College Physics: A Strategic Approach (3rd Edition)
3rd Edition
ISBN: 9780321879721
Author: Randall D. Knight (Professor Emeritus), Brian Jones, Stuart Field
Publisher: PEARSON
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Chapter 28, Problem 32P
To determine
The fraction of paramecium’s length the wavelength represent.
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A paramecium is covered with motile hairs called cilia that propel it at a speed of 1 mm/s. If the paramecium has a volume of 2 x 10-13 m3 and a density equal to that of water, what is its de Broglie wavelength when in motion? What fraction of the paramecium’s 150 μm length does this wavelength represent?
A proton is moving with a speed of v = 1.20 x 10° m/s. What is its de Broglie wavelength (in m)?
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The electron beam in a scanning electron microscope (SEM) can have an energy ranging from 0.2 keV to 40 keV.
(Note: an eV is an electronvolt, the measure of an amount of kinetic energy for a single electron.
1 eV = 1.60218×10−19 J and 1 J = 1 kg m2 s−2).
What is the de Broglie wavelength of the electron beam in the SEM when the electrons are accelerated to kinetic energy of 6.6 keV?
Chapter 28 Solutions
College Physics: A Strategic Approach (3rd Edition)
Ch. 28 - Prob. 1CQCh. 28 - Prob. 2CQCh. 28 - Prob. 3CQCh. 28 - Prob. 4CQCh. 28 - Prob. 5CQCh. 28 - Prob. 6CQCh. 28 - Prob. 7CQCh. 28 - Prob. 8CQCh. 28 - Prob. 9CQCh. 28 - Prob. 10CQ
Ch. 28 - Prob. 11CQCh. 28 - Prob. 12CQCh. 28 - Prob. 13CQCh. 28 - Prob. 14CQCh. 28 - Prob. 15CQCh. 28 - Prob. 16CQCh. 28 - Prob. 17CQCh. 28 - Prob. 18CQCh. 28 - Prob. 19CQCh. 28 - Prob. 20CQCh. 28 - Prob. 21CQCh. 28 - Prob. 22CQCh. 28 - Prob. 23CQCh. 28 - Prob. 24CQCh. 28 - Prob. 25CQCh. 28 - Prob. 26MCQCh. 28 - Prob. 27MCQCh. 28 - Prob. 28MCQCh. 28 - Prob. 29MCQCh. 28 - Prob. 30MCQCh. 28 - Prob. 31MCQCh. 28 - Prob. 32MCQCh. 28 - Prob. 33MCQCh. 28 - Prob. 34MCQCh. 28 - Prob. 35MCQCh. 28 - Prob. 1PCh. 28 - Prob. 2PCh. 28 - Prob. 3PCh. 28 - Prob. 4PCh. 28 - Prob. 5PCh. 28 - Prob. 6PCh. 28 - Prob. 7PCh. 28 - Prob. 8PCh. 28 - Prob. 9PCh. 28 - Prob. 10PCh. 28 - Prob. 11PCh. 28 - Prob. 12PCh. 28 - Prob. 13PCh. 28 - Prob. 14PCh. 28 - Prob. 15PCh. 28 - Prob. 16PCh. 28 - Prob. 17PCh. 28 - Prob. 18PCh. 28 - Prob. 19PCh. 28 - Prob. 20PCh. 28 - Prob. 21PCh. 28 - Prob. 22PCh. 28 - Prob. 23PCh. 28 - Prob. 24PCh. 28 - Prob. 25PCh. 28 - Prob. 26PCh. 28 - Prob. 27PCh. 28 - Prob. 28PCh. 28 - Prob. 29PCh. 28 - Prob. 30PCh. 28 - Prob. 31PCh. 28 - Prob. 32PCh. 28 - Prob. 33PCh. 28 - Prob. 34PCh. 28 - Prob. 35PCh. 28 - Prob. 36PCh. 28 - Prob. 37PCh. 28 - Prob. 38PCh. 28 - Prob. 39PCh. 28 - Prob. 40PCh. 28 - Prob. 41PCh. 28 - Prob. 42PCh. 28 - Prob. 43PCh. 28 - Prob. 44PCh. 28 - Prob. 45PCh. 28 - Prob. 46PCh. 28 - Prob. 47PCh. 28 - Prob. 48PCh. 28 - Prob. 