is “Fall” season and year is “2017”.

After selecting number of IDs, select the maximum enrollment from all section.

g.

Explanation of Solution

Query:

With sec_enrollment as (select course_id,sec_id,count(ID) from section natural join takes where semester= ‘Fall’ and year=2017 group by course_id, sec_id)

Select course_id,sec_id from sec_enrollment where enrollment=(select max(enrollment) from sec_enrollment)

Explanation:

In the above query, “Select”, “from”, “natural join”, “group by” and “where” are the keywords in Structured Query Language (SQL).

This first inner query selects the number of IDs from enrolment sections where semester is “Fall” season and year is “2017”.

After selecting number of IDs, select the maximum enrollment from all section.

It is stored in temporary view as “sec_enrollment”.

Next the second inner query selects the maximum enrollment from “sec_enrollment” which displays the section id, course id from the table.

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Answer 3

Question

Chapter 3, Problem 1PE

a.

Program Plan Intro

Refer the university schema from the textbook for the following subparts.

a.

Expert Solution

Explanation of Solution

Query:

Select title from where dept_name= ‘Comp.Sci’ and credits=3

Explanation:

In the above query, “Select”, “from”, and “where” are the keywords in Structured Query Language (SQL).
This query selects the title of courses where department matches with “Comp.Sci” department and credits is equal to “3”.

b.

Explanation of Solution

Query:

Select distinct student.ID from (student join takes using (ID)) join (instructor join teaches using(ID)) using(course_id,sec_id,semester,year) where instructor.name= ‘Einstein’

Explanation:

In the above query, “Select”, “distinct”, “from”, “join”, “using” and “where” are the keywords in Structured Query Language (SQL).

In this query, the join operation is performed between student and instructor table using the ID’s.

Then it retrieves the fields such as course id, section id, semester and year of the student. In that fields, select the distinct student ID taught by the instructor name “Einstein”.

c.

Explanation of Solution

Query:

Select max(salary) from instructor

Explanation:

In the above query, “Select”, “from”, and “max” are the keywords in Structured Query Language (SQL).

This query selects the maximum salary of the instructor from instructor table.

d.

Explanation of Solution

Query:

Select ID,name from instructor where salary=(select max(salary) from instructor)

Explanation:

In the above query, “Select”, “from”, and “where” are the keywords in Structured Query Language (SQL).

This query selects the ID and name from the instructor table where salary is equal to maximum salary from the instructor table.

e.

Explanation of Solution

Query:

Select course_id,sec_id,count(ID) from section natural join takes where semester= ‘Fall’ and year=2017 group by course_id, sec_id

Explanation:

In the above query, “Select”, “from”, “natural join”, “group by” and “where” are the keywords in Structured Query Language (SQL).

This query selects the course id, section id and count of enrollment of each section where semester is “Fall” season and year is “2017”.

f.

Explanation of Solution

Query:

Select max(enrollment) from (select count(ID) as enrollment from section natural join takes where semester= ‘Fall’ and year=2017 group by course_id, sec_id)

Explanation:

In the above query, “Select”, “from”, “natural join”, “group by” and “where” are the keywords in Structured Query Language (SQL).

This query selects the number of IDs from enrolment sections where semester is “Fall” season and year is “2017”.

After selecting number of IDs, select the maximum enrollment from all section.

g.

Explanation of Solution

Query:

With sec_enrollment as (select course_id,sec_id,count(ID) from section natural join takes where semester= ‘Fall’ and year=2017 group by course_id, sec_id)

Select course_id,sec_id from sec_enrollment where enrollment=(select max(enrollment) from sec_enrollment)

Explanation:

In the above query, “Select”, “from”, “natural join”, “group by” and “where” are the keywords in Structured Query Language (SQL).

This first inner query selects the number of IDs from enrolment sections where semester is “Fall” season and year is “2017”.

After selecting number of IDs, select the maximum enrollment from all section.

It is stored in temporary view as “sec_enrollment”.

Next the second inner query selects the maximum enrollment from “sec_enrollment” which displays the section id, course id from the table.

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Answer 4

Question

Chapter 3, Problem 1PE

a.

Program Plan Intro

Refer the university schema from the textbook for the following subparts.

a.

Expert Solution

Explanation of Solution

Query:

Select title from where dept_name= ‘Comp.Sci’ and credits=3

Explanation:

In the above query, “Select”, “from”, and “where” are the keywords in Structured Query Language (SQL).
This query selects the title of courses where department matches with “Comp.Sci” department and credits is equal to “3”.

b.

Explanation of Solution

Query:

Select distinct student.ID from (student join takes using (ID)) join (instructor join teaches using(ID)) using(course_id,sec_id,semester,year) where instructor.name= ‘Einstein’

Explanation:

In the above query, “Select”, “distinct”, “from”, “join”, “using” and “where” are the keywords in Structured Query Language (SQL).

