Chapter 27, Problem 48GP

To determine

The measure of photosynthetic efficiency, that is, the ratio of the energy released to the energy absorbed, if the reverse reaction releases 4.9 eV of energy per ${\text{CO}}_2$ molecule and eight photons of $670\text{ nm}$ wavelength cause the photosynthetic reaction shown below.

${\text{6CO}}_{\text{2}}+6{\text{H}}_{\text{2}}\text{O}\to {\text{C}}_{\text{6}}{\text{H}}_{\text{12}}{\text{O}}_{\text{6}}+6{\text{O}}_{\text{2}}$