College Physics
10th Edition
ISBN: 9781285737027
Author: Raymond A. Serway, Chris Vuille
Publisher: Cengage Learning
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Chapter 3, Problem 14CQ
A car moving around a circular track, with constant speed (a) has zero acceleration, (b) has an acceleration component in the direction of its velocity, (c) has an acceleration directed away from the center of its path, (d) has an acceleration directed toward the center of its path, or (e) has an acceleration with a direction that cannot be determined from the information given.
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is 0.3026 a finite number
Plastic beads can often carry a small charge and therefore can generate electric fields. Three beads are oriented such that
system of all three beads is zero.
91
E field lines
93
92
What charge does each bead carry?
91
92
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What is the net charge of the system? What charges have to be equal? μC
2.9
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What is the net charge of the system? What charges have to be equal? μC
93 = 2.9
μС
92
is between and
91 93°
The sum of the charge on q₁ and 92 is 91 + 92 = −2.9 μC, and the net charge of the
Chapter 3 Solutions
College Physics
Ch. 3.1 - The magnitudes of two vectors A and B are 12 units...Ch. 3.2 - Prob. 3.2QQCh. 3.2 - Prob. 3.3QQCh. 3.3 - Which of the following objects cant be...Ch. 3.3 - Consider the following controls in an automobile:...Ch. 3.4 - Suppose you are carrying a ball and running at...Ch. 3.4 - As a projectile moves in its parabolic path, where...Ch. 3 - A vector A has components Ax = 5.00 m and Ay =...Ch. 3 - Calculate (a) the x- and (b) y-components of the...Ch. 3 - Find (a) the x- and (b) y-components of R = 2A B...
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- Plastic beads can often carry a small charge and therefore can generate electric fields. Three beads are oriented such that 92 is between q₁ and 93. The sum of the charge on 9₁ and 92 is 9₁ + 92 = −2.9 µС, and the net charge of the system of all three beads is zero. E field lines 93 92 What charge does each bead carry? 91 92 -1.45 What is the net charge of the system? What charges have to be equal? μC 2.9 ✓ What is the net charge of the system? What charges have to be equal? μC 93 2.9 μεarrow_forwardNo chatgpt pls will upvotearrow_forwardPoint charges of 6.50 μC and -2.50 μC are placed 0.300 m apart. (Assume the negative charge is located to the right of the positive charge. Include the sign of the value in your answers.) (a) Where can a third charge be placed so that the net force on it is zero? 0.49 m to the right of the -2.50 μC charge (b) What if both charges are positive? 0.49 xm to the right of the 2.50 μC chargearrow_forward
- Find the electric field at the location of q, in the figure below, given that q₁ =9c9d = +4.60 nC, q = -1.00 nC, and the square is 20.0 cm on a side. (The +x axis is directed to the right.) magnitude direction 2500 x What symmetries can you take advantage of? What charges are the same magnitude and the same distance away? N/C 226 × How does charge sign affect the direction of the electric field? counterclockwise from the +x-axis 9a 9b % 9 9darrow_forwardwould 0.215 be the answer for part b?arrow_forwardSuppose a toy boat moves in a pool at at a speed given by v=1.0 meter per second at t=0, and that the boat is subject to viscous damping. The damping on the boat causes the rate of speed loss to be given by the expression dv/dt=-2v. How fast will the boat be traveling after 1 second? 3 seconds? 10 seconds? Use separation of variables to solve this.arrow_forward
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- What is the net charge on a sphere that has the following? x (a) 5.75 × 106 electrons and 8.49 × 106 protons 4.39e-13 What is the charge of an electron? What is the charge of a proton? C (b) 200 electrons and 109 protons 1.60e-10 What is the charge of an electron? What is the charge of a proton? Carrow_forwardA spider begins to spin a web by first hanging from a ceiling by his fine, silk fiber. He has a mass of 0.025 kg and a charge of 3.5 μC. A second spider with a charge of 4.2 μC rests in her own web exactly 2.1 m vertically below the first spider. (a) What is the magnitude of the electric field due to the charge on the second spider at the position of the first spider? 8.57e3 N/C (b) What is the tension in the silk fiber above the first spider? 0.125 How does the electric field relate to the force? How do you calculate the net force? Narrow_forwardPoint charges of 6.50 μC and -2.50 μC are placed 0.300 m apart. (Assume the negative charge is located to the right of the positive charge. Include the sign of the value in your answers.) (a) Where can a third charge be placed so that the net force on it is zero? 0.49 m to the right of the -2.50 μC charge (b) What if both charges are positive? 0.185 xm to the right of the 2.50 μC chargearrow_forward
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