In this query, the join operation is performed between student and instructor table using the ID’s.

Then it retrieves the fields such as course id, section id, semester and year of the student. In that fields, select the distinct student ID taught by the instructor name “Einstein”.

c.

Explanation of Solution

Query:

Select max(salary) from instructor

Explanation:

In the above query, “Select”, “from”, and “max” are the keywords in Structured Query Language (SQL).

This query selects the maximum salary of the instructor from instructor table.

d.

Explanation of Solution

Query:

Select ID,name from instructor where salary=(select max(salary) from instructor)

Explanation:

In the above query, “Select”, “from”, and “where” are the keywords in Structured Query Language (SQL).

This query selects the ID and name from the instructor table where salary is equal to maximum salary from the instructor table.

e.

Explanation of Solution

Query:

Select course_id,sec_id,count(ID) from section natural join takes where semester= ‘Fall’ and year=2017 group by course_id, sec_id

Explanation:

In the above query, “Select”, “from”, “natural join”, “group by” and “where” are the keywords in Structured Query Language (SQL).

This query selects the course id, section id and count of enrollment of each section where semester is “Fall” season and year is “2017”.

f.

Explanation of Solution

Query:

Select max(enrollment) from (select count(ID) as enrollment from section natural join takes where semester= ‘Fall’ and year=2017 group by course_id, sec_id)

Explanation:

In the above query, “Select”, “from”, “natural join”, “group by” and “where” are the keywords in Structured Query Language (SQL).

This query selects the number of IDs from enrolment sections where semester is “Fall” season and year is “2017”.

After selecting number of IDs, select the maximum enrollment from all section.

g.

Explanation of Solution

Query:

With sec_enrollment as (select course_id,sec_id,count(ID) from section natural join takes where semester= ‘Fall’ and year=2017 group by course_id, sec_id)

Select course_id,sec_id from sec_enrollment where enrollment=(select max(enrollment) from sec_enrollment)

Explanation:

In the above query, “Select”, “from”, “natural join”, “group by” and “where” are the keywords in Structured Query Language (SQL).

This first inner query selects the number of IDs from enrolment sections where semester is “Fall” season and year is “2017”.

After selecting number of IDs, select the maximum enrollment from all section.

It is stored in temporary view as “sec_enrollment”.

Next the second inner query selects the maximum enrollment from “sec_enrollment” which displays the section id, course id from the table.

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Answer 5

Chapter 3, Problem 1PE

a.

Program Plan Intro

Refer the university schema from the textbook for the following subparts.

a.

Expert Solution

Explanation of Solution

Query:

Select title from where dept_name= ‘Comp.Sci’ and credits=3

Explanation:

In the above query, “Select”, “from”, and “where” are the keywords in Structured Query Language (SQL).
This query selects the title of courses where department matches with “Comp.Sci” department and credits is equal to “3”.

b.

Explanation of Solution

Query:

Select distinct student.ID from (student join takes using (ID)) join (instructor join teaches using(ID)) using(course_id,sec_id,semester,year) where instructor.name= ‘Einstein’

Explanation:

In the above query, “Select”, “distinct”, “from”, “join”, “using” and “where” are the keywords in Structured Query Language (SQL).

In this query, the join operation is performed between student and instructor table using the ID’s.

Then it retrieves the fields such as course id, section id, semester and year of the student. In that fields, select the distinct student ID taught by the instructor name “Einstein”.

c.

Explanation of Solution

Query:

Select max(salary) from instructor

Explanation:

In the above query, “Select”, “from”, and “max” are the keywords in Structured Query Language (SQL).

This query selects the maximum salary of the instructor from instructor table.

d.

Explanation of Solution

Query:

Select ID,name from instructor where salary=(select max(salary) from instructor)

Explanation:

In the above query, “Select”, “from”, and “where” are the keywords in Structured Query Language (SQL).

This query selects the ID and name from the instructor table where salary is equal to maximum salary from the instructor table.

e.

Explanation of Solution

Query:

Select course_id,sec_id,count(ID) from section natural join takes where semester= ‘Fall’ and year=2017 group by course_id, sec_id

Explanation:

In the above query, “Select”, “from”, “natural join”, “group by” and “where” are the keywords in Structured Query Language (SQL).

This query selects the course id, section id and count of enrollment of each section where semester is “Fall” season and year is “2017”.

f.

Explanation of Solution

Query:

Select max(enrollment) from (select count(ID) as enrollment from section natural join takes where semester= ‘Fall’ and year=2017 group by course_id, sec_id)

Explanation:

In the above query, “Select”, “from”, “natural join”, “group by” and “where” are the keywords in Structured Query Language (SQL).

