Chemistry: Atoms First
Chemistry: Atoms First
2nd Edition
ISBN: 9780073511184
Author: Julia Burdge, Jason Overby Professor
Publisher: McGraw-Hill Education
bartleby

Concept explainers

bartleby

Videos

Question
Book Icon
Chapter 2.7, Problem 3PPA

(a)

Interpretation Introduction

Interpretation:

The number of atoms should be calculated in 7.31 moles of potassium.

Concept introduction:

Avogadro’s number is 6.022 × 10231 mole = 6.022 × 1023Avogadro’s number 

mol × 6.022 × 1023 atoms1 mol =  atoms

(b)

Interpretation Introduction

Interpretation:

The number of moles of potassium should be calculated in a sample containing 8.91 × 1025 K atoms.

Concept introduction:

Avogadro’s number is 6.022 × 10231 mole = 6.022 × 1023Avogadro’s number 

atoms × 1 mol 6.022 × 1023 atoms=mol

Blurred answer
Students have asked these similar questions
Calculate (a) the number of atoms in 1.05 × 10−6 mole of helium and (b) the number of moles of helium that contains 2.33 × 1021 atoms.
A student weighs a sample of carbon on a balance that is accurate to 0.001 g. (a) How many atoms are in 0.001 g of C?(b) The carbon is used in the following reaction: Pb₃O₄(s) +C(s)→3PbO(s) +CO(g) What mass difference in the lead(II) oxide would be caused by an error in the carbon mass of 0.001 g?
1. Provide the chemical formula (including brackets where appropriate) or systematic name for the following compounds. (a) gold(I) hypoiodite (b) HI(aq): (f) Ca(ClO4)2·4H2O: 2. What mass (in g) of chlorine atoms are there in a sample that consists of 5e+23 molecules of molecular chlorine? INSTRUCTIONS: Report your answer to 3 significant figures in scientific notation unless stated otherwise. DO NOT include the units in your answer.

