a) HCN+CH 3 CO 2 -Na + ----->Na + CN - +CH 3 CO 2 H Interpretation: Whether the reaction, HCN+CH 3 CO 2 -Na + ----->Na + CN - +CH 3 CO 2 H will take place to a significant extent as written is to be stated. Concept introduction: A strong acid will always donate a proton to a strong base. That is, an acid will donate a proton to the conjucate base of a weak acid. In other words the conjucate base of a weaker acid will remove a proton from stronger acid. To determine: Whether the reaction, HCN + CH 3 CO 2 -Na + ----->Na + CN - Â + CH 3 CO 2 H will take place to a significant extent as written.

Question

A covalent bond is the result of the a) b) c) d) e) overlap of two half-filled s orbitals overlap of a half-filled s orbital and a half-filled p orbital overlap of two half-filled p orbitals along their axes parallel overlap of two half-filled parallel p orbitals all of the above

Answer 1

Question

Chapter 2.9, Problem 14P

Interpretation Introduction

a) HCN+CH₃CO₂-Na⁺----->Na⁺CN^-+CH₃CO₂H

Interpretation:

Whether the reaction, HCN+CH₃CO₂-Na⁺----->Na⁺CN^-+CH₃CO₂H will take place to a significant extent as written is to be stated.

Concept introduction:

A strong acid will always donate a proton to a strong base. That is, an acid will donate a proton to the conjucate base of a weak acid. In other words the conjucate base of a weaker acid will remove a proton from stronger acid.

To determine:

Whether the reaction, HCN + CH₃CO₂-Na⁺----->Na⁺CN^-Â + CH₃CO₂H will take place to a significant extent as written.

Interpretation Introduction

b) CH₃CH₂OH+Na⁺CN^------->CH₃CH₂O^-Na⁺+HCN

Interpretation:

Whether the reaction, CH₃CH₂OH+Na⁺CN^------->CH₃CH₂O^-Na⁺+HCN will take place to a significant extent as written is to be stated.

Concept introduction:

A strong acid will always donate a proton to a strong base. That is, an acid will donate a proton to the conjucate base of a weaker acid. In other words the conjucate base of a weaker acid will remove a proton from stronger acid.

To determine:

Whether the reaction, CH₃CH₂OH+Na⁺CN^------->CH₃CH₂O^-Na⁺+ HCN will take place to a significant extent as written.

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