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Draw short segments of the
(a)
Interpretation:
The short segment of polymer obtained from the given monomer has to be drawn and also have to indicate whether it is a chain growth or step growth polymer.
Answer to Problem 25P
The short segment of given monomer is shown below and the monomer undergoes chain growth polymerization.
Explanation of Solution
Given the monomer is
The short segment of polymer obtained from this monomer is given below.
The polymer formed is a Chain growth polymer because monomer addition occurs at the end of the chain.
(b)
Interpretation:
The short segment of polymer obtained from the given monomer has to be drawn and also have to indicate whether it is a chain growth or step growth polymer.
Answer to Problem 25P
The short segment of given monomer is shown below and the monomer undergoes chain growth polymerization.
Explanation of Solution
Given the monomer is
The short segment of polymer obtained from this monomer is given below.
The polymer formed is a Chain growth polymer because monomer addition occurs at the end of the chain.
(c)
Interpretation:
The short segment of polymer obtained from the given monomer has to be drawn and also have to indicate whether it is a chain growth or step growth polymer.
Answer to Problem 25P
The short segment of given monomer is shown below and the monomer undergoes step growth polymerization.
Explanation of Solution
Given the monomer is
The short segment of polymer obtained from this monomer is given below.
The polymer formed is a Step growth polymer because monomer addition occurs not at the end of the chain and these polymers are formed by combining monomers by removing small molecules of water or alcohol.
(d)
Interpretation:
The short segment of polymer obtained from the given monomer has to be drawn and also have to indicate whether it is a chain growth or step growth polymer.
Answer to Problem 25P
The short segment of given monomer is shown below and the monomer undergoes step growth polymerization.
Explanation of Solution
Given the monomer is
The short segment of polymer obtained from this monomer is given below.
The polymer formed is a step growth polymer because monomer addition occurs not at the end of the chain and these polymers are formed by combining monomers by removing small molecules of water or alcohol.
(e)
Interpretation:
The short segment of polymer obtained from the given monomer has to be drawn and also have to indicate whether it is a chain growth or step growth polymer.
Answer to Problem 25P
The short segment of given monomer is shown below and the monomer undergoes step growth polymerization.
Explanation of Solution
Polymers are formed from linking small units called monomers and they are classified into Chain growth polymers and Step growth polymers.
Given the monomer is
The short segment of polymer obtained from this monomer is given below.
The polymer formed is a Step growth polymer because monomer addition occurs not at the end of the chain and these polymers are formed by combining monomers by removing small molecules of water or alcohol.
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Chapter 27 Solutions
Organic Chemistry
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- You may wish to address the following issues in your response if they are pertinent to the reaction(s) you propose to employ:1) Chemoselectivity (why this functional group and not another?) 2) Regioselectivity (why here and not there?) 3) Stereoselectivity (why this stereoisomer?) 4) Changes in oxidation state. Please make it in detail and draw it out too in what step what happens. Thank you for helping me!arrow_forward1) Chemoselectivity (why this functional group and not another?) 2) Regioselectivity (why here and not there?) 3) Stereoselectivity (why this stereoisomer?) 4) Changes in oxidation state. Everything in detail and draw out and write it.arrow_forwardCalculating the pH at equivalence of a titration 3/5 Izabella A chemist titrates 120.0 mL of a 0.7191M dimethylamine ((CH3)2NH) solution with 0.5501 M HBr solution at 25 °C. Calculate the pH at equivalence. The pk of dimethylamine is 3.27. Round your answer to 2 decimal places. Note for advanced students: you may assume the total volume of the solution equals the initial volume plus the volume of HBr solution added. pH = ☐ ✓ 18 Ar Boarrow_forward
- Alcohols can be synthesized using an acid-catalyzed hydration of an alkene. An alkene is combined with aqueous acid (e.. sulfuric acid in water). The reaction mechanism typically involves a carbocation intermediate. > 3rd attempt 3343 10 8 Draw arrows to show the reaction between the alkene and hydronium ion. that 2nd attempt Feedback 1st attempt تعمال Ju See Periodic Table See Hint F D Ju See Periodic Table See Hintarrow_forwardDraw the simplified curved arrow mechanism for the reaction of acetone and CHgLi to give the major product. 4th attempt Π Draw the simplified curved arrow mechanism T 3rd attempt Feedback Ju See Periodic Table See Hint H -H H -I H F See Periodic Table See Hintarrow_forwardSelect the correct reagent to accomplish the first step of this reaction. Then draw a mechanism on the Grignard reagent using curved arrow notation to show how it is converted to the final product. 4th attempt Part 1 (0.5 point) Select the correct reagent to accomplish the first step of this reaction. Choose one: OA Mg in ethanol (EtOH) OB. 2 Li in THF O C. Li in THF D. Mg in THF O E Mg in H2O Part 2 (0.5 point) Br Part 1 Bri Mg CH B CH, 1 Draw intermediate here, but no arrows. © TE See Periodic Table See Hint See Hint ין Harrow_forward
- Select the product for the following reaction. HO HO PCC OH ○ OH O HO ○ HO HO HOarrow_forward5:45 Х Select the final product for the following reaction sequence. O O 1. Mg. ether 2.D.Oarrow_forwardBased on the chart Two similarities between the molecule with alpha glycosidic linkages. Two similarities between the molecules with beta glycosidtic linkages. Two differences between the alpha and beta glycosidic linkages.arrow_forward
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