For each demand equation in Exercises 23-30, differentiate implicitly to
d
p
/
d
x
.
(
p
+
4
)
(
x
+
3
)
=
48
With integration, one of the major concepts of calculus. Differentiation is the derivative or rate of change of a function with respect to the independent variable.
A company selling widgets has found that the number of items sold, x, depends upon the price, p at which
30000
they're sold, according the equation =
(0.6p + 1)²
Due to inflation and increasing health benefit costs, the company has been increasing the price by $0.03
per month. Find the rate at which revenue is changing when the company is selling widgets at $3 each.
Revenue is changing at a rate of
dollars per month.
Graph each function using the reference points (-1,1) (0,0) (1,1)
Create multiple representations (x-> y table, graph, and equation) of the function g(x)= 2/x. Then make at least 3 summary statements.
University Calculus: Early Transcendentals (4th Edition)
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