(a)
Interpretation:
The name of the ionic compound formed from zinc and oxygen is to be determined.
Concept introduction:
Ionic compounds are those compounds which are composed of ions. An ionic bond is formed when two ions of opposite charges combine due to the electrostatic forces of attraction. Ionic compounds are formed when a metal reacts with a non-metal. Metals have the tendency to lose electrons. Metals lose electrons to form cations whereas non-metals gain electrons to form anions. Cations and anions attract each other and form ionic compounds.
(b)
Interpretation:
The name of the ionic compound formed from bromine and silver is to be determined.
Concept introduction:
Ionic compounds are those compounds which are composed of ions. An ionic bond is formed when two ions of opposite charges combine due to the electrostatic forces of attraction. Ionic compounds are formed when a metal reacts with a non-metal. Metals have the tendency to lose electrons. Metals lose electrons to form cations whereas non-metals gain electrons to form anions. Cations and anions attract each other and form ionic compounds.
(c)
Interpretation:
The name of the ionic compound formed from lithium and chlorine is to be determined.
Concept introduction:
Ionic compounds are those compounds which are composed of ions. An ionic bond is formed when two ions of opposite charges combine due to the electrostatic forces of attraction. Ionic compounds are formed when a metal reacts with a non-metal. Metals have the tendency to lose electrons. Metals lose electrons to form cations whereas non-metals gain electrons to form anions. Cations and anions attract each other and form ionic compounds.
(d)
Interpretation:
The name of the ionic compound formed from sulfur and aluminium is to be determined.
Concept introduction:
Ionic compounds are those compounds which are composed of ions. An ionic bond is formed when two ions of opposite charges combine due to the electrostatic forces of attraction. Ionic compounds are formed when a metal reacts with a non-metal. Metals have the tendency to lose electrons. Metals lose electrons to form cations whereas non-metals gain electrons to form anions. Cations and anions attract each other and form ionic compounds.
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Chapter 2 Solutions
CHEMISTRY: MOLECULAR...(LL) W/ALEKS
- I don't understand what to put for final step. Does that just mean termination? And would a radical form when I add bromine to ch2 between the rings?arrow_forwardNonearrow_forward11 1 Which one of the following compounds would show a proton NMR signal at the highest chemical shift? (7pts) cl @amitabh CI CI d) Cl CICIarrow_forward
- Nonearrow_forwardH2SO4 (cat.), H₂O 100 °C NH₂arrow_forwardX Draw the major products of the elimination reaction below. If elimination would not occur at a significant rate, check the box under the drawing area instead. ది www. Cl + OH Elimination will not occur at a significant rate. Click and drag to start drawing a structure.arrow_forward
- Nonearrow_forward1A H 2A Li Be Use the References to access important values if needed for this question. 8A 3A 4A 5A 6A 7A He B C N O F Ne Na Mg 3B 4B 5B 6B 7B 8B-1B 2B Al Si P 1B 2B Al Si P S Cl Ar K Ca Sc Ti V Cr Mn Fe Co Ni Cu Zn Ga Ge As Se Br Kr Rb Sr Y Zr Nb Mo Tc Ru Rh Pd Ag Cd In Sn Sb Te I Xe * Cs Ba La Hf Ta W Re Os Ir Pt Au Hg Tl Pb Bi Po At Rn Fr Ra Ac Rf Ha ****** Ce Pr Nd Pm Sm Eu Gd Tb Dy Ho Er Tm Yb Lu Th Pa U Np Pu Am Cm Bk Cf Es Fm Md No Lr Analyze the following reaction by looking at the electron configurations given below each box. Put a number and a symbol in each box to show the number and kind of the corresponding atom or ion. Use the smallest integers possible. cation anion + + Shell 1: 2 Shell 2: 8 Shell 3: 1 Shell 1 : 2 Shell 2 : 6 Shell 1 : 2 Shell 2: 8 Shell 1: 2 Shell 2: 8arrow_forwardNonearrow_forward
- IV. Show the detailed synthesis strategy for the following compounds. a. CH3CH2CH2CH2Br CH3CH2CCH2CH2CH3arrow_forwardDo the electrons on the OH participate in resonance with the ring through a p orbital? How many pi electrons are in the ring, 4 (from the two double bonds) or 6 (including the electrons on the O)?arrow_forwardPredict and draw the product of the following organic reaction:arrow_forward
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