Physics for Scientists and Engineers, Vol. 1
6th Edition
ISBN: 9781429201322
Author: Paul A. Tipler, Gene Mosca
Publisher: Macmillan Higher Education
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Chapter 27, Problem 5P
To determine
The differences and similarities between the Gauss’s law for magnetism and Gauss’s law for electricity.
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Chapter 27 Solutions
Physics for Scientists and Engineers, Vol. 1
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- Consider an electron rotating in a circular orbit of radius r. Show that the magnitudes of the magnetic dipole moment and the angular momentum L of the electron are related by: = L=e2marrow_forwardWhat is the maximum force on an aluminum rod with a 0.100-μC charge that you pass between the poles of a 1.50-T permanent magnet at a speed of 5.00 m/s? In what direction is the force?arrow_forwardAn electron in J. J. Thomson's charge-to-mass apparatus moves perpendicular to a B-field along a circular path of radius 13.10 cm. If imposition of an E-field of 17.80 kV/m makes the path straight, what is the value of B?arrow_forward
- What is the maximum force (in N) on an aluminum rod with a 0.200 µC charge that you pass between the poles of a 2.40 T permanent magnet at a speed of 4.50 m/s?arrow_forwardAn electron encounters an E and B fields.B field is given by B = 0.1 j T.Electron experiences a force F = (9.6 x 10^-14 i – 9.6 x 10^-14 k)Find the electric field encountered by the electron. The velocity of the electron isv = 5 x 10^6 i m/s.arrow_forwardConsider the symmetrically arrange charges in the figure which qa=qb=-1.25 uC,& qc= qd= +1.25uC. Calculate the magnet who of the electric field E at the location of q given that the square is 6.55 cm on a side. E= N/C two particles have charges -7.97×10 ^-6 and 4.39×10 ^ -6C respectively and are 0.0284 meters apart. What is the magnitude F of the force Either particle exerts on the other? F= N  supposed to different particles, each having the identical positive charge q3, are separated by the same 0.0284 meters. The force between them is measured to be the same as for the for first pair What is q3? q3= Carrow_forward
- Calculate the magnetic dipole moment of Earth. Assume that it is produced by charges flowing in Earth's molten outer core. The current is measured to be 2.08 x 109 A and the radius of the charges' path is 3.50x103 km.arrow_forwardWhat is the maximum force on an aluminum rod with a 0.100-μC charge that you pass between the poles of a 1.50-Tesla permanent magnet directed toward the +Y, and at a speed of 5.00 m/s directed to the -X?arrow_forward(a) A 0.140-kg baseball, pitched at 40.0 m/s horizontally and perpendicular to the Earth’s horizontal 5.00×10−5 T field, has a 100-nC charge on it. What distance is it deflected from its path by the magnetic force, after traveling 30.0 m horizontally? (b) Would you suggest this as a secret technique for a pitcher to throw curve balls?arrow_forward
- The intensity of the electric field measured on any day at points close to the earth is 100 N / C and its direction is radially inward. When this value is the same for every point of the world, Find the total load on Earth.arrow_forwardIn previous chapters, we looked at how to determine the electric dipole moment for charge configurations that were asymmetric. Such configurations are called asymmetric electric dipoles, and when you place one of them in a uniform electric field it will experience not only a net torque, but also a net force. One way to create the analogous situation using magnetism is to have a wire loop in which there was different amounts of current in different parts of the loop. How might such a current loop be constructed (select all that apply)? O It could be one of the loops in a multi-loop circuit containing a different source of emf in each loop, but with each emf set to a different voltage O It is impossible to construct such a loop because it would violate the conservation of electric charge O It could be one of the loops in a multi-loop circuit containing a different source of emf in each loop, and with each emf set to the same voltage O It could be done using a single source of emf and two…arrow_forwardA magnet brought near an old-fashioned TV screen (TV sets with cathode ray tubes instead of LCD screens) severely distorts its picture by altering the path of the electrons that make its phosphors glow. (Don’t try this at home, as it will permanently magnetize and ruin the TV.) To illustrate this, calculate the radius of curvature of the path of an electron having a velocity of 6.00×107 m/s (corresponding to the accelerating voltage of about 10.0 kV used in some TVs) perpendicular to a magnetic field of strength B = 0.500 T (obtainable with permanent magnets).arrow_forward
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