Physics for Scientists and Engineers, Vol. 1
Physics for Scientists and Engineers, Vol. 1
6th Edition
ISBN: 9781429201322
Author: Paul A. Tipler, Gene Mosca
Publisher: Macmillan Higher Education
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Chapter 27, Problem 14P

(a)

To determine

The magnetic field at x=1.0m,y=3.0m .

(a)

Expert Solution
Check Mark

Answer to Problem 14P

The magnetic field is (12.72pT)k^ .

Explanation of Solution

Given:

The charge is q=12μC .

The velocity is v=30m/si^ .

Formula used:

The expression for magnetic field is given by,

  B=μ04πqv×r^r2

Calculation:

The magnetic field is calculated as,

  B=μ04πqv×r^r2=( 4π× 10 7 Tm/A 4π)( ( ( 12μC )( 10 6 C 1μC ) )( ( 30m/s i ^ )× r ^ ) ( ( 1.0m0m ) i ^ +( 3.0m2.0m ) j ^ ) 2 )=(( 36× 10 12 T m 2 )( 10 12 pT 1T ))( ( i ^ ×( 1 ( 1m ) 2 + ( 1m ) 2 i ^ + 1 ( 1m ) 2 + ( 1m ) 2 j ^ ) ) ( ( 1m ) 2 + ( 1m ) 2 ) 2 )=(12.72pT)k^

Conclusion:

Therefore, the magnetic field at origin is (12.72pT)k^ .

(b)

To determine

The magnetic field at x=2.0,y=2.0m .

(b)

Expert Solution
Check Mark

Answer to Problem 14P

The magnetic field is 0 .

Explanation of Solution

Calculation:

The magnetic field is calculated as,

  B=μ04πqv×r^r2=( 4π× 10 7 Tm/A 4π)( ( ( 12μC )( 10 6 C 1μC ) )( ( 30m/s i ^ )× r ^ ) ( ( 2.0m0m ) i ^ +( 2.0m2.0m ) j ^ ) 2 )=(( 36× 10 12 T m 2 )( 10 12 pT 1T ))( ( i ^ ×( i ^ ) ) ( 2m ) 2 )=0(i^×i^=0)

Conclusion:

Therefore, the magnetic field is 0 .

(c)

To determine

The magnetic field at x=2.0,y=3.0m .

(c)

Expert Solution
Check Mark

Answer to Problem 14P

The magnetic field is (3.22pT)k^ .

Explanation of Solution

Calculation:

The magnetic field is calculated as,

  B=μ04πqv×r^r2=( 4π× 10 7 Tm/A 4π)( ( ( 12μC )( 10 6 C 1μC ) )( ( 30m/s i ^ )× r ^ ) ( ( 2.0m0m ) i ^ +( 3.0m2.0m ) j ^ ) 2 )=(( 36× 10 12 T m 2 )( 10 12 pT 1T ))( ( i ^ ×( i ^ ) ) ( ( ( 2.0m ) 2 + ( 1.0m ) 2 ) ) 2 )=(3.22pT)k^

Conclusion:

Therefore, the magnetic field is (3.22pT)k^ .

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Chapter 27 Solutions

Physics for Scientists and Engineers, Vol. 1

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