Physics for Scientists and Engineers, Vol. 1
6th Edition
ISBN: 9781429201322
Author: Paul A. Tipler, Gene Mosca
Publisher: Macmillan Higher Education
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Question
Chapter 27, Problem 48P
(a)
To determine
A graph for the magnitude of the magnetic field as a function of the radial distance
(b)
To determine
The magnitude of the field for
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Figure is a cross-sectional view of a coaxial cable. The center conductor is surrounded by a rubber layer, which is surrounded by an outer conductor, which is surrounded by another rubber layer. In a particular application, the current in the inner conductor I 2 is 7.00 A out of the page and the current in the outer conductor I 1 is 5.00 A into the page. Assume that l = 1.20 mm. Determine the magnitude and direction (upward or downward of the page) of the magnetic field at point a. (Choose upward of the page as the positive y-direction and express the magnetic field by using the sign of the result, which must be in µT and without decimals. That means if you get a result of a 922 and the direction of the field is upward of the page, just type 922 or if you find the direction of the field as downward of the page, just tpe -922 in the answer box. Take vacuum permeability µ 0 = 4π x 10 -7 T /A 2 and π = 3.14.)
Consider a coaxial cable as shown in the figure. The cable consists of a solid inner conductor of radius r = 0.5 cm that is surrounded by a cylindrical tube
of inner radius ry = 0.8 cm and outer radius r = 1.9 cm. The conductors carry equal and opposite currents / = 4 A but the current density varies
linearly with the distance from the center for the inner conductor (j = cr) while it is distributed uniformly for the outer conductor. Determine the
magnetic field (in units of uT (microtesla)) at a distance r = 1.2 cm from the axis.
(Ho = 4x x 10-7 N/A² and x = 3.14)
Answer:
The figure below is a cross-sectional view of a coaxial cable. The center conductor is surrounded by a rubber layer, an outer conductor, and another rubber layer. In a particular application, the current
in the inner conductor is I, = 1.06 A out of the page and the current in the outer conductor is I,
= 2.96 A into the page. Assuming the distance d
= 1.00 mm, answer the following.
(a) Determine the magnitude and direction of the magnetic field at point a.
magnitude
direction
--Select---
(b) Determine the magnitude and direction of the magnetic field at point b.
magnitude
µT
direction
---Select---
Chapter 27 Solutions
Physics for Scientists and Engineers, Vol. 1
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- The figure below is a cross-sectional view of a coaxial cable. The center conductor is surrounded by a rubber layer, an outer conductor, and another rubber layer. In a particular application, the current in the inner conductor is I, = 1.16 A out of the page and the current in the outer conductor is I, = 3.18 A into the page. Assuming the distance d = 1.00 mm, answer the following. (a) Determine the magnitude and direction of the magnetic field at point a. magnitude HT direction --Select-- (b) Determine the magnitude and direction of the magnetic field at point b. magnitude HT direction ---Select---arrow_forwardAn infinite solid cylindrical conductor has radius c and carries a current I. The current is uniformly distributed over its cross section. A coaxial infinite cylindrical conducting shell with inner radius b and outer radius a carries the same magnitude but opposite direction current. If I= 120 A, c= 0.4 cm, b= 1.8 cm, a= 2 cm. What is the magnitude of the B-field at the distance of: 1) 0.3 cm from the center of the system. 2) 1 cm from the center of the system.arrow_forwardProblem 1: Two long thin parallel wires are 0.1 m apart and each wire carries a current of 12 A. The current for the wire on the left is into the page and the current for the wire on the right is out of the page. What is B at point P, 0.08 m from one wire and 0.06 m from the other wire? Hint: Point P is on the corner of the right triangle with the right angle. Answer: B = −(1.4 × 10−5 T)î − (4.8 × 10-5 T)ĵ. 0.08 m - X 0.1 m- I -0.06 marrow_forward
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