This query selects the number of IDs from enrolment sections where semester is “Fall” season and year is “2017”.

After selecting number of IDs, select the maximum enrollment from all section.

g.

Explanation of Solution

Query:

With sec_enrollment as (select course_id,sec_id,count(ID) from section natural join takes where semester= ‘Fall’ and year=2017 group by course_id, sec_id)

Select course_id,sec_id from sec_enrollment where enrollment=(select max(enrollment) from sec_enrollment)

Explanation:

In the above query, “Select”, “from”, “natural join”, “group by” and “where” are the keywords in Structured Query Language (SQL).

This first inner query selects the number of IDs from enrolment sections where semester is “Fall” season and year is “2017”.

After selecting number of IDs, select the maximum enrollment from all section.

It is stored in temporary view as “sec_enrollment”.

Next the second inner query selects the maximum enrollment from “sec_enrollment” which displays the section id, course id from the table.

Answer 6

Chapter 3, Problem 1PE

a.

Program Plan Intro

Refer the university schema from the textbook for the following subparts.

a.

Expert Solution

Explanation of Solution

Query:

Select title from where dept_name= ‘Comp.Sci’ and credits=3

Explanation:

In the above query, “Select”, “from”, and “where” are the keywords in Structured Query Language (SQL).
This query selects the title of courses where department matches with “Comp.Sci” department and credits is equal to “3”.

Answer 7

Chapter 3, Problem 1PE

a.

Program Plan Intro

Refer the university schema from the textbook for the following subparts.

Answer 8

a.

Expert Solution

Explanation of Solution

Query:

Select title from where dept_name= ‘Comp.Sci’ and credits=3

Explanation:

In the above query, “Select”, “from”, and “where” are the keywords in Structured Query Language (SQL).
This query selects the title of courses where department matches with “Comp.Sci” department and credits is equal to “3”.

Answer 9

a.

Expert Solution

Answer 10

a.

Expert Solution

Answer 11

Expert Solution

Answer 12

b.

Explanation of Solution

Query:

Select distinct student.ID from (student join takes using (ID)) join (instructor join teaches using(ID)) using(course_id,sec_id,semester,year) where instructor.name= ‘Einstein’

Explanation:

In the above query, “Select”, “distinct”, “from”, “join”, “using” and “where” are the keywords in Structured Query Language (SQL).

In this query, the join operation is performed between student and instructor table using the ID’s.

Then it retrieves the fields such as course id, section id, semester and year of the student. In that fields, select the distinct student ID taught by the instructor name “Einstein”.

Answer 13

b.

Explanation of Solution

Query:

Select distinct student.ID from (student join takes using (ID)) join (instructor join teaches using(ID)) using(course_id,sec_id,semester,year) where instructor.name= ‘Einstein’

Explanation:

In the above query, “Select”, “distinct”, “from”, “join”, “using” and “where” are the keywords in Structured Query Language (SQL).

In this query, the join operation is performed between student and instructor table using the ID’s.

Then it retrieves the fields such as course id, section id, semester and year of the student. In that fields, select the distinct student ID taught by the instructor name “Einstein”.

Answer 14

c.

Explanation of Solution

Query:

Select max(salary) from instructor

Explanation:

In the above query, “Select”, “from”, and “max” are the keywords in Structured Query Language (SQL).

This query selects the maximum salary of the instructor from instructor table.

Answer 15

c.

Explanation of Solution

Query:

Select max(salary) from instructor

Explanation:

In the above query, “Select”, “from”, and “max” are the keywords in Structured Query Language (SQL).

This query selects the maximum salary of the instructor from instructor table.

Answer 16

d.

Explanation of Solution

Query:

Select ID,name from instructor where salary=(select max(salary) from instructor)

Explanation:

In the above query, “Select”, “from”, and “where” are the keywords in Structured Query Language (SQL).

This query selects the ID and name from the instructor table where salary is equal to maximum salary from the instructor table.

Answer 17

d.

Explanation of Solution

Query:

Select ID,name from instructor where salary=(select max(salary) from instructor)

Explanation:

In the above query, “Select”, “from”, and “where” are the keywords in Structured Query Language (SQL).

This query selects the ID and name from the instructor table where salary is equal to maximum salary from the instructor table.

Answer 18

e.

Explanation of Solution

Query:

Select course_id,sec_id,count(ID) from section natural join takes where semester= ‘Fall’ and year=2017 group by course_id, sec_id

Explanation:

In the above query, “Select”, “from”, “natural join”, “group by” and “where” are the keywords in Structured Query Language (SQL).

This query selects the course id, section id and count of enrollment of each section where semester is “Fall” season and year is “2017”.