Chapter 2 Solutions

Chemistry: Atoms First

Ch. 2.5 - The average atomic mass of nitrogen is 14.0067....Ch. 2.5 - Prob. 2PPCCh. 2.5 - Boron has two naturally occurring isotopes, 10B...Ch. 2.5 - The two naturally occurring isotopes of antimony,...Ch. 2.6 - Prob. 2.6.1SRCh. 2.6 - Prob. 2.6.2SRCh. 2.7 - Calcium is the most abundant metal in the human...Ch. 2.7 - Prob. 3PPACh. 2.7 - Calculate (a) the number of atoms in 1.05 106...Ch. 2.7 - Prob. 3PPCCh. 2.7 - Prob. 2.4WECh. 2.7 - Prob. 4PPACh. 2.7 - Prob. 4PPBCh. 2.7 - Prob. 4PPCCh. 2.7 - Prob. 2.5WECh. 2.7 - Prob. 5PPACh. 2.7 - Prob. 5PPBCh. 2.7 - Prob. 5PPCCh. 2.7 - Prob. 2.7.1SRCh. 2.7 - Prob. 2.7.2SRCh. 2.7 - Prob. 2.7.3SRCh. 2.7 - Prob. 2.7.4SRCh. 2 - Define the terms atom and element.Ch. 2 - Use a familiar macroscopic example as an analogy...Ch. 2 - Prob. 2.3QPCh. 2 - Prob. 2.4QPCh. 2 - Prob. 2.5QPCh. 2 - Prob. 2.6QPCh. 2 - Describe the experimental basis for believing that...Ch. 2 - Prob. 2.8QPCh. 2 - Prob. 2.9QPCh. 2 - Prob. 2.10QPCh. 2 - Prob. 2.11QPCh. 2 - Prob. 2.12QPCh. 2 - Prob. 2.13QPCh. 2 - Prob. 2.14QPCh. 2 - Prob. 2.15QPCh. 2 - Prob. 2.16QPCh. 2 - Prob. 2.17QPCh. 2 - Prob. 2.18QPCh. 2 - Prob. 2.19QPCh. 2 - Determine the mass number of (a) a beryllium atom...Ch. 2 - Prob. 2.21QPCh. 2 - The following radioactive isotopes are used in...Ch. 2 - Prob. 2.23QPCh. 2 - Prob. 2.24QPCh. 2 - Prob. 2.25QPCh. 2 - Prob. 2.26QPCh. 2 - Prob. 2.27QPCh. 2 - Prob. 2.28QPCh. 2 - Prob. 2.29QPCh. 2 - Prob. 2.30QPCh. 2 - What is the mass (in amu) of a carbon-12 atom? Why...Ch. 2 - Prob. 2.32QPCh. 2 - What information would you need to calculate the...Ch. 2 - Prob. 2.34QPCh. 2 - Prob. 2.35QPCh. 2 - Prob. 2.36QPCh. 2 - Prob. 2.37QPCh. 2 - The element rubidium has two naturally occurring...Ch. 2 - Prob. 2.39QPCh. 2 - Prob. 2.40QPCh. 2 - Prob. 2.41QPCh. 2 - Give two examples of each of the following: (a)...Ch. 2 - Prob. 2.43QPCh. 2 - Prob. 2.44QPCh. 2 - Describe the changes in properties (from metals to...Ch. 2 - Consult the WebElements Periodic Table of the...Ch. 2 - Group the following elements in pairs that you...Ch. 2 - Prob. 2.48QPCh. 2 - Prob. 2.49QPCh. 2 - Prob. 2.50QPCh. 2 - Prob. 2.51QPCh. 2 - Prob. 2.52QPCh. 2 - Prob. 2.53QPCh. 2 - Prob. 2.54QPCh. 2 - Prob. 2.55QPCh. 2 - Prob. 2.56QPCh. 2 - Prob. 2.57QPCh. 2 - Prob. 2.58QPCh. 2 - Prob. 2.59QPCh. 2 - Prob. 2.60QPCh. 2 - Prob. 2.61QPCh. 2 - Prob. 2.62QPCh. 2 - Prob. 2.63QPCh. 2 - Prob. 2.64QPCh. 2 - The element francium (Fr) was the last element of...Ch. 2 - Prob. 2.66QPCh. 2 - Prob. 2.67QPCh. 2 - Prob. 2.68QPCh. 2 - Prob. 2.69QPCh. 2 - Prob. 2.70QPCh. 2 - Discuss the significance of assigning an atomic...Ch. 2 - Prob. 2.72QPCh. 2 - Prob. 2.73QPCh. 2 - Prob. 2.74QPCh. 2 - Prob. 2.75QPCh. 2 - Prob. 2.76QPCh. 2 - Identify each of the following elements: (a) a...Ch. 2 - Prob. 2.78QPCh. 2 - Prob. 2.79QPCh. 2 - Prob. 2.80QPCh. 2 - Prob. 2.81QPCh. 2 - Prob. 2.82QPCh. 2 - Prob. 2.83QPCh. 2 - Prob. 2.84QP
Knowledge Booster
Background pattern image
Chemistry
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.
Similar questions
SEE MORE QUESTIONS
Recommended textbooks for you
Text book image
Chemistry for Engineering Students
Chemistry
ISBN:9781337398909
Author:Lawrence S. Brown, Tom Holme
Publisher:Cengage Learning
Text book image
Chemistry: The Molecular Science
Chemistry
ISBN:9781285199047
Author:John W. Moore, Conrad L. Stanitski
Publisher:Cengage Learning
Text book image
Chemistry & Chemical Reactivity
Chemistry
ISBN:9781337399074
Author:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Publisher:Cengage Learning
Text book image
Introductory Chemistry: A Foundation
Chemistry
ISBN:9781337399425
Author:Steven S. Zumdahl, Donald J. DeCoste
Publisher:Cengage Learning
Text book image
Chemistry: Principles and Practice
Chemistry
ISBN:9780534420123
Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Publisher:Cengage Learning
Text book image
Chemistry & Chemical Reactivity
Chemistry
ISBN:9781133949640
Author:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Publisher:Cengage Learning
Step by Step Stoichiometry Practice Problems | How to Pass ChemistryMole Conversions Made Easy: How to Convert Between Grams and Moles; Author: Ketzbook;https://www.youtube.com/watch?v=b2raanVWU6c;License: Standard YouTube License, CC-BY