Concept explainers
Introduction:
The mycelia are the vegetative structure of the
Answer to Problem 1TYK
Correct answer:
The mycelial growth habit leads to a body with a high surface-area-to-volume ratio to have a large surface area for absorption.
Explanation of Solution
Explanation/justification for the correct answer:
Option (a) is given that the mycelial body has a high surface-area-to-volume ratio to have a large surface area for absorption. The fungi feed on the dead and the decaying organism. The long length of mycelia increases its surface area that helps them to easily absorb the food material (nutrients). Hence, Option (a) is correct.
Explanation for incorrect answer:
Option (b) is given that the mycelial body has a high surface-area-to-volume ratio, so that the hyphae that makeup mycelia are long, thin tubes. The large surface area of mycelia helps in absorption of nutrients. So, it is a wrong answer.
Option (c) is given that the mycelial body has a high surface-area-to-volume ratio, so that most hyphae are broken up into compartments by walls called septa, although some exist as single, gigantic cells. The distribution of mycelial body into fragments helps in asexual reproduction and has no relation to the large surface area of the mycelial body. So, it is a wrong answer.
Option (d) is given that mycelial body has a high surface-area-to-volume ratio so, that the hyphae can infiltrate living and dead tissues. The infiltration of living or dead tissue is done by the pores in the septa that separate the hyphae into compartments. So, it is a wrong answer.
Hence, options (b), (c), and (d) are incorrect.
The mycelial growth habit results in the development of high surface-area-to-volume ratio. The large surface area is important, so that the mycelia have increased area for the absorption of nutrients from the dead decaying food source.
Want to see more full solutions like this?
Chapter 29 Solutions
Biological Science (6th Edition)
- answer questions 1-10arrow_forwardAnswer Question 1-9arrow_forwardEx: Mr. Mandarich wanted to see if the color of light shined on a planthad an effect on the number of leaves it had. He gathered a group ofthe same species of plants, gave them the same amount of water, anddid the test for the same amount of time. Only the color of light waschanged. IV:DV:Constants:Control Gr:arrow_forward
- ethical considerations in medical imagingarrow_forwardPlease correct answer and don't used hand raiting and don't used Ai solutionarrow_forward2. In one of the reactions of the citric acid cycle, malate is oxidized to oxaloacetate. When this reaction is considered in isolation, a small amount of malate remains and is not oxidized. The best term to explain this is a. enthalpy b. entropy c. equilibrium d. free energy e. loss of energyarrow_forward
- 18. The citric acid cycle takes place in a. the chloroplasts b. the cytosol c. the inner mitochondrial membrane d. between the two mitochondrial membranes e. the mitochondrial matrix 40 WILarrow_forward8. Most reactions of anaerobic respiration are similar to a. aerobic respiration b. photosynthesis c. lactic acid fermentation d. alcoholic fermentation e. both c and darrow_forward12. Which of the following molecules can absorb light? a. Pigments b. Chlorophyll c. Rhodopsin d. Carotenoids e. All of the abovearrow_forward
- Which of the following proteins or protein complexes is directly required for the targeting of mitochondrial inner membrane multipass proteins, such as metabolite transporters, whose signal sequence is normally not cleaved after import? OA. TIM22 OB. TIM23 C. OXA OD. Mia40 OE SAMarrow_forwardQUESTION 9 An animal cell has been wounded and has a small rupture in its plasma membrane. Which of the following is more likely to happen next? OA. The cell rapidly cleaves by cytokinesis. OB. The rate of receptor-mediati endocytosis is increased. OC. The rate of exocytosis is increased. OD. The rate of pinocytosis is increased.arrow_forwardFor the a subunit of a trimeric G protein, A. a G-protein-coupled receptor GPCR) acts as a guanine nucleotide exchange factor (GEF), whereas a regulator of G protein signaling (RGS) can act as a GTPase-activating protein (GAP). B. a GPCR acts as a GAP, whereas an RGS can act as a GEF. C. both a GPCR and an RGS can act as a GEF. O D. both a GPCR and an RGS can act as a GAP OE. None of the above.arrow_forward
- Biology (MindTap Course List)BiologyISBN:9781337392938Author:Eldra Solomon, Charles Martin, Diana W. Martin, Linda R. BergPublisher:Cengage LearningBiology: The Unity and Diversity of Life (MindTap...BiologyISBN:9781305073951Author:Cecie Starr, Ralph Taggart, Christine Evers, Lisa StarrPublisher:Cengage LearningConcepts of BiologyBiologyISBN:9781938168116Author:Samantha Fowler, Rebecca Roush, James WisePublisher:OpenStax College
- Biology: The Dynamic Science (MindTap Course List)BiologyISBN:9781305389892Author:Peter J. Russell, Paul E. Hertz, Beverly McMillanPublisher:Cengage LearningBiology Today and Tomorrow without Physiology (Mi...BiologyISBN:9781305117396Author:Cecie Starr, Christine Evers, Lisa StarrPublisher:Cengage Learning