Test cases for the algorithm given in “R3.14”:

Test case #1:

Consider the value of “month” is 3 and “day” is 20:

In the above case:

The “if” condition checks whether “month” is equal to 1, 2 or 3.

Here, the value of “month” is “3” and “Winter” is assigned to “season”.

The program will not move to the remaining “else-if” conditions

The “if” condition checks if the “month” is divisible by 3 and the “day” is greater than or equal to 21.

Here, the value of “month” is divisible by 3 and the value of “day” is not greater than or equal to 21.

Here, the value of “month” is “3” and “Winter” is assigned to “season”.

Test case #2:

Consider the value of “month” is 5 and “day” is 25:

In the above case:

The “if” condition checks whether “month” is equal to 1, 2 or 3.

This condition fails.

The “else-if” condition checks whether “month” is equal to 4, 5 or 6.

Here, the value of “month” is “5” and “Spring” is assigned to “season”.

The program will not move to the remaining “else-if” conditions

The “if” condition checks if the “month” is divisible by 3 and the “day” is greater than or equal to 21.

Here, the value of “month” is not divisible by 3 and the value of “day” is greater than 21...

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Chapter 3, Problem 16RE

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