The number of nucleosomes present in a gene with 10 , 000 base pairs is to be determined. Concept Introduction: The species formed by the conjunction of a section of DNA and histone proteins is called a nucleosome. Each nucleosome contains 146 base pairs and each nucleosome is separated by a linker of about 50 base pairs of DNA. Thus, there are a total of 196 base pairs per nucleosome.

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Answer 1

Question

Chapter 27.9, Problem 12P

Interpretation Introduction

Interpretation:

The number of nucleosomes present in a gene with 10,000 base pairs is to be determined.

Concept Introduction:

The species formed by the conjunction of a section of DNA and histone proteins is called a nucleosome.

Each nucleosome contains 146 base pairs and each nucleosome is separated by a linker of about 50 base pairs of DNA. Thus, there are a total of 196 base pairs per nucleosome.

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Answer 2

Question

Chapter 27.9, Problem 12P

Interpretation Introduction

Interpretation:

The number of nucleosomes present in a gene with 10,000 base pairs is to be determined.

Concept Introduction:

The species formed by the conjunction of a section of DNA and histone proteins is called a nucleosome.

Each nucleosome contains 146 base pairs and each nucleosome is separated by a linker of about 50 base pairs of DNA. Thus, there are a total of 196 base pairs per nucleosome.

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Answer 3

Question

Chapter 27.9, Problem 12P

Interpretation Introduction

Interpretation:

The number of nucleosomes present in a gene with 10,000 base pairs is to be determined.

Concept Introduction:

The species formed by the conjunction of a section of DNA and histone proteins is called a nucleosome.

Each nucleosome contains 146 base pairs and each nucleosome is separated by a linker of about 50 base pairs of DNA. Thus, there are a total of 196 base pairs per nucleosome.

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Answer 4

Question

Chapter 27.9, Problem 12P

Interpretation Introduction

Interpretation:

The number of nucleosomes present in a gene with 10,000 base pairs is to be determined.

Concept Introduction:

The species formed by the conjunction of a section of DNA and histone proteins is called a nucleosome.

Each nucleosome contains 146 base pairs and each nucleosome is separated by a linker of about 50 base pairs of DNA. Thus, there are a total of 196 base pairs per nucleosome.

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Answer 5

Chapter 27.9, Problem 12P

Interpretation Introduction

Interpretation:

The number of nucleosomes present in a gene with 10,000 base pairs is to be determined.

Concept Introduction:

The species formed by the conjunction of a section of DNA and histone proteins is called a nucleosome.

Each nucleosome contains 146 base pairs and each nucleosome is separated by a linker of about 50 base pairs of DNA. Thus, there are a total of 196 base pairs per nucleosome.

Answer 6

Chapter 27.9, Problem 12P

Interpretation Introduction

Interpretation:

The number of nucleosomes present in a gene with 10,000 base pairs is to be determined.

Concept Introduction:

The species formed by the conjunction of a section of DNA and histone proteins is called a nucleosome.

Each nucleosome contains 146 base pairs and each nucleosome is separated by a linker of about 50 base pairs of DNA. Thus, there are a total of 196 base pairs per nucleosome.

Answer 7

Chapter 27.9, Problem 12P

Interpretation Introduction

Interpretation:

The number of nucleosomes present in a gene with 10,000 base pairs is to be determined.

Concept Introduction:

The species formed by the conjunction of a section of DNA and histone proteins is called a nucleosome.

Each nucleosome contains 146 base pairs and each nucleosome is separated by a linker of about 50 base pairs of DNA. Thus, there are a total of 196 base pairs per nucleosome.

Answer 8

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Answer 11

Ch. 27.1 - Problem 27.1 Write a structural formula for the...Ch. 27.1 - Prob. 2P Ch. 27.1 - Prob. 3P Ch. 27.2 - Prob. 4P Ch. 27.3 - Prob. 5P Ch. 27.3 - Prob. 6P Ch. 27.5 - Prob. 7P Ch. 27.5 - Prob. 8P Ch. 27.5 - Prob. 9P Ch. 27.6 - Prob. 10P

Solution Summary: The author explains that the number of nucleosomes present in a gene with 10,000 base pairs is to be determined.

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