(a) Interpretation: The speed of the template DNA that spins at an E.coli replication fork needs to be determined. Concept introduction: DNA exists inside the nucleus as a molecule which is double-stranded. One strand is the coding strand while the second strand of DNA is a non-coding strand. The non-coding strand is actually the template (Template DNA).

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Answer 1

Question

Chapter 29, Problem 6P

Interpretation Introduction

(a)

Interpretation:

The speed of the template DNA that spins at an E.coli replication fork needs to be determined.

Concept introduction:

DNA exists inside the nucleus as a molecule which is double-stranded. One strand is the coding strand while the second strand of DNA is a non-coding strand. The non-coding strand is actually the template (Template DNA).

Interpretation Introduction

(b)

Interpretation:

The relative velocity of movement of DNA polymerase III holoenzyme and template needs to be determined.

Concept introduction:

The DNA polymerase III holoenzyme is the type of primary enzyme complex which is involved in prokaryotic DNA replication.

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For a Michaelis-Menten reaction, k₁-5 x 10'/M-s, k.-2 x 10%/s, and k₂-4 x 10²/s. a) Calculate the Ks and KM for this reaction. b) Does substrate binding achieve equilibrium or steady state?

Assume that an enzyme-catalyzed reaction follows the scheme shown: E+S SES →E + P k₁ = 1 x 109/M-s k-1=2.5 x 10%/s k₂ = 3.4 x 107/s What is the dissociation constant for the enzyme-substrate, K,? What is the Michaelis constant, Km, for this enzyme? What is the turnover number, Keat, for this enzyme? What is the catalytic efficiency for the enzyme? If the initial Et concentration is 0.25mM, what is Vmax?

An enzyme lowers the activation energy, (AG) of a reaction from 50.0 kcal/mol to 40.0 kcal/mol. Calulate the catalytic power at 310K. (R-1.987x10 kcal/mol)

Answer 2

Question

Chapter 29, Problem 6P

Interpretation Introduction

(a)

Interpretation:

The speed of the template DNA that spins at an E.coli replication fork needs to be determined.

Concept introduction:

DNA exists inside the nucleus as a molecule which is double-stranded. One strand is the coding strand while the second strand of DNA is a non-coding strand. The non-coding strand is actually the template (Template DNA).

Interpretation Introduction

(b)

Interpretation:

The relative velocity of movement of DNA polymerase III holoenzyme and template needs to be determined.

Concept introduction:

The DNA polymerase III holoenzyme is the type of primary enzyme complex which is involved in prokaryotic DNA replication.

Expert Solution & Answer

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Answer 3

Question

Chapter 29, Problem 6P

Interpretation Introduction

(a)

Interpretation:

The speed of the template DNA that spins at an E.coli replication fork needs to be determined.

Concept introduction:

DNA exists inside the nucleus as a molecule which is double-stranded. One strand is the coding strand while the second strand of DNA is a non-coding strand. The non-coding strand is actually the template (Template DNA).

Interpretation Introduction

(b)

Interpretation:

The relative velocity of movement of DNA polymerase III holoenzyme and template needs to be determined.

Concept introduction:

The DNA polymerase III holoenzyme is the type of primary enzyme complex which is involved in prokaryotic DNA replication.

Expert Solution & Answer

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See solution

Answer 4

Question

Chapter 29, Problem 6P

Interpretation Introduction

(a)

Interpretation:

The speed of the template DNA that spins at an E.coli replication fork needs to be determined.

Concept introduction:

DNA exists inside the nucleus as a molecule which is double-stranded. One strand is the coding strand while the second strand of DNA is a non-coding strand. The non-coding strand is actually the template (Template DNA).

Interpretation Introduction

(b)

Interpretation:

The relative velocity of movement of DNA polymerase III holoenzyme and template needs to be determined.

Concept introduction:

The DNA polymerase III holoenzyme is the type of primary enzyme complex which is involved in prokaryotic DNA replication.

Expert Solution & Answer

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See solution

Answer 5

Chapter 29, Problem 6P

Interpretation Introduction

(a)

Interpretation:

The speed of the template DNA that spins at an E.coli replication fork needs to be determined.

Concept introduction:

DNA exists inside the nucleus as a molecule which is double-stranded. One strand is the coding strand while the second strand of DNA is a non-coding strand. The non-coding strand is actually the template (Template DNA).

Interpretation Introduction

(b)

Interpretation:

The relative velocity of movement of DNA polymerase III holoenzyme and template needs to be determined.

Concept introduction:

The DNA polymerase III holoenzyme is the type of primary enzyme complex which is involved in prokaryotic DNA replication.

Answer 6

Chapter 29, Problem 6P

Interpretation Introduction

(a)

Interpretation:

The speed of the template DNA that spins at an E.coli replication fork needs to be determined.

Concept introduction:

DNA exists inside the nucleus as a molecule which is double-stranded. One strand is the coding strand while the second strand of DNA is a non-coding strand. The non-coding strand is actually the template (Template DNA).

Answer 7

Chapter 29, Problem 6P

Interpretation Introduction

(a)

Interpretation:

The speed of the template DNA that spins at an E.coli replication fork needs to be determined.

Concept introduction:

DNA exists inside the nucleus as a molecule which is double-stranded. One strand is the coding strand while the second strand of DNA is a non-coding strand. The non-coding strand is actually the template (Template DNA).

Answer 8

Interpretation Introduction

(b)

Interpretation:

The relative velocity of movement of DNA polymerase III holoenzyme and template needs to be determined.

Concept introduction:

The DNA polymerase III holoenzyme is the type of primary enzyme complex which is involved in prokaryotic DNA replication.

Answer 9

Interpretation Introduction

(b)

Interpretation:

The relative velocity of movement of DNA polymerase III holoenzyme and template needs to be determined.

Concept introduction:

The DNA polymerase III holoenzyme is the type of primary enzyme complex which is involved in prokaryotic DNA replication.

Answer 10

Expert Solution & Answer

Answer 11

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Answer 12

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Answer 13

Ch. 29 - Prob. 1P Ch. 29 - Prob. 2P Ch. 29 - Prob. 3P Ch. 29 - Prob. 4P Ch. 29 - Prob. 5P Ch. 29 - Prob. 6P Ch. 29 - Prob. 7P Ch. 29 - Prob. 8P Ch. 29 - Prob. 9P Ch. 29 - Prob. 10P

Solution Summary: The author explains that DNA exists inside the nucleus as a molecule which is double-stranded. The template DNA spins at an E.coli replication fork is 160 to 170 revolutions per second.

Concept explainers

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(b)

Interpretation:

The relative velocity of movement of DNA polymerase III holoenzyme and template needs to be determined.

Concept introduction:

The DNA polymerase III holoenzyme is the type of primary enzyme complex which is involved in prokaryotic DNA replication.

Want to see the full answer?

Chapter 29 Solutions

Solution Summary: The author explains that DNA exists inside the nucleus as a molecule which is double-stranded. The template DNA spins at an E.coli replication fork is 160 to 170 revolutions per second.

Concept explainers

Videos

(b) Interpretation: The relative velocity of movement of DNA polymerase III holoenzyme and template needs to be determined. Concept introduction: The DNA polymerase III holoenzyme is the type of primary enzyme complex which is involved in prokaryotic DNA replication.

Want to see the full answer?

Chapter 29 Solutions

(b)

Interpretation:

The relative velocity of movement of DNA polymerase III holoenzyme and template needs to be determined.

Concept introduction:

The DNA polymerase III holoenzyme is the type of primary enzyme complex which is involved in prokaryotic DNA replication.