
Concept explainers
Classify each of die following statements as a characteristic (a) of electric forces only, (b) of magnetic forces only, (c) of both electric and magnetic forces, or (d) of neither electric nor magnetic forces. (i) The force is proportional to the magnitude of the field exerting it. (ii) The force is proportional to the magnitude of the charge of the object on which the force is exerted. (iii) The force exerted on a negatively charged object is opposite in direction to the force on a positive charge. (iv) The force exerted on a stationary charged object is nonzero. (v) The force exerted on a moving charged object is zero. (vi) The force exerted on a charged object is proportional to its speed. (vii) The force exerted on a charged object cannot alter the object’s speed. (viii) The magnitude of the force depends on the charged object’s direction of motion.
(i)

The forces which are proportional to the magnitude of their respective fields.
Answer to Problem 29.8OQ
Option(c) of both electric and magnetic forces.
Explanation of Solution
The expression for electrical force is,
Here,
Increase the electric field, the force on the charge will also increase proportional to it.
The expression for magnetic force is,
Here,
Increase the magnetic field with same speed on same charge in the same direction, the force on the charge will also increase proportional to it.
Conclusion:
The electric force is proportional to the electric field and the magnetic force is proportional to the magnetic field. Both electric and magnetic forces are proportional to their respective fields but option (a) includes only electric force. Thus, option (a) is incorrect.
The magnetic force is proportional to the magnetic field and the electric force is proportional to the electric field. Both the forces are proportional to their respective fields but option (b) includes only magnetic force. Thus, option (b) is incorrect.
Both the forces are proportional to their respective fields. Thus option (c) is correct.
The exerted forces in magnetic field as well as electric field are proportional to their respective field that contradicts the option (d). Thus, option (d) is incorrect.
(ii)

The forces proportional to the magnitude of the charge.
Answer to Problem 29.8OQ
Option (c) both electric and magnetic forces
Explanation of Solution
The expression for electrical force is,
Increase the magnitude of charge, the force on the charge will also increase proportional to it.
The expression for magnetic force is
Increase the magnitude of charge with same speed and in the same field, in the same direction, the force on the charge will also increase proportional to it.
Conclusion:
The electric force is proportional to the magnitude of charge and the magnetic force is also proportional to magnitude of charge. Both electric and magnetic forces are proportional to the magnitude of charge but option (a) includes only electric force. Thus, option (a) is incorrect.
The magnetic force is proportional to the magnitude of charge and also the electric force is proportional to magnitude of charge .Both the forces are proportional to the magnitude of charge but option (b) only magnetic force. Thus, option (b) is incorrect.
Both the forces are proportional to the magnitude of charge. Thus option (c) is correct.
The exerted forces in magnetic field as well as electric field are proportional to the magnitude of charge that contradicts the option (d). Thus, option (d) is incorrect.
(iii)

The forces which exert force on a negatively charged particle in opposite direction to the force on a positively charged particle.
Answer to Problem 29.8OQ
Option (c) both electric and magnetic forces.
Explanation of Solution
The electric force on a positively charged particle is
Here
The electric force on a negatively charged particle is
Here
From equation (1) and equation (2),
Thus, electric force on the same magnitude of electric charge of opposite nature are equal but opposite in direction.
The magnetic force on a positively charged particle is,
Here
The magnetic force on a negatively charged particle is,
Here,
From equation (3) and (4),
Thus, magnetic force on the same magnitude of electric charge moving with same speed but of opposite nature are equal but opposite in direction.
Conclusion:
Both magnetic force and electric force exert force on negative charge in the opposite direction to the force on positive charge but option (a) includes only electric force. Thus, option (a) is incorrect.
Both magnetic force and electric force exert force on negative charge in the opposite direction to the force on positive charge but option (b) includes only magnetic force. Thus option (b) is incorrect.
Both magnetic force and electric force exert force on negative charge in the opposite direction to the force on positive charge. Thus, option (c) is correct.
Both the forces exert force on negative charge in the opposite direction to the force on positive charge that contradicts the option (d). Thus, option (d) is incorrect.
(iv)

