PHY F/SCIENTIST MOD MASTERING 24 MO
17th Edition
ISBN: 9780137319497
Author: Knight
Publisher: PEARSON
expand_more
expand_more
format_list_bulleted
Concept explainers
Videos
Textbook Question
Chapter 29, Problem 66EAP
Particle accelerators, such as the Large Hadron Collider. use magnetic fields to steer charged particles around a ring. Consider a proton ring with 36 identical bending magnets connected by straight segments. The protons move along a 1.0-rn-long circular arc as they pass through each magnet. What magnetic field strength is needed in each magnet to steer protons around the ring with a speed of
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solution
Students have asked these similar questions
a. Calculate the radius of the helical path traced out by the electron. Give your answer in centimeters.
b. Calculate the electron’s cyclotron frequency. Give your answer in Megahertz.
A particle of charge +5 nC and mass = 5 micro-gram) moves with a velocity V = 3.6 i km/s in a
region where the magnetic field is B = 5.7 i + 6.8 j mT. What is the magnitude of the force on the
particle due to the magnetic field? Write your answer in nano-newtons.
In an experiment designed to measure the magnitude of a uniform magnetic field, electrons
are accelerated from rest through a potential difference of 350 V (think of problem 7 in hw
3). The electrons travel along a curved path because of the magnetic force exerted on them,
and the radius of the path is measured to be 7.5 cm. If the magnetic field is perpendicular
to the beam,
a. What is the magnitude of the field?
b. What is the angular speed of the electrons?
Chapter 29 Solutions
PHY F/SCIENTIST MOD MASTERING 24 MO
Ch. 29 - The lightweight glass sphere in FIGURE Q29.1 hangs...Ch. 29 - The metal sphere in FIGURE Q29.2 hangs by a...Ch. 29 - Prob. 3CQCh. 29 - Prob. 4CQCh. 29 - What is the current direction in the wire of...Ch. 29 - What is the initial direction of deflection for...Ch. 29 - What is the initial direction of deflection for...Ch. 29 - Determine the magnetic field direction that causes...Ch. 29 - Determine the magnetic field direction that causes...Ch. 29 - Prob. 10CQ
Ch. 29 - The south pole of a bar magnet is brought toward...Ch. 29 - Prob. 12CQCh. 29 - Prob. 1EAPCh. 29 - Prob. 2EAPCh. 29 - 3. A proton moves along the x-axis with rn/s. As...Ch. 29 - An electron moves along the z-axis with vz=2.0107...Ch. 29 - What is the magnetic field at the position of the...Ch. 29 - What is the magnetic field at the position of the...Ch. 29 - Prob. 7EAPCh. 29 - Prob. 8EAPCh. 29 - Prob. 9EAPCh. 29 - A biophysics experiment uses a very sensitive...Ch. 29 - The magnetic field at the center of a 1.0...Ch. 29 - 12. What are the magnetic fields at points a to c...Ch. 29 - Prob. 13EAPCh. 29 - What are the magnetic field strength and direction...Ch. 29 - Prob. 15EAPCh. 29 - 16. The on-axis magnetic field strength cm from...Ch. 29 - A A current circulates around a -mm-diameter...Ch. 29 - 18. A small, square loop carries a A current. The...Ch. 29 - Prob. 19EAPCh. 29 - 20. What is the line integral of integral points...Ch. 29 - 21. What is the line integral of between points i...Ch. 29 - The value of the line integral of around the...Ch. 29 - 23. The value of the line integral of around the...Ch. 29 - 24. What is the line integral of between points i...Ch. 29 - Prob. 25EAPCh. 29 - 26. A proton moves in the magnetic field with a...Ch. 29 - Prob. 27EAPCh. 29 - 28. Radio astronomers detect electromagnetic...Ch. 29 - Prob. 29EAPCh. 29 - Prob. 30EAPCh. 29 - The microwaves in a microwave oven are produced in...Ch. 29 - The Hall voltage across a conductor in a 55mT...Ch. 29 - 33. What magnetic field strength and direction...Ch. 29 - 34. The two -cm-long parallel wires in FIGURE...Ch. 29 - The right edge of the circuit in FIGURE EX29.35...Ch. 29 - Prob. 36EAPCh. 29 - Prob. 37EAPCh. 29 - 38. A square current loop cm on each side carries...Ch. 29 - Prob. 39EAPCh. 29 - 40. a. What is the magnitude of the torque on the...Ch. 29 - A long wire carrying a 5.0A current perpendicular...Ch. 29 - Prob. 42EAPCh. 