Concept explainers
Interpretation: The formation of F from E by a two step reaction sequence consisting of a
Concept introduction: In the sigmatropic rearrangement, the rearrangement of pi bond and the breaking of sigma bond take place. This results in the generation of new sigma bond in the product. In this type of rearrangement, the number of pi bonds remains constant in the reactant as well as in the product.
Curved arrows aid in determining the movement and flow of electrons in the reaction. The electrons that take part in the
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- A student adds NBS to a solution of 1-methylcyclohexene and irradiates the mixture with a sunlamp until all the NBS has reacted. After a careful distillation, the product mixture contains two major products of formula C7H11Br. (a)Rank these three intermediates from most stable to least stable.arrow_forwardShow the detailed mechanism of this in 3D structure, and predict the major regioisomer and the major stereoisomer with a stepwise explanation. show the final major product in Newman projection.arrow_forwardNonearrow_forward
- For each reaction, decide whether substitution or elimination (or both) is possible, andpredict the products you expect. Label the major products. chlorocyclohexane + NaOCH3 in CH3OHarrow_forwardTrans-1-bromo-2-methylcyclohexane will yield a non-Zaitsev elimination product (3-methylcyclohexene) upon reaction with KOH. Show this reaction by drawing the chair conformations of the reactant and product. Include the curved arrows and explain why the product is not a non-Zaitsev product.arrow_forwardA novel heterocyclic compound, M, contains nitrogen and sulfur atoms and exhibits interesting photochemical properties. When exposed to ultraviolet (UV) light at a specific wavelength, M undergoes a photoreaction resulting in two products: N and O. Product N is formed through a [2+2] cycloaddition involving the nitrogen atom in M, while product O results from a homolytic cleavage of a sulfur-sulfur bond in M. Given these reaction pathways, what is the most probable structure of M, and what are the likely structures of N and O? A. M is a thiazole derivative; N is a dimerized product through the nitrogen atoms, and O is a compound with two sulfur-centered radicals. B. M is a diazine derivative; N is a tetra-atomic cyclic compound, and O is a compound with two separate thiol groups. C. M is a thiadiazole derivative; N is a four-membered ring involving the nitrogen atom, and O results in two sulfur-centered radicals. D. M is a dithiolane derivative; N is a dimer involving the nitrogen…arrow_forward
- The deuterated ethanol shown can be converted to an alkyl halide via a mesylate intermediate. Complete the mechanism, draw the final product (with nonbonding electrons) and select the correct absolute stereochemistry of the starting material and the final product.arrow_forward4) Draw the complete electron-pushing arrow mechanism for the following reductions. Explain, using resonance contributors, the regiochemistry that results in each case. ỌMe Na, MeOH ? NH3 CHO Na, MeOH ? NH3arrow_forwardWhen buta-1,3-diene (CH2 = CH – CH = CH2) is treated with HBr, two constitutional isomers are formed, CH3CHBrCH = CH2 and BrCH2CH = CHCH3. Draw a stepwise mechanism that accounts for the formation of both products.arrow_forward
- Trans-1-bromo-2-methylcyclohexane will yield a non-Zaitsev elimination product (3-methylcyclohexene) upon reaction with KOH. Show this reaction by drawing the chair conformations of the reactant and product. Include the curved arrows and explain why the product is not a non-Zaitsev product.arrow_forwardIn the presence of light or heat, diazomethane (CH,N2) creates a carbene, which then adds to an alkene to make a cyclopropane. In the boxes below. draw the mechanism arrows for the reaction. H INEN: INE N:arrow_forward6. Draw the products(s) for the following reaction. Include stereochemistry for every product. H2SO4 KI H-B HBr H → Br Harrow_forward
- Organic Chemistry: A Guided InquiryChemistryISBN:9780618974122Author:Andrei StraumanisPublisher:Cengage Learning