Answer 19

e.

Explanation of Solution

Query:

Select course_id,sec_id,count(ID) from section natural join takes where semester= ‘Fall’ and year=2017 group by course_id, sec_id

Explanation:

In the above query, “Select”, “from”, “natural join”, “group by” and “where” are the keywords in Structured Query Language (SQL).

This query selects the course id, section id and count of enrollment of each section where semester is “Fall” season and year is “2017”.

Answer 20

f.

Explanation of Solution

Query:

Select max(enrollment) from (select count(ID) as enrollment from section natural join takes where semester= ‘Fall’ and year=2017 group by course_id, sec_id)

Explanation:

In the above query, “Select”, “from”, “natural join”, “group by” and “where” are the keywords in Structured Query Language (SQL).

This query selects the number of IDs from enrolment sections where semester is “Fall” season and year is “2017”.

After selecting number of IDs, select the maximum enrollment from all section.

Answer 21

f.

Explanation of Solution

Query:

Select max(enrollment) from (select count(ID) as enrollment from section natural join takes where semester= ‘Fall’ and year=2017 group by course_id, sec_id)

Explanation:

In the above query, “Select”, “from”, “natural join”, “group by” and “where” are the keywords in Structured Query Language (SQL).

This query selects the number of IDs from enrolment sections where semester is “Fall” season and year is “2017”.

After selecting number of IDs, select the maximum enrollment from all section.

Answer 22

g.

Explanation of Solution

Query:

With sec_enrollment as (select course_id,sec_id,count(ID) from section natural join takes where semester= ‘Fall’ and year=2017 group by course_id, sec_id)

Select course_id,sec_id from sec_enrollment where enrollment=(select max(enrollment) from sec_enrollment)

Explanation:

In the above query, “Select”, “from”, “natural join”, “group by” and “where” are the keywords in Structured Query Language (SQL).

This first inner query selects the number of IDs from enrolment sections where semester is “Fall” season and year is “2017”.

After selecting number of IDs, select the maximum enrollment from all section.

It is stored in temporary view as “sec_enrollment”.

Next the second inner query selects the maximum enrollment from “sec_enrollment” which displays the section id, course id from the table.

Answer 23

g.

Explanation of Solution

Query:

With sec_enrollment as (select course_id,sec_id,count(ID) from section natural join takes where semester= ‘Fall’ and year=2017 group by course_id, sec_id)

Select course_id,sec_id from sec_enrollment where enrollment=(select max(enrollment) from sec_enrollment)

Explanation:

In the above query, “Select”, “from”, “natural join”, “group by” and “where” are the keywords in Structured Query Language (SQL).

This first inner query selects the number of IDs from enrolment sections where semester is “Fall” season and year is “2017”.

After selecting number of IDs, select the maximum enrollment from all section.

It is stored in temporary view as “sec_enrollment”.

Next the second inner query selects the maximum enrollment from “sec_enrollment” which displays the section id, course id from the table.

Answer 24

Ch. 3 - Prob. 1PE Ch. 3 - Prob. 2PE Ch. 3 - Prob. 3PE Ch. 3 - Suppose that we have a relation marks(ID, score)...Ch. 3 - Suppose that we have a relation marks(ID, score)...Ch. 3 - The SQL like operator is case sensitive (in most...Ch. 3 - Prob. 7PE Ch. 3 - Prob. 8PE Ch. 3 - Prob. 9PE Ch. 3 - Prob. 10PE

Refer the university schema from the textbook for the following subparts.

Concept explainers

Videos

Refer the university schema from the textbook for the following subparts.

Explanation of Solution

Explanation of Solution

Explanation of Solution

Query:

Select max(salary) from instructor

Explanation:

In the above query, “Select”, “from”, and “max” are the keywords in Structured Query Language (SQL).

This query selects the maximum salary of the instructor from instructor table.

Explanation of Solution

Explanation of Solution

Explanation of Solution

Explanation of Solution

Want to see more full solutions like this?

Chapter 3 Solutions

Refer the university schema from the textbook for the following subparts.

Concept explainers

Videos

Refer the university schema from the textbook for the following subparts.

Explanation of Solution

Explanation of Solution

Explanation of Solution

Query: Select max(salary) from instructor Explanation: In the above query, “Select”, “from”, and “max” are the keywords in Structured Query Language (SQL). This query selects the maximum salary of the instructor from instructor table.

Explanation of Solution

Explanation of Solution

Explanation of Solution

Explanation of Solution

Want to see more full solutions like this?

Chapter 3 Solutions

Query:

Select max(salary) from instructor

Explanation:

In the above query, “Select”, “from”, and “max” are the keywords in Structured Query Language (SQL).

This query selects the maximum salary of the instructor from instructor table.