29 - What are the strength and direction of the...Ch. 29 - At what distance on the axis of a current loop is...Ch. 29 - 45. Find an expression for the magnetic field...Ch. 29 - Prob. 46EAPCh. 29 - Prob. 47EAPCh. 29 - 48. A -m-long, -mm-diameter aluminum wire has a...Ch. 29 - Prob. 49EAPCh. 29 - Prob. 50EAPCh. 29 - Prob. 51EAPCh. 29 - Weak magnetic fields can be measured at the...Ch. 29 - The heart produces a weak magnetic field that can...Ch. 29 - Prob. 54EAPCh. 29 - 55. The toroid of FIGURE P29.55 is a coil of wire...Ch. 29 - 56. The coaxial cable shown in FIGURE P29.56...Ch. 29 - 57. A long, hollow wire has inner radius and...Ch. 29 - 58. A proton moving in a uniform magnetic field...Ch. 29 - 59. An electron travels with speed m/s between...Ch. 29 - Prob. 60EAPCh. 29 - An antiproton (same properties as a proton except...Ch. 29 - a. A 65 -cm-diameter cyclotron uses a 500 V...Ch. 29 - An antiproton is identical to a proton except it...Ch. 29 - Prob. 64EAPCh. 29 - Prob. 65EAPCh. 29 - Particle accelerators, such as the Large Hadron...Ch. 29 - 67. A particle of charge q and mass m moves in the...Ch. 29 - 68. A Hall-effect probe to measure magnetic field...Ch. 29 - Prob. 69EAPCh. 29 - Prob. 70EAPCh. 29 - The 10-turn loop of wire shown in FIGURE P29.71...Ch. 29 - The two springs in FIGURE P29.72 each have a...Ch. 29 - Prob. 73EAPCh. 29 - Prob. 74EAPCh. 29 - A conducting bar of length I and mass m rests at...Ch. 29 - Prob. 76EAPCh. 29 - A wire along the x-axis carries current I in the...Ch. 29 - Prob. 78EAPCh. 29 - Prob. 79EAPCh. 29 - a. Derive an expression for the magnetic field...Ch. 29 - Prob. 81EAPCh. 29 - A long, straight conducting wire of radius R has a...Ch. 29 - Prob. 83EAP
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.Similar questions
- (a) A cosmic ray proton moving toward the Earth at 5.00107m/s experiences a magnetic force of 1.701016N. What is the strength of the magnetic field it there is a 45° angle between it and the proton’s velocity? (b) Is the value obtained in part (a) consistent with the known strength of the Earth’s magnetic field on its surface? Discuss.arrow_forwardA particle moving downward at a speed of 6.0106 m/s enters a uniform magnetic field that is horizontal and directed from east to west. (a) If the particle is deflected initially to the north in a circular arc, is its charge positive or negative? (b) If B = 0.25 T and the charge-to-mass ratio (q/m) of the particle is 40107 C/kg. what is ±e radius at the path? (c) What is the speed of the particle after c has moved in the field for 1.0105s ? for 2.0s?arrow_forwardIn Niels Bohr’s 1913 model of the hydrogen atom, the single electron is in a circular orbit of radius 5.29 × 10−11 m and its speed is 2.19 × 106 m/s. (a) What is the magnitude of the magnetic moment due to the electron’s motion? (b) If the electron moves in a horizontal circle, counterclockwise as seen from above, what is the direction of this magnetic moment vector?arrow_forward
- (a) What is the force per meter on a lightning bolt at the equator that carries 20,000 A perpendicular to the Earth's 3.00105-T field? (b) What is the direction of the force it the current is straight up and the Earth’s field direction is due north, parallel to the ground?arrow_forwardAt a particular instant an electron is traveling west to east with a kinetic energy of 10 keV. Earth's magnetic field has a horizontal component of 1.8105 T north and a vertical component of 5.0105 T down. (a) What is the path of the election? (b) What is the radius of curvature of the path?arrow_forwardAn electron in a TV CRT moves with a speed of 6.0107 m/s, in a direction perpendicular to Earth's field, which has a strength of 5.0105 T. (a) What strength electric field must be applied perpendicular to the Earth’s field to make the election moves in a straight line? (b) If this is done between plates separated by 1.00 cm, what is the voltage applied? (Note that TVs are usually surrounded by a ferromagnetic material to shield against external magnetic fields and avoid the need for such a collection,)arrow_forward