The forces which are non-zero on a stationary object.
Answer to Problem 29.8OQ
Option (a) only electric forces exert non-zero force on stationary object.
Explanation of Solution
The expression for electrical force is,
There is no relation between motion of charged object and electric field because electric field exists for all orientations of charges, whether it is stationary or in motion.
The expression for magnetic force is,
Magnetic force exists only when charges are in motion. Thus for stationary charges the magnetic force is not valid.
Conclusion:
Electrical force is valid for any particle that has charge; it is fundamental force in nature. Thus, option (a) is correct.
Magnetic field is existence for any charged particle in motion. Stationary charged particles have zero magnetic force. Thus option (b) is incorrect.
For a stationary charge only electric force is non-zero and magnetic force is zero that contradicts the option (c). Thus, option (c) is incorrect.
For a stationary charge only electric force is non-zero and magnetic field is zero which is contradictory to the option (d). Thus, option (d) is incorrect.
(v)

The forces which are zero on a moving charge.
Answer to Problem 29.8OQ
Option (d) neither electric nor magnetic force.
Explanation of Solution
The expression for electrical force is,
There is no relation between motion of charged object and electric field because electric field exists for all orientations of charges, whether it is stationary or in motion. If electric field exists then there is a non-zero force on the charged object.
The expression for magnetic force is,
Magnetic force exists only when charges are in motion. Thus for moving charges the magnetic force may be zero if the charge moves either in the direction of the magnetic field or opposite to it.
Conclusion:
Electrical force is valid for any particle that has charge; it is fundamental force in nature. Thus, option (a) is incorrect.
Magnetic field is existence for any charged object in motion. Moving charged objects may have zero magnetic force if the charged object moves along or against the direction of the magnetic field. Thus, option (b) is incorrect.
For a moving charge, electric force is non-zero but the magnetic force may or may not be zero that contradicts the option (c). Thus, option (c) is incorrect.
For a moving charge only electric force is non-zero and magnetic force may or may not be zero. Thus option (d) is correct.
(vi)

The forces proportional to the speed of the charged object.
Answer to Problem 29.8OQ
option (b) magnetic forces only.
Explanation of Solution
The expression for electrical force is,
There is no relation between motion of charged object and the electric field force.
The expression for magnetic force is,
The magnetic force exists only if there is motion and is directly proportional to the speed of the charged particle.
Conclusion:
The electric force exerted on the charged object has no relation with its motion. Thus option (a) is incorrect.
The magnetic force is exerted on a body in motion and is directly proportional to the speed of the object. Thus option (b) is correct.
The electric force exerted on the charged object has no relation with its motion while magnetic force on it is proportional to the speed of the object. Thus, option (c) is incorrect.
The electric force exerted on the charged object has no relation with its motion while magnetic force on it is proportional to the speed of the object that contradicts the option (d). Thus, option (d) is incorrect.
(vii)

The forces on the charged object which can alter its speed.
Answer to Problem 29.8OQ
Option (b) magnetic forces only.
Explanation of Solution
The expression for electrical force is,
There is no relation between motion of charged object and the electric field force.
The expression for magnetic force is,
The magnetic force acts on the perpendicular direction of the motion of the object because it is along the direction of cross product vector of
Conclusion:
There is no relation of motion of the charged object and the electric field force. Thus option (a) is incorrect.
The magnetic force has no change in the speed but it does change the direction of motion of the object. Thus option (b) is correct.
Electric forces have no relation with speed of the charged body while magnetic forces cannot alter speed of the object but it can change its direction of motion. Thus option (c) is incorrect.
Electric forces are independent of any motion of the charged object while magnetic forces can change only the direction of motion of the object. Thus option (d) is incorrect
(viii)

