Chapter 27, Problem 27.20P

Interpretation Introduction

Interpretation:

The amount of phosphorous in the given sample has to be calculated.

Concept introduction:

Molarity can be defined as the moles of solute to the volume of the solution (in litres). The molarity of a solution can be given by the formula,

$\text{Molarity(M)=}\frac{\text{Moles}\text{of}\text{solute(in}\text{mol)}}{\text{Volume}\text{of}\text{solution(in}\text{L)}}$

$\text{Molar}\text{mass}\text{=}\frac{\text{Mass}}{\text{Mole}}$

Interpretation Introduction

Interpretation:

The amount of phosphorous in the $100mL$ sample has to be calculated.

Concept introduction:

Molarity can be defined as the moles of solute to the volume of the solution (in litres). The molarity of a solution can be given by the formula,

$\text{Molarity(M)=}\frac{\text{Moles}\text{of}\text{solute(in}\text{mol)}}{\text{Volume}\text{of}\text{solution(in}\text{L)}}$

$\text{Molar}\text{mass}\text{=}\frac{\text{Mass}}{\text{Mole}}$