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Concept explainers
Print number series
- Create a class “PrintNumber”,
- Define the method “printNumbers()” that accepts maximum number as an argument,
- Print the numbers.
- Define the method “main()”,
- Call the method “printNumbers()” with an argument “15”.
- Call the method “printNumbers()” with an argument “5”.
- Define the method “printNumbers()” that accepts maximum number as an argument,
![Check Mark](/static/check-mark.png)
This program demonstrates the method that accepts maximum number as an argument and prints the number from “1” to that given maximum number.
Explanation of Solution
Program:
File name: “PrintNumber.java”
//Create a class
public class PrintNumber
{
//Define the method "printNumbers()"
public static void printNumbers(int number)
{
//Create loop to iterate over given number of times
for (int n = 1; n <= number; n++)
{
//Print the current number
System.out.print("[" + n + "] ");
}
//Print new line
System.out.println();
}
//Define the main() method
public static void main(String[] args)
{
//Print the string
System.out.println("The output for the call printNumbers(15) is: ");
//Call the method with argument "15"
printNumbers(15);
//Print the string
System.out.println("The output for the call printNumbers(5) is: ");
//Call the method with argument "5"
printNumbers(5);
}
}
Output:
The output for the call printNumbers(15) is:
[1] [2] [3] [4] [5] [6] [7] [8] [9] [10] [11] [12] [13] [14] [15]
The output for the call printNumbers(5) is:
[1] [2] [3] [4] [5]
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Chapter 3 Solutions
Building Java Programs: A Back To Basics Approach (5th Edition)
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