Physics For Scientists And Engineers With Modern Physics, 9th Edition, The Ohio State University
9th Edition
ISBN: 9781305372337
Author: Raymond A. Serway | John W. Jewett
Publisher: Cengage Learning
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Chapter 29, Problem 70AP
To determine
The reason for the impossible situation as described in the problem.
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Chapter 29 Solutions
Physics For Scientists And Engineers With Modern Physics, 9th Edition, The Ohio State University
Ch. 29.1 - An electron moves in the plane of this paper...Ch. 29.2 - Prob. 29.2QQCh. 29.4 - A wire carries current in the plane of this paper...Ch. 29.5 - (i) Rank the magnitudes of the torques acting on...Ch. 29 - Prob. 1OQCh. 29 - Prob. 2OQCh. 29 - Prob. 3OQCh. 29 - Prob. 4OQCh. 29 - Prob. 5OQCh. 29 - Prob. 6OQ
Ch. 29 - Prob. 7OQCh. 29 - Prob. 8OQCh. 29 - Prob. 9OQCh. 29 - Prob. 10OQCh. 29 - Prob. 11OQCh. 29 - Prob. 12OQCh. 29 - Prob. 13OQCh. 29 - Prob. 1CQCh. 29 - Prob. 2CQCh. 29 - Prob. 3CQCh. 29 - Prob. 4CQCh. 29 - Prob. 5CQCh. 29 - Prob. 6CQCh. 29 - Prob. 7CQCh. 29 - At the equator, near the surface of the Earth, the...Ch. 29 - Prob. 2PCh. 29 - Prob. 3PCh. 29 - Consider an electron near the Earths equator. In...Ch. 29 - Prob. 5PCh. 29 - A proton moving at 4.00 106 m/s through a...Ch. 29 - Prob. 7PCh. 29 - Prob. 8PCh. 29 - A proton travels with a speed of 5.02 106 m/s in...Ch. 29 - Prob. 10PCh. 29 - Prob. 11PCh. 29 - Prob. 12PCh. 29 - Prob. 13PCh. 29 - An accelerating voltage of 2.50103 V is applied to...Ch. 29 - A proton (charge + e, mass mp), a deuteron (charge...Ch. 29 - Prob. 16PCh. 29 - Review. One electron collides elastically with a...Ch. 29 - Review. One electron collides elastically with a...Ch. 29 - Review. An electron moves in a circular path...Ch. 29 - Prob. 20PCh. 29 - Prob. 21PCh. 29 - Prob. 22PCh. 29 - Prob. 23PCh. 29 - A cyclotron designed to accelerate protons has a...Ch. 29 - Prob. 25PCh. 29 - Prob. 26PCh. 29 - A cyclotron (Fig. 28.16) designed to accelerate...Ch. 29 - Prob. 28PCh. 29 - Prob. 29PCh. 29 - Prob. 30PCh. 29 - Prob. 31PCh. 29 - Prob. 32PCh. 29 - Prob. 33PCh. 29 - Prob. 34PCh. 29 - A wire carries a steady current of 2.40 A. A...Ch. 29 - Prob. 36PCh. 29 - Prob. 37PCh. 29 - Prob. 38PCh. 29 - Prob. 39PCh. 29 - Consider the system pictured in Figure P28.26. A...Ch. 29 - Prob. 41PCh. 29 - Prob. 42PCh. 29 - Prob. 43PCh. 29 - Prob. 44PCh. 29 - Prob. 45PCh. 29 - A 50.0-turn circular coil of radius 5.00 cm can be...Ch. 29 - Prob. 47PCh. 29 - Prob. 48PCh. 29 - Prob. 49PCh. 29 - Prob. 50PCh. 29 - Prob. 51PCh. 29 - Prob. 52PCh. 29 - Prob. 53PCh. 29 - A Hall-effect probe operates with a 120-mA...Ch. 29 - Prob. 55PCh. 29 - Prob. 56APCh. 29 - Prob. 57APCh. 29 - Prob. 58APCh. 29 - Prob. 59APCh. 29 - Prob. 60APCh. 29 - Prob. 61APCh. 29 - Prob. 62APCh. 29 - Prob. 63APCh. 29 - Prob. 64APCh. 29 - Prob. 65APCh. 29 - Prob. 66APCh. 29 - A proton having an initial velocity of 20.0iMm/s...Ch. 29 - Prob. 68APCh. 29 - Prob. 69APCh. 29 - Prob. 70APCh. 29 - Prob. 71APCh. 29 - Prob. 72APCh. 29 - Prob. 73APCh. 29 - Prob. 74APCh. 29 - Prob. 75APCh. 29 - Prob. 76APCh. 29 - Prob. 77CPCh. 29 - Prob. 78CPCh. 29 - Review. A wire having a linear mass density of...Ch. 29 - Prob. 80CP
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- A particle moving downward at a speed of 6.0106 m/s enters a uniform magnetic field that is horizontal and directed from east to west. (a) If the particle is deflected initially to the north in a circular arc, is its charge positive or negative? (b) If B = 0.25 T and the charge-to-mass ratio (q/m) of the particle is 40107 C/kg. what is ±e radius at the path? (c) What is the speed of the particle after c has moved in the field for 1.0105s ? for 2.0s?arrow_forwardIn Niels Bohr’s 1913 model of the hydrogen atom, the single electron is in a circular orbit of radius 5.29 × 10−11 m and its speed is 2.19 × 106 m/s. (a) What is the magnitude of the magnetic moment due to the electron’s motion? (b) If the electron moves in a horizontal circle, counterclockwise as seen from above, what is the direction of this magnetic moment vector?arrow_forwardThe velocity vector of a singly charged helium ion (mHe = 6.64 1027 kg) is given by v=4.50105m/s. The acceleration of the ion in a region of space with a uniform magnetic field is 8.50 1012 m/s2 in the positive y direction. The velocity is perpendicular to the field direction. What are the magnitude and direction of the magnetic field in this region?arrow_forward
