EBK ALGEBRA 2
EBK ALGEBRA 2
11th Edition
ISBN: 9780544714304
Author: Larson
Publisher: HMH PUB
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Chapter 2.8, Problem 6MRPS
Solution

(a.)

A labelled diagram of the sculpture in terms of x .

A labelled diagram of the sculpture in terms of x, is given as follows:

  EBK ALGEBRA 2, Chapter 2.8, Problem 6MRPS , additional homework tip  1

Given:

A sculpture is shaped as a pyramid with a square base.

The height of the pyramid is 4 inches less than the length of a side of the base.

The volume of the sculpture is 200 cubic inches.

Concept used:

Assuming an unknown dimension as x and determining the other dimensions in terms of x , a labelled diagram of the given figure can be constructed.

Calculation:

Let x represent the length (in inches) of a side of the sculpture’s base.

It is given that the height of the pyramid is 4 inches less than the length of a side of the base.

Then, the height of the pyramid shaped sculpture is x4 .

Now, a labelled diagram of the sculpture is given as follows,

  EBK ALGEBRA 2, Chapter 2.8, Problem 6MRPS , additional homework tip  2

Conclusion:

A labelled diagram of the sculpture in terms of x, is given as follows:

  EBK ALGEBRA 2, Chapter 2.8, Problem 6MRPS , additional homework tip  3

(b.)

A function that gives the volume V of the sculpture, in terms of x .

It has been determined that the function that gives the volume V of the sculpture, in terms of x , is V=13x2x4 .

Given:

A sculpture is shaped as a pyramid with a square base.

The height of the pyramid is 4 inches less than the length of a side of the base.

The volume of the sculpture is 200 cubic inches.

Concept used:

The volume V of a pyramid with square base equals one-third the product of the area of the square base and the height.

Calculation:

As assumed previously, x represents the length (in inches) of a side of the sculpture’s base and the height (in inches) of the pyramid shaped sculpture is x4 .

Then, the area of the square base (in square inches) is given as x2 .

Now, according to the discussed formula, the volume V of the pyramid shaped sculpture (in cubic inches) is given as,

  V=13×x2×x4

Rewriting,

  V=13x2x4

This is the required function that gives the volume V of the sculpture, in terms of x .

Conclusion:

It has been determined that the function that gives the volume V of the sculpture, in terms of x , is V=13x2x4 .

(c.)

The graph of the function obtained in part (b) and the estimate of the value of x for the sculpture.

The graph of the function obtained in part (b) is given as:

  EBK ALGEBRA 2, Chapter 2.8, Problem 6MRPS , additional homework tip  4

It has been determined that the estimate of the value of x for the sculpture is x=10 .

Given:

A sculpture is shaped as a pyramid with a square base.

The height of the pyramid is 4 inches less than the length of a side of the base.

The volume of the sculpture is 200 cubic inches.

Concept used:

If either the abscissa or the ordinate is known, the corresponding ordinate or the abscissa can be obtained from the graph of the function.

Calculation:

The function obtained in part (b) is,

  V=13x2x4

The graph of this function is given as,

  EBK ALGEBRA 2, Chapter 2.8, Problem 6MRPS , additional homework tip  5

It is given that the volume of the sculpture is 200 cubic inches.

So, V=200 .

It can be seen from the graph that V=200 corresponds to x=10 .

This is the required estimate.

Conclusion:

The graph of the function obtained in part (b) is given as:

  EBK ALGEBRA 2, Chapter 2.8, Problem 6MRPS , additional homework tip  6

It has been determined that the estimate of the value of x for the sculpture is x=10 .

(d.)

The value of x , by writing and solving an equation, its comparison with the estimate from part (c) and the dimensions of the sculpture.

The value of x , by writing and solving an equation, has been determined to be x=10 , which is equal to its estimate from part (c).

It has been determined that the base of the sculpture is 10 inches by 10 inches and the height of the sculpture is 6 inches.

Given:

A sculpture is shaped as a pyramid with a square base.

The height of the pyramid is 4 inches less than the length of a side of the base.

The volume of the sculpture is 200 cubic inches.

Concept used:

An equation can be solved by factorizing.

Calculation:

The function obtained in part (b) is,

  V=13x2x4

It is given that the volume of the sculpture is 200 cubic inches.

So, V=200 .