- One long wire carries current 30.0 A to the left along the x axis. A second long wire carries current 50.0 A to the right along the line (y = 0.280 m, z = 0). (a) Where in the plane of the two wires is the total magnetic field equal to zero? (b) A particle with a charge of 2.00 C is moving with a velocity of 150iMm/s along the line (y = 0.100 m, z = 0). Calculate the vector magnetic force acting on the particle. (c) What If? A uniform electric field is applied to allow this particle to pass through this region undetected. Calculate the required vector electric field.arrow_forwardA charged particle moves into a region of uniform magnetic field, goes through half a circle, and then exits that region. The particle is either a proton or an electron (you must decide which). It spends 130 ns in the region. What is the magnitude of B? Give your answer in T. (mproton=1.672x1027 kg, melectron-9.1lx10-3! kg, e-1.602x10-19 C) OBarrow_forwardA particle with charge qenters a region where there is a uniform magnetic field B= Bk. The initial velocity of the particle is (=vi). The particle leaves the region with velocity (v= vj). Find the distance between the points where the particle enters and leaves the region with a uniform magnetic field. a. qB b. 2gB 2mv qB d. V2mu qB e. qBarrow_forward
- A proton moves in a helical path at speed v = 5.10 x 107 m/s high above the atmosphere, where Earth's magnetic field has magnitude B = 3.80 x 10-6 T. The proton's velocity makes an angle of 25.0° with the magnetic field. The mass of the proton is 1.673x10-27 kg. Find the radius of the helix. kmarrow_forwardCalculate the magnetic force on an electron in the following cases. Provide your answers in component form (Here i, j, k denote the unit vectors for the x,y, and z directions, respectively.): a. A proton with velocity v = (1.20×104 i) m/s moving in a magnetic field of magnitude (0.7 k) T. Fx Fy F₂ Submit Answer Tries 0/10 = b. A proton with velocity v = (1.70×104 i) m/s moving in a magnetic field of magnitude (0.05 i + 0.7 j) T. Fx = Fy= F₂= Submit Answer Tries 0/10 c. A proton with velocity v = (1.50×104 i +5.00×10³ j) m/s moving in a magnetic field of magnitude (0.65 i + 0.85 k) T. Fx Fy= F₂ = Submit Answer Tries 0/10 Fy b. A proton with velocity v = (2.70×104 i +2.10×104 j+ 1.40×104 k) m/s moving in a magnetic field of magnitude (0.95 i -0.75 j + 0.2 k) T. Fx = = F₂ = Submit Answer Tries 0/10arrow_forwardQ8.2arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
Physics for Scientists and EngineersPhysicsISBN:9781337553278Author:Raymond A. Serway, John W. JewettPublisher:Cengage Learning
Physics for Scientists and Engineers with Modern ...PhysicsISBN:9781337553292Author:Raymond A. Serway, John W. JewettPublisher:Cengage Learning
Principles of Physics: A Calculus-Based TextPhysicsISBN:9781133104261Author:Raymond A. Serway, John W. JewettPublisher:Cengage Learning
College PhysicsPhysicsISBN:9781938168000Author:Paul Peter Urone, Roger HinrichsPublisher:OpenStax College
Physics for Scientists and Engineers: Foundations...PhysicsISBN:9781133939146Author:Katz, Debora M.Publisher:Cengage Learning
Physics for Scientists and Engineers
Physics
ISBN:9781337553278
Author:Raymond A. Serway, John W. Jewett
Publisher:Cengage Learning
Physics for Scientists and Engineers with Modern ...
Physics
ISBN:9781337553292
Author:Raymond A. Serway, John W. Jewett
Publisher:Cengage Learning
Principles of Physics: A Calculus-Based Text
Physics
ISBN:9781133104261
Author:Raymond A. Serway, John W. Jewett
Publisher:Cengage Learning
College Physics
Physics
ISBN:9781938168000
Author:Paul Peter Urone, Roger Hinrichs
Publisher:OpenStax College
Physics for Scientists and Engineers: Foundations...
Physics
ISBN:9781133939146
Author:Katz, Debora M.
Publisher:Cengage Learning
Magnets and Magnetic Fields; Author: Professor Dave explains;https://www.youtube.com/watch?v=IgtIdttfGVw;License: Standard YouTube License, CC-BY