A rectangular block of iron 4.60 c m x 10.3 c m x 13.2 cm has a mass of 4.92 kg. Its density in g/cm 3 is to be calculated. Concept introduction: Commonly, two variables such as mass (m) and volume (V) can be described as directly proportional one on other by the expression m α V. Besides, the term density is defined by mass of a substance per unit volume and denoted by the ‘D’ symbol.

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Answer 1

Question

Chapter 3, Problem 106E

Interpretation Introduction

Interpretation:

A rectangular block of iron 4.60 cm x 10.3 cm x 13.2 cm has a mass of 4.92 kg. Its density in g/cm³ is to be calculated.

Concept introduction:

Commonly, two variables such as mass (m) and volume (V) can be described as directly proportional one on other by the expression m α V. Besides, the term density is defined by mass of a substance per unit volume and denoted by the ‘D’ symbol.

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Answer 2

Question

Chapter 3, Problem 106E

Interpretation Introduction

Interpretation:

A rectangular block of iron 4.60 cm x 10.3 cm x 13.2 cm has a mass of 4.92 kg. Its density in g/cm³ is to be calculated.

Concept introduction:

Commonly, two variables such as mass (m) and volume (V) can be described as directly proportional one on other by the expression m α V. Besides, the term density is defined by mass of a substance per unit volume and denoted by the ‘D’ symbol.

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Answer 3

Question

Chapter 3, Problem 106E

Interpretation Introduction

Interpretation:

A rectangular block of iron 4.60 cm x 10.3 cm x 13.2 cm has a mass of 4.92 kg. Its density in g/cm³ is to be calculated.

Concept introduction:

Commonly, two variables such as mass (m) and volume (V) can be described as directly proportional one on other by the expression m α V. Besides, the term density is defined by mass of a substance per unit volume and denoted by the ‘D’ symbol.

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Answer 4

Question

Chapter 3, Problem 106E

Interpretation Introduction

Interpretation:

A rectangular block of iron 4.60 cm x 10.3 cm x 13.2 cm has a mass of 4.92 kg. Its density in g/cm³ is to be calculated.

Concept introduction:

Commonly, two variables such as mass (m) and volume (V) can be described as directly proportional one on other by the expression m α V. Besides, the term density is defined by mass of a substance per unit volume and denoted by the ‘D’ symbol.

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Answer 5

Chapter 3, Problem 106E

Interpretation Introduction

Interpretation:

A rectangular block of iron 4.60 cm x 10.3 cm x 13.2 cm has a mass of 4.92 kg. Its density in g/cm³ is to be calculated.

Concept introduction:

Commonly, two variables such as mass (m) and volume (V) can be described as directly proportional one on other by the expression m α V. Besides, the term density is defined by mass of a substance per unit volume and denoted by the ‘D’ symbol.

Answer 6

Chapter 3, Problem 106E

Interpretation Introduction

Interpretation:

A rectangular block of iron 4.60 cm x 10.3 cm x 13.2 cm has a mass of 4.92 kg. Its density in g/cm³ is to be calculated.

Concept introduction:

Commonly, two variables such as mass (m) and volume (V) can be described as directly proportional one on other by the expression m α V. Besides, the term density is defined by mass of a substance per unit volume and denoted by the ‘D’ symbol.

Answer 7

Chapter 3, Problem 106E

Interpretation Introduction

Interpretation:

A rectangular block of iron 4.60 cm x 10.3 cm x 13.2 cm has a mass of 4.92 kg. Its density in g/cm³ is to be calculated.

Concept introduction:

Commonly, two variables such as mass (m) and volume (V) can be described as directly proportional one on other by the expression m α V. Besides, the term density is defined by mass of a substance per unit volume and denoted by the ‘D’ symbol.

Answer 8

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Answer 9

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Answer 10

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Answer 11

Ch. 3 - Equivalency, conversion factor, solving...Ch. 3 - Metric system, SI units, derived unit, base unit Ch. 3 - Prob. 3CLE Ch. 3 - Prob. 4CLE Ch. 3 - Prob. 5CLE Ch. 3 - Write the following numbers in scientific...Ch. 3 - Prob. 2E Ch. 3 - Write the following numbers in ordinary decimal...Ch. 3 - Write the ordinary form of the following numbers:...Ch. 3 - Prob. 5E

Solution Summary: The author explains that the density of a rectangular block of iron in g/cm 3 is calculated by the division of the mass of that object (m) and volume (V).

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