The force whose magnitude depends on the charged object’s direction of motion.
Answer to Problem 29.8OQ
Option (b) magnetic forces only
Explanation of Solution
The expression for electrical force is
There is no relation between motion of charged object and the electric field force.
The expression for magnetic force is
The value of
Conclusion:
The electric field has no relation with the motion of the charged object Thus option (a) is incorrect.
The variation in direction of motion varies the value of
The direction of motion of the charged object affects only the magnetic force but not electric force. Thus option (c) is incorrect as it considers both the forces.
Only the magnetic force is affected by variation in direction of motion of the charged object but not electric force. Thus option (d) is incorrect as it considers neither of the forces.
Want to see more full solutions like this?
Chapter 29 Solutions
Physics for Scientists and Engineers, Technology Update (No access codes included)
- Solve and answer the problem correctly and be sure to check your work. Thank you!!arrow_forwardThe spring in the figure has a spring constant of 1300 N/m. It is compressed 17.0 cm, then launches a 200 g block. The horizontal surface is frictionless, but the block’s coefficient of kinetic friction on the incline is 0.200. What distance d does the block sail through the air?arrow_forwardSolve and answer the problem correctly and be sure to check your work. Thank you!!arrow_forward
- Solve and answer the problem correctly and be sure to check your work. Thank you!!arrow_forwardA 10-m-long glider with a mass of 680 kg (including the passengers) is gliding horizontally through the air at 28 m/s when a 60 kg skydiver drops out by releasing his grip on the glider. What is the glider's speed just after the skydiver lets go?arrow_forwardPROBLEM 2 A cube of mass m is placed in a rotating funnel. (The funnel is rotating around the vertical axis shown in the diagram.) There is no friction between the cube and the funnel but the funnel is rotating at just the right speed needed to keep the cube rotating with the funnel. The cube travels in a circular path of radius r, and the angle between the vertical and the wall of the funnel is 0. Express your answers to parts (b) and (c) in terms of m, r, g, and/or 0. (a) Sketch a free-body diagram for the cube. Show all the forces acting on it, and show the appropriate coordinate system to use for this problem. (b) What is the normal force acting on the cube? FN=mg58 (c) What is the speed v of the cube? (d) If the speed of the cube is different from what you determined in part (c), a force of friction is necessary to keep the cube from slipping in the funnel. If the funnel is rotating slower than it was above, draw a new free-body diagram for the cube to show which way friction…arrow_forward
- Circular turns of radius r in a race track are often banked at an angle θ to allow the cars to achieve higher speeds around the turns. Assume friction is not present. Write an expression for the tan(θ) of a car going around the banked turn in terms of the car's speed v, the radius of the turn r, and g so that the car will not move up or down the incline of the turn. tan(θ) =arrow_forwardThe character Min Min from Arms was a DLC character added to Super Smash Bros. Min Min’s arms are large springs, with a spring constant of 8.53 ⋅ 10^3 N/m, which she uses to punch and fling away her opponents. Min Min pushes her spring arm against Steve, who is not moving, compressing it 1.20 m as shown in figure A. Steve has a mass of 81.6 kg. Assuming she uses only the spring to launch Steve, how fast is Steve moving when the spring is no longer compressed? As Steve goes flying away he goes over the edge of the level, as shown in figure C. What is the magnitude of Steve’s velocity when he is 2.00 m below where he started?arrow_forwardSlinky dog whose middle section is a giant spring with a spring constant of 10.9 N/m. Woody, who has a mass of 0.412 kg, grabs onto the tail end of Slink and steps off the bed with no initial velocity and reaches the floor right as his velocity hits zero again. How high is the bed? What is Woody’s velocity halfway down? Enter just the magnitude of velocity.arrow_forward
- No chatgpt pls will upvotearrow_forwardA positive charge of 91 is located 5.11 m to the left of a negative charge 92. The charges have different magnitudes. On the line through the charges, the net electric field is zero at a spot 2.90 m to the right of the negative charge. On this line there are also two spots where the potential is zero. (a) How far to the left of the negative charge is one spot? (b) How far to the right of the negative charge is the other?arrow_forwardA charge of -3.99 μC is fixed in place. From a horizontal distance of 0.0423 m, a particle of mass 7.31 x 103 kg and charge -9.76 µC is fired with an initial speed of 84.1 m/s directly toward the fixed charge. How far does the particle travel before its speed is zero?arrow_forward
- Physics for Scientists and Engineers: Foundations...PhysicsISBN:9781133939146Author:Katz, Debora M.Publisher:Cengage LearningPrinciples of Physics: A Calculus-Based TextPhysicsISBN:9781133104261Author:Raymond A. Serway, John W. JewettPublisher:Cengage LearningCollege PhysicsPhysicsISBN:9781305952300Author:Raymond A. Serway, Chris VuillePublisher:Cengage Learning
- College PhysicsPhysicsISBN:9781285737027Author:Raymond A. Serway, Chris VuillePublisher:Cengage LearningGlencoe Physics: Principles and Problems, Student...PhysicsISBN:9780078807213Author:Paul W. ZitzewitzPublisher:Glencoe/McGraw-HillClassical Dynamics of Particles and SystemsPhysicsISBN:9780534408961Author:Stephen T. Thornton, Jerry B. MarionPublisher:Cengage Learning