Put V=200 in V=13x2x4 to get,

  200=13x2x4

Simplifying,

  x2x4=600

On further simplification,

  x34x2=600

Finally,

  x34x2600=0

Factorizing,

  x310x2+10x24x260x+60x600=0x310x2+6x260x+60x600=0x2x10+6xx10+60x10=0x10x2+6x+60=0

Note that the discriminant of x2+6x+60 is given as,

  624160=36240<0

This implies that the roots of x2+6x+60=0 are complex.

So, the only real root of the obtained equation is x=10 .

Now, the estimated value from part (c.) was also x=10 .

As assumed in part (a), the length of a side of the square base is x=10 inches and the height of the pyramid is x4=104=6 inches.

So, the base of the sculpture is 10 inches by 10 inches and the height of the sculpture is 6 inches.

Conclusion:

The value of x , by writing and solving an equation, has been determined to be x=10 , which is equal to its estimate from part (c).

It has been determined that the base of the sculpture is 10 inches by 10 inches and the height of the sculpture is 6 inches.

Chapter 2 Solutions

EBK ALGEBRA 2

Ch. 2.1 - Prob. 3ECh. 2.1 - Prob. 4ECh. 2.1 - Prob. 5ECh. 2.1 - Prob. 6ECh. 2.1 - Prob. 7ECh. 2.1 - Prob. 8ECh. 2.1 - Prob. 9ECh. 2.1 - Prob. 10ECh. 2.1 - Prob. 11ECh. 2.1 - Prob. 12ECh. 2.1 - Prob. 13ECh. 2.1 - Prob. 14ECh. 2.1 - Prob. 15ECh. 2.1 - Prob. 16ECh. 2.1 - Prob. 17ECh. 2.1 - Prob. 18ECh. 2.1 - Prob. 19ECh. 2.1 - Prob. 20ECh. 2.1 - Prob. 21ECh. 2.1 - Prob. 22ECh. 2.1 - Prob. 23ECh. 2.1 - Prob. 24ECh. 2.1 - Prob. 25ECh. 2.1 - Prob. 26ECh. 2.1 - Prob. 27ECh. 2.1 - Prob. 28ECh. 2.1 - Prob. 29ECh. 2.1 - Prob. 30ECh. 2.1 - Prob. 31ECh. 2.1 - Prob. 32ECh. 2.1 - Prob. 33ECh. 2.1 - Prob. 34ECh. 2.1 - Prob. 35ECh. 2.1 - Prob. 36ECh. 2.1 - Prob. 37ECh. 2.1 - Prob. 38ECh. 2.1 - Prob. 39ECh. 2.1 - Prob. 40ECh. 2.1 - Prob. 41ECh. 2.1 - Prob. 42ECh. 2.1 - Prob. 43ECh. 2.1 - Prob. 44ECh. 2.1 - Prob. 45ECh. 2.1 - Prob. 46ECh. 2.1 - Prob. 47ECh. 2.1 - Prob. 48ECh. 2.1 - Prob. 49PSCh. 2.1 - Prob. 50PSCh. 2.1 - Prob. 51PSCh. 2.1 - Prob. 52PSCh. 2.1 - Prob. 53PSCh. 2.1 - Prob. 54PSCh. 2.1 - Prob. 1DCCh. 2.1 - 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Prob. 7MRPSCh. 