49PCh. 28 - Prob. 50GPCh. 28 - Prob. 51GPCh. 28 - Prob. 52GPCh. 28 - Prob. 53GPCh. 28 - Prob. 54GPCh. 28 - Prob. 55GPCh. 28 - Prob. 56GPCh. 28 - Prob. 57GPCh. 28 - Prob. 58GPCh. 28 - Prob. 59GPCh. 28 - Prob. 60GPCh. 28 - Prob. 61GPCh. 28 - Prob. 62GPCh. 28 - Prob. 63GPCh. 28 - Prob. 64GPCh. 28 - Prob. 65GPCh. 28 - Prob. 66GPCh. 28 - Prob. 67GPCh. 28 - Prob. 68GPCh. 28 - Prob. 69GPCh. 28 - Prob. 70GPCh. 28 - Prob. 71GPCh. 28 - Prob. 72GPCh. 28 - Prob. 73GPCh. 28 - Prob. 74GPCh. 28 - Prob. 75GPCh. 28 - Prob. 76GPCh. 28 - Prob. 77GPCh. 28 - Prob. 78GPCh. 28 - Prob. 79GPCh. 28 - Prob. 80GPCh. 28 - Prob. 81GPCh. 28 - Prob. 82GPCh. 28 - Prob. 83GPCh. 28 - Prob. 84GPCh. 28 - Prob. 85MSPPCh. 28 - Prob. 86MSPPCh. 28 - Prob. 87MSPPCh. 28 - Prob. 88MSPP
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Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.Similar questions
- A 900-W microwave generator in an oven generates energy quanta of frequency 2560 MHz. (a) How many energy quanta does it emit per second? (b) How many energy quanta must be absorbed by a pasta dish placed in the radiation cavity to increase its temperature by 45.0 K? Assume that the dish has a mass of 0.5 kg and that its specific heat is 0.9 kcal/kg • K. (c) Assume that all energy quanta emitted by the generator are absorbed by the pasta dish. How long must we wait until the dish in (b) is ready?arrow_forward(a) What is the energy of an electron whose de Brogue wavelength is that of a photon of yellow light with wavelength 590 nm? (b) What is the de Brogue wavelength of an electron whose energy is that of the photon of yellow light?arrow_forward(a) Calculate the wavelength of a photon that has the same momentum as a proton moving with 1% of the speed of light in a vacuum. (b) What is the energy of this photon in MeV? (c) What is the kinetic energy of the proton in MeV?arrow_forward
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- An electron and a 5.20 kg bowling ball each have 4.55 eV of kinetic energy. HINT (a) Calculate e, the de Broglie wavelength of the electron (in m). (b) Calculate 1p, the de Broglie wavelength of the bowling ball (in m). m (c) Calculate the wavelength i, of a 4.55 eV photon (in m). marrow_forward(a) What is the de Broglie wavelength (in m) of a proton moving at a speed of 3.30 × 104 m/s? m (b) What is the de Broglie wavelength (in m) of a proton moving at a speed of 1.92 × 108 m/s? m m (c) What is the de Broglie wavelength for an electron having a kinetic energy of 3.15 MeV?arrow_forwardA neutron of mass 1.675 × 10-27 kg has a de Broglie wavelength of 7.8x10-12 m. What is the kinetic energy (in eV) of this non-relativistic neutron? Please give your answer with two decimal places. 1 eV = 1.60 × 10-19 J, h = 6.626 × 10-34 J ∙ s.arrow_forward
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