EBK ELECTRICAL WIRING RESIDENTIAL
EBK ELECTRICAL WIRING RESIDENTIAL
19th Edition
ISBN: 9781337516549
Author: Simmons
Publisher: CENGAGE LEARNING - CONSIGNMENT
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Chapter 27, Problem 43R
To determine

Fill in the blanks regarding the grounding electrode conductor.

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Consider the following circuit, assuming the switch has been in the same position for a long period of time before t = 0: Vx L iL R3 R2 R₁ Is + Vo - コロ >Where Is = 100 mA,R=2202, R2 = 4702,R3 =4702,L= 1 mH. As indicated on the diagram, before t = 0, the switch is closed, after t = 0 the switch is open. 1. What are Ve and Vo before the switch shown opens (answer to within 1% accuracy)? Vx = V, Vo = V 2. What is the T of the RL circuit after the switch operates (answer to within 1% accuracy)? T= μs 3. Complete the derivation for the inductor current in (t) differential equation below by filling in the blank coefficients (answer to within 1% accuracy): diy(1) dt di (0) + iz (t)+ = 0 4. Hence or otherwise, find the time domain expression for Vo(t) (answer to within 1% accuracy): Vo(t)= exp(
確定圖5-38中的I1、I2和IB。 Vcc=-12 V;R1=33 kN;RC=1.8 kN;βDC = 150;RE=560;R2=5.6 kN  圖 5-38
Consider the following circuit: Vs R₁ Vx ww C'₁ R2 Where Vs = 3.3 cos(2000t-10) VR:=2202 R2 = 1002,L=1mH, Ci = 22 nF, C2 = 47 nF N.B. We have been using cosine as the basis for our phasors. 1. What is the impedance of each of R, Ci, L (answer to within 1%): Z RI = +j Q Zci= +j QZL= +jQ 心 2. Complete the following KCL for node Vo, assuming current flowing out of the node is positive (answer to within 1%): 0= +j )+Vo/ +j0)+Vo/(0+j 回回回 3. Hence or otherwise solve for Vo in phasor form (answer to within 1% amplitude and 5 degrees of phase): Vo = ° V 回 4. Convert this phasor to a time domain expression for Vo(t) (answer to within 1% amplitude and 5 degrees of phase): Vo(t) = cos( t+ Vo 1
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