ORGANIC CHEMISTRY 1 TERM ACCESS
ORGANIC CHEMISTRY 1 TERM ACCESS
3rd Edition
ISBN: 9781119661511
Author: Klein
Publisher: WILEY
Question
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Chapter 27, Problem 50CP

(a)

Interpretation Introduction

Interpretation:

Draw mechanism of formation of poly(ethylene oxide) from ethylene oxide

Concept introduction:

Polymerization is a reaction when monomer molecules are reacted to form a polymer chain.  Nucleophilic attack to the epoxide ring opens to form an alkoxide ion.  This acts as nucleophile and attacks another molecule extending the chain forming a polymer.

To draw : To draw a mechanism for formation of poly(ethylene oxide)

(b)

Interpretation Introduction

Interpretation:

Draw mechanism of formation of poly(ethylene oxide) from ethylene oxide

Concept introduction:

Polymerization is a reaction when monomer molecules are reacted to form a polymer chain. In acidic conditions the epoxide gets protonated and then nucleophilic attack occurs in the epoxide ring opens to form an alcohol.  This acts as weak nucleophile and attacks another protonated epoxide ring to extend the carbon chain forming a polymeric chain.

To draw: To draw a mechanism for formation of poly(ethylene oxide) under acidic conditions

(c)

Interpretation Introduction

Interpretation:

Draw mechanism of formation of poly(ethylene oxide) from ethylene oxide

Concept introduction:

Polymerization is a reaction when monomer molecules are reacted to form a polymer chain. If the formed polymer is having an ether linkage in it then the monomer must have been a epoxide.

To draw : To draw the structure of monomer required for the synthesis of given polymer.

(d)

Interpretation Introduction

Interpretation:

Draw mechanism of formation of poly(ethylene oxide) from ethylene oxide

To determine: To determine whether acidic or basic conditions is used to synthesize the given polymer.

Concept introduction:

Polymerization is a reaction when monomer molecules are reacted to form a polymer chain. If the formed polymer is having an ether linkage in it then the monomer must have been a epoxide.

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