
Concept explainers
(a)
Interpretation: The product formed when the given compound in Problem 27.6 undergoes photochemical electrocyclic ring opening or ring closure is to be predicted. The given process is to be labeled as conrotatory or disrotatory. The stereochemistry around tetrahedral stereogenic centers and double bonds is to be indicated.
Concept introduction: Electrocyclic reactions involve the conversion of
Curved arrows aid in determining the movement and flow of electrons in the reaction. The electrons that take part in the

Answer to Problem 27.8P
The product formed in the given photochemical electrocyclic ring closure reaction is
Explanation of Solution
The thermal electrocyclic ring closure reaction is shown below.
Figure 1
Electrocyclic reactions involve the conversion of
Under photochemical condition, conrotatory process takes place in the given reaction. The orientation of substituents and stereochemistry around tetrahedral stereogenic centers and double bonds in the given reaction are shown below.
Figure 2
The conrotatory process involves the rotation of two orbitals in the same direction. The reaction in above figure implies that orbitals move in the same direction in the reactant molecule and the formation of trans product occurs. One methyl group is present above the plane and one methyl group is present below the plane in the product. Therefore, the product formed in the given photochemical electrocyclic ring closure reaction is
The product formed in the given photochemical electrocyclic ring closure reaction is
(b)
Interpretation: The product formed when the given compound in Problem 27.6 undergoes photochemical electrocyclic ring opening or ring closure is to be predicted. The given process is to be labeled as conrotatory or disrotatory. The stereochemistry around tetrahedral stereogenic centers and double bonds is to be indicated.
Concept introduction: Electrocyclic reactions involve the conversion of
Curved arrows aid in determining the movement and flow of electrons in the reaction. The electrons that take part in the chemical reactions are shown by the curved arrows.

Answer to Problem 27.8P
The product formed in the given photochemical electrocyclic ring opening reaction is
Explanation of Solution
The thermal electrocyclic ring opening reaction is shown below.
Figure 3
Electrocyclic reactions involve the conversion of
Under photochemical condition, disrotatory process takes place in the given reaction. The movement of substituents and stereochemistry around tetrahedral stereogenic centers and double bonds in the given reaction are shown below.
Figure 4
The disrotatory process involves the rotation of two orbitals in the opposite direction. The reaction in above figure implies that orbitals move in the opposite direction in the reactant molecule and the formation of trans product occurs. One methyl group is present above the plane and one methyl group is present below the plane in the product shows the stereochemistry. Therefore, the product formed in the given photochemical electrocyclic ring opening reaction is
The product formed in the given photochemical electrocyclic ring opening reaction is
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Chapter 27 Solutions
Package: Loose Leaf for Organic Chemistry with Biological Topics with Connect Access Card
- Please label this COZY spectraarrow_forwardPlease label this HNMRarrow_forwardConsider the following gas chromatographs of Compound A, Compound B, and a mixture of Compounds A and B. Inject A B mixture Area= 9 Area = 5 Area = 3 Area Inject . མི། Inject J2 What is the percentage of Compound B in the the mixture?arrow_forward
- Rank these according to stability. CH3 H3C CH3 1 CH3 H3C 1 most stable, 3 least stable O 1 most stable, 2 least stable 2 most stable, 1 least stable O2 most stable, 3 least stable O3 most stable, 2 least stable O3 most stable, 1 least stable CH3 2 CH3 CH3 H₂C CH3 3 CH3 CHarrow_forwardConsider this IR and NMR: INFRARED SPECTRUM TRANSMITTANCE 0.8- 0.6 0.4 0.2 3000 10 9 8 00 HSP-00-541 7 CO 6 2000 Wavenumber (cm-1) сл 5 ppm 4 M Which compound gave rise to these spectra? N 1000 1 0arrow_forwardConsider this reaction (molecular weights are under each compound): HC=CH + 2 HCI --> C2H4Cl 2 MW = 26 36.5 99 If 4.4 g of HC=CH are reacted with 110 mL of a 2.3 M HCI solution, and 6.0 g of product are actually produced, what is the percent yield?arrow_forward
- What is the name of the major product of this reaction? OH CH3 H₂SO4, heat 1-methylcyclohexene O2-methyl-1-cyclohexene O 3-mthylcyclohexene 1-methyl-2-cyclohexenearrow_forwardWe added a brown solution of Br2 to one of our products, and the brown color disappeared. This indicated that our product wasarrow_forwardRank the following according to reactivity toward nitration: a) benzene b) bromobenzene c) nitrobenzene d) phenol Od) greatest, c) least Od) greatest, b) least Od) greatest, a) least a) greatest, b) least a) greatest, c) least Oa) greatest, d) least Ob) greatest, a) least O b) greatest, c) least Ob) greatest, d) least O c) greatest, a) least O c) greatest, b) least O c) greatest, d) leastarrow_forward
- O-Nitrophenol was distilled over with the steam in our experiment while the other isomer did not. This is due to: O intramolecular hydrogen bonding in the ortho isomer O intermolecular hydrogen bonding in the the ortho isomer O the ortho isomer has a lower density O the ortho isomer has a lower molecular weightarrow_forwardK 44% Problem 68 of 15 Submit Curved arrows are used to illustrate the flow of electrons. Using the provided starting and product structures, draw the curved electron-pushing arrows for the following reaction or mechanistic step(s). Be sure to account for all bond-breaking and bond-making steps. :6: :: :CI: CI CI: :0:0 Select to Add Arrows Select to Add Arrows H H Cl CI: CI CI: Select to Add Arrows Select to Add Arrows H :CI: Alarrow_forwardI I H :0: Submit Curved arrows are used to illustrate the flow of electrons. Using the provided starting and product structures, draw the curved electron-pushing arrows for the following reaction or mechanistic step(s). Be sure to account for all bond-breaking and bond-making steps. 0:0 :0: CI ΑΙ :CI: :CI: :0: CI Select to Add Arrows Select to Add Arrows cl. :0: Cl © ハ CI:: CI H CO Select to Add Arrows Select to Add Arrows 10: AI ::arrow_forward
