Concept explainers
The common thing between the Earth’s crust and conveyor belt
Answer to Problem 14TE
Like conveyor belts in a factory moves boxes the Earth’s crust gets a free ride with the
Explanation of Solution
The Earth’s crust is very thin as compared to other three layers in its core. And it is only about
The temperature of the crust varies as the distance from the top of its layer, as we move down the crust, the temperature varies near exponentially and may go about 1600 degrees.
The other portion of the Earth’s core known as the mantle moves due to the convection currents and the mantle of the core is responsible for the movement of the crust, as when it moves it pushes the crust to move along with it. This process can be compared with the conveyor belt used in the factories to move the work from one place to another place inside the factory.
Conclusion:
Therefore, like conveyor belts in a factory moves boxes the Earth’s crust gets a free ride with the convection currents and move many Earth’s plates from one location to the other.
Chapter 27 Solutions
Conceptual Physical Science Explorations
Additional Science Textbook Solutions
Anatomy & Physiology (6th Edition)
Human Biology: Concepts and Current Issues (8th Edition)
Campbell Biology (11th Edition)
College Physics: A Strategic Approach (3rd Edition)
Campbell Essential Biology (7th Edition)
Biology: Life on Earth (11th Edition)
- Car P moves to the west with constant speed v0 along a straight road. Car Q starts from rest at instant 1, and moves to the west with increasing speed. At instant 5, car Q has speed w0 relative to the road (w0 < v0). Instants 1-5 are separated by equal time intervals. At instant 3, cars P and Q are adjacent to one another (i.e., they have the same position). In the reference frame o f the road, at instant 3 i s the speed o f car Q greater than, less than, or equal to the speed of car P? Explain.arrow_forwardCar P moves to the west with constant speed v0 along a straight road. Car Q starts from rest at instant 1, and moves to the west with increasing speed. At instant 5, car Q has speed w0 relative to the road (w0 < v0). Instants 1-5 are separated by equal time intervals.arrow_forwardCar P moves to the west with constant speed v0 along a straight road. Car Q starts from rest at instant 1, and moves to the west with increasing speed. At instant 5, car Q has speed w0 relative to the road (w0 < v0). Instants 1-5 are separated by equal time intervals. Sketch and label a vector diagram illustrating the Galilean transformation of velocities that relates velocity of car P relative to the road, velocity of car Q relative to road, and velocity of car Q relative to car P at instant 3. In the frame of car P, at instant 3 is car Q moving to the west, moving to the east, or at rest? Explain.arrow_forward
- Just 5 and 6 don't mind 7arrow_forwardIn an electron gun, electrons are accelerated through a region with an electric field of magnitude 1.5 × 104 N/C for a distance of 2.5 cm. If the electrons start from rest, how fast are they moving after traversing the gun?arrow_forwardPlease solve and answer this problem correctly please. Thank you!!arrow_forward
- Please solve and answer this problem correctly please. Thank you!!arrow_forwarda) Use the node-voltage method to find v1, v2, and v3 in the circuit in Fig. P4.14. b) How much power does the 40 V voltage source deliver to the circuit? Figure P4.14 302 202 w w + + + 40 V V1 80 Ω 02 ΣΑΩ 28 A V3 + w w 102 202arrow_forwardPlease solve and answer this problem correctly please. Thank you!!arrow_forward
- You're on an interplanetary mission, in an orbit around the Sun. Suppose you make a maneuver that brings your perihelion in closer to the Sun but leaves your aphelion unchanged. Then you must have Question 2 options: sped up at perihelion sped up at aphelion slowed down at perihelion slowed down at aphelionarrow_forwardThe force of the quadriceps (Fq) and force of the patellar tendon (Fp) is identical (i.e., 1000 N each). In the figure below angle in blue is Θ and the in green is half Θ (i.e., Θ/2). A) Calculate the patellar reaction force (i.e., R resultant vector is the sum of the horizontal component of the quadriceps and patellar tendon force) at the following joint angles: you need to provide a diagram showing the vector and its components for each part. a1) Θ = 160 degrees, a2) Θ = 90 degrees. NOTE: USE ONLY TRIGNOMETRIC FUNCTIONS (SIN/TAN/COS, NO LAW OF COSINES, NO COMPLICATED ALGEBRAIC EQUATIONS OR ANYTHING ELSE, ETC. Question A has 2 parts!arrow_forwardThe force of the quadriceps (Fq) and force of the patellar tendon (Fp) is identical (i.e., 1000 N each). In the figure below angle in blue is Θ and the in green is half Θ (i.e., Θ/2). A) Calculate the patellar reaction force (i.e., R resultant vector is the sum of the horizontal component of the quadriceps and patellar tendon force) at the following joint angles: you need to provide a diagram showing the vector and its components for each part. a1) Θ = 160 degrees, a2) Θ = 90 degrees. NOTE: USE DO NOT USE LAW OF COSINES, NO COMPLICATED ALGEBRAIC EQUATIONS OR ANYTHING ELSE, ETC. Question A has 2 parts!arrow_forward
- College PhysicsPhysicsISBN:9781305952300Author:Raymond A. Serway, Chris VuillePublisher:Cengage LearningUniversity Physics (14th Edition)PhysicsISBN:9780133969290Author:Hugh D. Young, Roger A. FreedmanPublisher:PEARSONIntroduction To Quantum MechanicsPhysicsISBN:9781107189638Author:Griffiths, David J., Schroeter, Darrell F.Publisher:Cambridge University Press
- Physics for Scientists and EngineersPhysicsISBN:9781337553278Author:Raymond A. Serway, John W. JewettPublisher:Cengage LearningLecture- Tutorials for Introductory AstronomyPhysicsISBN:9780321820464Author:Edward E. Prather, Tim P. Slater, Jeff P. Adams, Gina BrissendenPublisher:Addison-WesleyCollege Physics: A Strategic Approach (4th Editio...PhysicsISBN:9780134609034Author:Randall D. Knight (Professor Emeritus), Brian Jones, Stuart FieldPublisher:PEARSON