2.6 - Prob. 1GPCh. 2.6 - Prob. 2GPCh. 2.6 - Prob. 3GPCh. 2.6 - Prob. 4GPCh. 2.6 - Prob. 5GPCh. 2.6 - Prob. 6GPCh. 2.6 - Prob. 7GPCh. 2.6 - Prob. 1ECh. 2.6 - Prob. 2ECh. 2.6 - Prob. 3ECh. 2.6 - Prob. 4ECh. 2.6 - Prob. 5ECh. 2.6 - Prob. 6ECh. 2.6 - Prob. 7ECh. 2.6 - Prob. 8ECh. 2.6 - Prob. 9ECh. 2.6 - Prob. 10ECh. 2.6 - Prob. 11ECh. 2.6 - Prob. 12ECh. 2.6 - Prob. 13ECh. 2.6 - Prob. 14ECh. 2.6 - Prob. 15ECh. 2.6 - Prob. 16ECh. 2.6 - Prob. 17ECh. 2.6 - Prob. 18ECh. 2.6 - Prob. 19ECh. 2.6 - Prob. 20ECh. 2.6 - Prob. 21ECh. 2.6 - Prob. 22ECh. 2.6 - Prob. 23ECh. 2.6 - Prob. 24ECh. 2.6 - Prob. 25ECh. 2.6 - Prob. 26ECh. 2.6 - Prob. 27ECh. 2.6 - Prob. 28ECh. 2.6 - Prob. 29ECh. 2.6 - Prob. 30ECh. 2.6 - Prob. 31ECh. 2.6 - Prob. 32ECh. 2.6 - Prob. 33ECh. 2.6 - Prob. 34ECh. 2.6 - Prob. 35ECh. 2.6 - Prob. 36ECh. 2.6 - Prob. 37ECh. 2.6 - Prob. 38ECh. 2.6 - Prob. 39ECh. 2.6 - Prob. 40ECh. 2.6 - Prob. 41ECh. 2.6 - Prob. 42ECh. 2.6 - Prob. 43ECh. 2.6 - Prob. 44ECh. 2.6 - Prob. 45PSCh. 2.6 - Prob. 46PSCh. 2.6 - Prob. 47PSCh. 2.6 - Prob. 48PSCh. 2.6 - Prob. 49PSCh. 2.6 - Prob. 50PSCh. 2.6 - Prob. 51PSCh. 2.6 - Prob. 1QCh. 2.6 - Prob. 2QCh. 2.6 - Prob. 3QCh. 2.6 - Prob. 4QCh. 2.6 - Prob. 5QCh. 2.6 - Prob. 6QCh. 2.6 - Prob. 7QCh. 2.6 - Prob. 8QCh. 2.6 - Prob. 9QCh. 2.6 - Prob. 10QCh. 2.6 - Prob. 11QCh. 2.6 - Prob. 12QCh. 2.6 - Prob. 13QCh. 2.6 - Prob. 1PCh. 2.6 - Prob. 2PCh. 2.6 - Prob. 3PCh. 2.6 - Prob. 4PCh. 2.7 - Prob. 1GPCh. 2.7 - Prob. 2GPCh. 2.7 - Prob. 3GPCh. 2.7 - Prob. 4GPCh. 2.7 - Prob. 5GPCh. 2.7 - Prob. 6GPCh. 2.7 - Prob. 7GPCh. 2.7 - Prob. 8GPCh. 2.7 - Prob. 9GPCh. 2.7 - Prob. 10GPCh. 2.7 - Prob. 11GPCh. 2.7 - Prob. 12GPCh. 2.7 - Prob. 1ECh. 2.7 - Prob. 2ECh. 2.7 - Prob. 3ECh. 2.7 - Prob. 4ECh. 2.7 - Prob. 5ECh. 2.7 - Prob. 6ECh. 2.7 - Prob. 7ECh. 2.7 - Prob. 8ECh. 2.7 - Prob. 9ECh. 2.7 - Prob. 10ECh. 2.7 - Prob. 11ECh. 2.7 - Prob. 12ECh. 2.7 - Prob. 13ECh. 2.7 - Prob. 14ECh. 2.7 - Prob. 15ECh. 2.7 - Prob. 16ECh. 2.7 - Prob. 17ECh. 2.7 - Prob. 18ECh. 2.7 - Prob. 19ECh. 2.7 - 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Prob. 3ECh. 2.8 - Prob. 4ECh. 2.8 - Prob. 5ECh. 2.8 - Prob. 6ECh. 2.8 - Prob. 7ECh. 2.8 - Prob. 8ECh. 2.8 - Prob. 9ECh. 2.8 - Prob. 10ECh. 2.8 - Prob. 11ECh. 2.8 - Prob. 12ECh. 2.8 - Prob. 13ECh. 2.8 - Prob. 14ECh. 2.8 - Prob. 15ECh. 2.8 - Prob. 16ECh. 2.8 - Prob. 17ECh. 2.8 - Prob. 18ECh. 2.8 - Prob. 19ECh. 2.8 - Prob. 20ECh. 2.8 - Prob. 21ECh. 2.8 - Prob. 22ECh. 2.8 - Prob. 23ECh. 2.8 - Prob. 24ECh. 2.8 - Prob. 25ECh. 2.8 - Prob. 26ECh. 2.8 - Prob. 27ECh. 2.8 - Prob. 28ECh. 2.8 - Prob. 29ECh. 2.8 - Prob. 30ECh. 2.8 - Prob. 31ECh. 2.8 - Prob. 32ECh. 2.8 - Prob. 33ECh. 2.8 - Prob. 34ECh. 2.8 - Prob. 35ECh. 2.8 - Prob. 36ECh. 2.8 - Prob. 37ECh. 2.8 - Prob. 38ECh. 2.8 - Prob. 39PSCh. 2.8 - Prob. 40PSCh. 2.8 - Prob. 41PSCh. 2.8 - Prob. 42PSCh. 2.8 - Prob. 43PSCh. 2.8 - Prob. 44PSCh. 2.8 - Prob. 1QCh. 2.8 - Prob. 2QCh. 2.8 - Prob. 3QCh. 2.8 - Prob. 4QCh. 2.8 - Prob. 5QCh. 2.8 - Prob. 6QCh. 2.8 - Prob. 7QCh. 2.8 - Prob. 8QCh. 2.8 - Prob. 9QCh. 2.8 - Prob. 10QCh. 2.8 - Prob. 1MRPSCh. 2.8 - Prob. 2MRPSCh. 2.8 - Prob. 3MRPSCh. 2.8 - Prob. 4MRPSCh. 2.8 - Prob. 5MRPSCh. 2.8 - Prob. 6MRPSCh. 2.8 - Prob. 7MRPSCh. 2 - Prob. 1VECh. 2 - Prob. 2VECh. 2 - Prob. 3VECh. 2 - Prob. 4VECh. 2 - Prob. 5REAECh. 2 - Prob. 6REAECh. 2 - Prob. 7REAECh. 2 - Prob. 8REAECh. 2 - Prob. 9REAECh. 2 - Prob. 10REAECh. 2 - Prob. 11REAECh. 2 - Prob. 12REAECh. 2 - Prob. 13REAECh. 2 - Prob. 14REAECh. 2 - Prob. 15REAECh. 2 - Prob. 16REAECh. 2 - Prob. 17REAECh. 2 - Prob. 18REAECh. 2 - Prob. 19REAECh. 2 - Prob. 20REAECh. 2 - Prob. 21REAECh. 2 - Prob. 22REAECh. 2 - Prob. 23REAECh. 2 - Prob. 24REAECh. 2 - Prob. 25REAECh. 2 - Prob. 26REAECh. 2 - Prob. 27REAECh. 2 - Prob. 28REAECh. 2 - Prob. 29REAECh. 2 - Prob. 30REAECh. 2 - Prob. 31REAECh. 2 - Prob. 32REAECh. 2 - Prob. 33REAECh. 2 - Prob. 34REAECh. 2 - Prob. 35REAECh. 2 - Prob. 36REAECh. 2 - Prob. 37REAECh. 2 - Prob. 38REAECh. 2 - Prob. 39REAECh. 2 - Prob. 40REAECh. 2 - Prob. 1TCh. 2 - Prob. 2TCh. 2 - Prob. 3TCh. 2 - Prob. 4TCh. 2 - Prob. 5TCh. 2 - Prob. 6TCh. 2 - Prob. 7TCh. 2 - Prob. 8TCh. 2 - Prob. 9TCh. 2 - Prob. 10TCh. 2 - Prob. 11TCh. 2 - Prob. 12TCh. 2 - Prob. 13TCh. 2 - Prob. 14TCh. 2 - Prob. 15TCh. 2 - Prob. 16TCh. 2 - Prob. 17TCh. 2 - Prob. 18TCh. 2 - Prob. 19TCh. 2 - Prob. 20TCh. 2 - Prob. 21TCh. 2 - Prob. 22TCh. 2 - Prob. 23TCh. 2 - Prob. 24TCh. 2 - Prob. 25TCh. 2 - Prob. 26TCh. 2 - Prob. 27TCh. 2 - Prob. 28TCh. 2 - Prob. 29TCh. 2 - Prob. 1PCh. 2 - Prob. 2PCh. 2 - Prob. 1TPCh. 2 - Prob. 2TPCh. 2 - Prob. 3TPCh. 2 - Prob. 4TPCh. 2 - Prob. 5TPCh. 2 - Prob. 6TPCh. 2 - Prob. 7TPCh. 2 - Prob. 8TPCh. 2 - Prob. 9TPCh. 2 - Prob. 10TPCh. 2 - Prob. 11TPCh. 2 - Prob. 12TPCh. 2 - Prob. 13TPCh. 2 - Prob. 14TPCh. 2 - Prob. 15TPCh. 2 - Prob. 16TPCh. 2 - Prob. 17TPCh. 2 - Prob. 18TPCh. 2 - Prob. 19TPCh. 2 - Prob. 20TPCh. 2 - Prob. 21TP
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