- Why is the following situation impossible? Figure P28.46 shows an experimental technique for altering the direction of travel for a charged particle. A particle of charge q = 1.00 C and mass m = 2.00 1015 kg enters the bottom of the region of uniform magnetic field at speed = 2.00 105 m/s, with a velocity vector perpendicular to the field lines. The magnetic force on the particle causes its direction of travel to change so that it leaves the region of the magnetic field at the top traveling at an angle from its original direction. The magnetic field has magnitude B = 0.400 T and is directed out of the page. The length h of the magnetic field region is 0.110 m. An experimenter performs the technique and measures the angle at which the particles exit the top of the field. She finds that the angles of deviation are exactly as predicted. Figure P28.46arrow_forwardTwo infinitely long current-carrying wires run parallel in the xy plane and are each a distance d = 11.0 cm from the y axis (Fig. P30.83). The current in both wires is I = 5.00 A in the negative y direction. a. Draw a sketch of the magnetic field pattern in the xz plane due to the two wires. What is the magnitude of the magnetic field due to the two wires b. at the origin and c. as a function of z along the z axis, at x = y = 0? FIGURE P30.83arrow_forwardA circular coil 15.0 cm in radius and composed of 145 tightly wound turns carries a current of 2.50 A in the counterclockwise direction, where the plane of the coil makes an angle of 15.0 with the y axis (Fig. P30.73). The coil is free to rotate about the z axis and is placed in a region with a uniform magnetic field given by B=1.35jT. a. What is the magnitude of the magnetic torque on the coil? b. In what direction will the coil rotate? FIGURE P30.73arrow_forward
- Determine the initial direction of the deflection of charged particles as they enter the magnetic fields as shown in Figure P22.2. Figure P22.2.arrow_forwardAn infinitely long wire carrying a current I is bent at a right angle as shown in Figure P22.30. Determine the magnetic field at point P, located a distance x from the corner of the wire. Figure P22.30arrow_forwardA magnetic field directed into the page changes with time according to B = 0.030 0t2 + 1.40, where B is in teslas and t is in seconds. The field has a circular cross section of radius R = 2.50 cm (see Fig. P23.28). When t = 3.00 s and r2 = 0.020 0 m, what are (a) the magnitude and (b) the direction of the electric field at point P2?arrow_forward
- A proton moving in the plane of the page has a kinetic energy of 6.00 MeV. A magnetic field of magnitude H = 1.00 T is directed into the page. The proton enters the magnetic field with its velocity vector at an angle = 45.0 to the linear boundary of' the field as shown in Figure P29.80. (a) Find x, the distance from the point of entry to where the proton will leave the field. (b) Determine . the angle between the boundary and the protons velocity vector as it leaves the field.arrow_forwardA wire carrying a current I is bent into the shape of an exponential spiral, r = e, from = 0 to = 2 as suggested in Figure P29.47. To complete a loop, the ends of the spiral are connected by a straight wire along the x axis. (a) The angle between a radial line and its tangent line at any point on a curve r = f() is related to the function by tan=rdr/d Use this fact to show that = /4. (b) Find the magnetic field at the origin. Figure P29.47arrow_forwardAt a particular instant an electron is traveling west to east with a kinetic energy of 10 keV. Earth's magnetic field has a horizontal component of 1.8105 T north and a vertical component of 5.0105 T down. (a) What is the path of the election? (b) What is the radius of curvature of the path?arrow_forward
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Magnets and Magnetic Fields; Author: Professor Dave explains;https://www.youtube.com/watch?v=IgtIdttfGVw;License: Standard YouTube License, CC-BY